Question

我可能没有在标题中解释得这么好，因为我真的不知道如何在标题的长度上解释它所以我为此道歉。无论如何这是我目前的代码：

// Gets the product that is used to get the factors
cout << "Enter a number that you want to be factored" << endl;
cin >> y;

system("cls");

// Gets the sum from the user that the two factors need to add up to
cout << "Input the sum that is needed" << endl;
cin >> neededSum;

secondary = y;
system("cls");

// Lists the factors that add up to the specified sum
cout << "The numbers that add up to " << neededSum << " are:" << endl;
for (int i = 0; i < 100; i++)
{
    x++;
    increment++;
    y = secondary / x;
    product = x * y;
    if (product == secondary)
    {
        sum = x + y;
        if (sum == neededSum)
        {
            cout << x << " and " << y << endl;
        }
    }
}

基本上，产品会列出该产品的所有因素。然后，它将所有因素加在一起，直到找到加起来为指定总和的因子。

但是，如果指定的总和为负值，例如'-11'，那么它将不起作用，因为'28'（一个例子）的因子是4和7而不是-4和-7。我需要想办法解决这个问题，以便知道什么时候需要-4和-7而不是正反转。

提前感谢您的帮助。

Answer 1

假装x和y为负数：

if (product == secondary)
{
    sum = x + y;
    if (sum == neededSum)
    {
        cout << x << " and " << y << endl;
    }
    else if (-sum == neededSum)
    {
        cout << -x << " and " << -y << endl;
    }
}

如何用一笔总和获得积极产品的负面因素

1 个答案: