我想将文件复制到新文件名。有时源文件可能是使用
创建的符号(文件)链接mklink C:\MyPath\ThisIsASymbolicLink.xml C:\MyPath\ThisIsTheOriginal.xml
我正在使用此代码:
string from = @"C:\MyPath\ThisIsASymbolicLink.xml";
string to = @"C:\MyPath\WantCopyOfOriginalFileHere.xml";
File.Copy(from, to, true);
但是,我收到IOException
系统无法解析文件的名称。
from
文件实际上是一个符号链接。
如何对源文件可能是真实文件或文件的符号链接的情况进行编码?
答案 0 :(得分:12)
扩展此blog post,我创建了一个扩展方法,它接受可以引用原始链接或符号链接的DirectoryInfo或FileInfo,并返回一个字符串,指示原始文件的完全限定路径名。 / p>
应用代码
应用程序代码修改如下:
// Works whether or not file is a symbolic link
string from =
new FileInfo(@"C:\MyPath\ThisIsASymbolicLink.xml").GetSymbolicLinkTarget();
扩展程序代码
private const int FILE_SHARE_READ = 1;
private const int FILE_SHARE_WRITE = 2;
private const int CREATION_DISPOSITION_OPEN_EXISTING = 3;
private const int FILE_FLAG_BACKUP_SEMANTICS = 0x02000000;
// http://msdn.microsoft.com/en-us/library/aa364962%28VS.85%29.aspx
[DllImport("kernel32.dll", EntryPoint = "GetFinalPathNameByHandleW", CharSet = CharSet.Unicode, SetLastError = true)]
public static extern int GetFinalPathNameByHandle(IntPtr handle, [In, Out] StringBuilder path, int bufLen, int flags);
// http://msdn.microsoft.com/en-us/library/aa363858(VS.85).aspx
[DllImport("kernel32.dll", EntryPoint = "CreateFileW", CharSet = CharSet.Unicode, SetLastError = true)]
public static extern SafeFileHandle CreateFile(string lpFileName, int dwDesiredAccess, int dwShareMode,
IntPtr SecurityAttributes, int dwCreationDisposition, int dwFlagsAndAttributes, IntPtr hTemplateFile);
public static string GetSymbolicLinkTarget(this FileSystemInfo symlink)
{
using (SafeFileHandle fileHandle = CreateFile(symlink.FullName, 0, 2, System.IntPtr.Zero, CREATION_DISPOSITION_OPEN_EXISTING, FILE_FLAG_BACKUP_SEMANTICS, System.IntPtr.Zero))
{
if (fileHandle.IsInvalid)
throw new Win32Exception(Marshal.GetLastWin32Error());
StringBuilder path = new StringBuilder(512);
int size = GetFinalPathNameByHandle(fileHandle.DangerousGetHandle(), path, path.Capacity, 0);
if (size < 0)
throw new Win32Exception(Marshal.GetLastWin32Error());
// The remarks section of GetFinalPathNameByHandle mentions the return being prefixed with "\\?\"
// More information about "\\?\" here -> http://msdn.microsoft.com/en-us/library/aa365247(v=VS.85).aspx
if (path[0] == '\\' && path[1] == '\\' && path[2] == '?' && path[3] == '\\')
return path.ToString().Substring(4);
else
return path.ToString();
}
}
单元测试
[TestClass]
public class SymlinkTest
{
[TestInitialize]
public void SetupFiles()
{
if (!File.Exists(@"C:\Temp\SymlinkUnitTest\Original.txt")) throw new Exception("Run Symlinksetup.bat as Admin to create test data.");
}
[TestMethod]
public void OrdinaryFile()
{
string file = @"C:\Temp\SymlinkUnitTest\Original.txt";
string actual = new FileInfo(file).GetSymbolicLinkTarget();
Assert.IsTrue(actual.EndsWith(@"SymlinkUnitTest\Original.txt"));
}
[TestMethod]
public void FileSymlink()
{
string file = @"C:\Temp\SymlinkUnitTest\Symlink.txt";
string actual = new FileInfo(file).GetSymbolicLinkTarget();
Assert.IsTrue(actual.EndsWith(@"SymlinkUnitTest\Original.txt"));
}
[TestMethod]
public void OrdinaryDirectory()
{
string dir = @"C:\Temp\SymlinkUnitTest";
string actual = new DirectoryInfo(dir).GetSymbolicLinkTarget();
Assert.IsTrue(actual.EndsWith(@"SymlinkUnitTest"));
}
[TestMethod]
public void DirectorySymlink()
{
string dir = @"C:\Temp\SymlinkUnitTest";
string actual = new DirectoryInfo(dir).GetSymbolicLinkTarget();
Assert.IsTrue(actual.EndsWith(@"SymlinkUnitTest"));
}
}
用于创建单元测试数据的批处理文件
必须以管理员身份运行... mklink的要求。
@Echo Off
Echo Must be run as Administrator (due to mklink)
mkdir C:\Temp
mkdir C:\Temp\SymlinkUnitTest
c:
cd C:\Temp\SymlinkUnitTest
echo Original File>Original.txt
mklink Symlink.txt Original.txt
mklink /D C:\Temp\SymlinkUnitTest\SymDir C:\Temp\SymlinkUnitTest