Informix SQL - 列出所有字段&表

时间:2009-09-04 18:17:57

标签: sql field informix isql

Informix iSQL有一个显示所有表的命令“info tables;” 查看字段及其各自数据类型的语法是“info columns for table;

是否有类似的命令显示所有表和所有字段的table.field?

4 个答案:

答案 0 :(得分:30)

使用首选的JOIN表示法:

SELECT TRIM(t.tabname) || '.' || TRIM(c.colname) AS table_dot_column
  FROM "informix".systables  AS t
  JOIN "informix".syscolumns AS c ON t.tabid = c.tabid
 WHERE t.tabtype = 'T'
   AND t.tabid >= 100
 ORDER BY t.tabname, c.colno;

或老式的join-in-where-clause符号:

SELECT TRIM(t.tabname) || '.' || TRIM(c.colname) AS table_dot_column
  FROM "informix".systables AS t, "informix".syscolumns AS c
 WHERE t.tabid = c.tabid
   AND t.tabtype = 'T'
   AND t.tabid >= 100
 ORDER BY t.tabname, c.colno;

假设您使用的是最新版本的IDS,您可以按选择列表中未引用的列进行排序。如果您收到投诉,请将订购列添加到选择列表中。

联合标准是显而易见的; tabtype ='T'仅列出表格,而不列出systables中列出的视图,同义词和其他此类项目; tabid> = 100仅列出在数据库中显式创建的表,而不是系统目录。

这不包括类型信息 - 如果你想要,你必须做更多的工作。您将找到一个文件$INFORMIXDIR/etc/xpg4_is.sql,其中包含旧版XPG4(X / Open标准)信息模式的粗略近似值(因此文件名)。在那里,有一些函数等可以将syscolumns.coltypesyscolumns.collength中的类型信息解码为可识别的字符串。但是,我强烈怀疑它不处理DISTINCT类型,也不处理其他用户定义的类型。我很高兴被证明是错误的,但是......如果你将该文件的相关部分添加到数据库中,那么你也应该能够获得类型信息。

另请注意,ISQL和DB-Access中的所有INFO命令都在前端进行模拟,而不是在IDS服务器中执行。基本上,程序接受请求并将其转换为更复杂的SQL语句。请参阅文件sqlinfo.ec中的代码,该文件是SQLCMD的一部分(可从IIUG Software Archive获得),以了解我的SQLCMD程序如何处理INFO语句。 (注意:SQLCMD的INFO输出格式与ISQL和DB-Access的INFO输出不同。)

答案 1 :(得分:1)

使用syscolumns表。 IBM Informix Guide to SQL

中描述了此类信息

我已经完成了简单的Python实用程序,它显示了InformixOraclePostgreSQL的架构信息。如果必须比较数据库,它们很有用。

答案 2 :(得分:1)

正如Jonathan Leffer的回答所提到的那样,对列类型和列详细信息的完整处理变得复杂,如SYSCOLUMNS文档中所示。但是,如果您正在查看不使用更复杂类型的数据库,那么对其脚本的添加将显示基本类型以及是否允许NULL:

SELECT TRIM(t.tabname) || '.' || TRIM(c.colname) AS table_dot_column,
CASE 
  WHEN MOD(coltype,256)=0 THEN 'CHAR' 
  WHEN MOD(coltype,256)=1 THEN 'SMALLINT' 
  WHEN MOD(coltype,256)=2 THEN 'INTEGER' 
  WHEN MOD(coltype,256)=3 THEN 'FLOAT' 
  WHEN MOD(coltype,256)=4 THEN 'SMALLFLOAT' 
  WHEN MOD(coltype,256)=5 THEN 'DECIMAL' 
  WHEN MOD(coltype,256)=6 THEN 'SERIAL' 
  WHEN MOD(coltype,256)=7 THEN 'DATE' 
  WHEN MOD(coltype,256)=8 THEN 'MONEY' 
  WHEN MOD(coltype,256)=9 THEN 'NULL' 
  WHEN MOD(coltype,256)=10 THEN 'DATETIME' 
  WHEN MOD(coltype,256)=11 THEN 'BYTE' 
  WHEN MOD(coltype,256)=12 THEN 'TEXT' 
  WHEN MOD(coltype,256)=13 THEN 'VARCHAR' 
  WHEN MOD(coltype,256)=14 THEN 'INTERVAL' 
  WHEN MOD(coltype,256)=15 THEN 'NCHAR' 
  WHEN MOD(coltype,256)=16 THEN 'NVARCHAR' 
  WHEN MOD(coltype,256)=17 THEN 'INT8' 
  WHEN MOD(coltype,256)=18 THEN 'SERIAL8' 
  WHEN MOD(coltype,256)=19 THEN 'SET' 
  WHEN MOD(coltype,256)=20 THEN 'MULTISET' 
  WHEN MOD(coltype,256)=21 THEN 'LIST' 
  WHEN MOD(coltype,256)=22 THEN 'ROW (unnamed)' 
  WHEN MOD(coltype,256)=23 THEN 'COLLECTION' 
  WHEN MOD(coltype,256)=40 THEN 'LVARCHAR fixed-length opaque types' 
  WHEN MOD(coltype,256)=41 THEN 'BLOB, BOOLEAN, CLOB variable-length opaque types' 
  WHEN MOD(coltype,256)=43 THEN 'LVARCHAR (client-side only)' 
  WHEN MOD(coltype,256)=45 THEN 'BOOLEAN' 
  WHEN MOD(coltype,256)=52 THEN 'BIGINT' 
  WHEN MOD(coltype,256)=53 THEN 'BIGSERIAL' 
  WHEN MOD(coltype,256)=2061 THEN 'IDSSECURITYLABEL'
  WHEN MOD(coltype,256)=4118 THEN 'ROW (named)' 
  ELSE TO_CHAR(coltype)
END AS Type,
BITAND(coltype,256)=256 AS NotNull
  FROM "informix".systables  AS t
  JOIN "informix".syscolumns AS c ON t.tabid = c.tabid
 WHERE t.tabtype = 'T'
   AND t.tabid >= 100
 ORDER BY t.tabname, c.colno;

答案 3 :(得分:0)

我做了一个基本的检查主键列。 还添加了列顺序,数据类型长度。 这提供了生成ETL的基本信息

SELECT TRIM(t.tabname)  AS TableName
,c.colno                AS ColumnOrder
,TRIM(c.colname)        AS ColumnName
,CASE 
  WHEN MOD(coltype,256)=0 THEN 'CHAR' 
  WHEN MOD(coltype,256)=1 THEN 'SMALLINT' 
  WHEN MOD(coltype,256)=2 THEN 'INTEGER' 
  WHEN MOD(coltype,256)=3 THEN 'FLOAT' 
  WHEN MOD(coltype,256)=4 THEN 'SMALLFLOAT' 
  WHEN MOD(coltype,256)=5 THEN 'DECIMAL' 
  WHEN MOD(coltype,256)=6 THEN 'SERIAL' 
  WHEN MOD(coltype,256)=7 THEN 'DATE' 
  WHEN MOD(coltype,256)=8 THEN 'MONEY' 
  WHEN MOD(coltype,256)=9 THEN 'NULL' 
  WHEN MOD(coltype,256)=10 THEN 'DATETIME' 
  WHEN MOD(coltype,256)=11 THEN 'BYTE' 
  WHEN MOD(coltype,256)=12 THEN 'TEXT' 
  WHEN MOD(coltype,256)=13 THEN 'VARCHAR' 
  WHEN MOD(coltype,256)=14 THEN 'INTERVAL' 
  WHEN MOD(coltype,256)=15 THEN 'NCHAR' 
  WHEN MOD(coltype,256)=16 THEN 'NVARCHAR' 
  WHEN MOD(coltype,256)=17 THEN 'INT8' 
  WHEN MOD(coltype,256)=18 THEN 'SERIAL8' 
  WHEN MOD(coltype,256)=19 THEN 'SET' 
  WHEN MOD(coltype,256)=20 THEN 'MULTISET' 
  WHEN MOD(coltype,256)=21 THEN 'LIST' 
  WHEN MOD(coltype,256)=22 THEN 'ROW (unnamed)' 
  WHEN MOD(coltype,256)=23 THEN 'COLLECTION' 
  WHEN MOD(coltype,256)=40 THEN 'LVARCHAR fixed-length opaque types' 
  WHEN MOD(coltype,256)=41 THEN 'BLOB, BOOLEAN, CLOB variable-length opaque types' 
  WHEN MOD(coltype,256)=43 THEN 'LVARCHAR (client-side only)' 
  WHEN MOD(coltype,256)=45 THEN 'BOOLEAN' 
  WHEN MOD(coltype,256)=52 THEN 'BIGINT' 
  WHEN MOD(coltype,256)=53 THEN 'BIGSERIAL' 
  WHEN MOD(coltype,256)=2061 THEN 'IDSSECURITYLABEL'
  WHEN MOD(coltype,256)=4118 THEN 'ROW (named)' 
  ELSE TO_CHAR(coltype)
END                     AS Datatype
,c.collength            AS DatatypeLength
,CASE WHEN NVL(
(
    SELECT MAX(i.idxname)
    FROM "informix".sysconstraints cn inner join "informix".sysindexes i 
        on cn.idxname = i.idxname
        and cn.tabid = i.tabid
    where cn.constrtype = 'P'
        AND cn.tabid = t.tabid
        AND
        (c.colno = i.part1
        OR c.colno = i.part2
        OR c.colno = i.part3
        OR c.colno = i.part4
        OR c.colno = i.part5
        OR c.colno = i.part6
        OR c.colno = i.part7
        OR c.colno = i.part8
        OR c.colno = i.part9
        OR c.colno = i.part10
        OR c.colno = i.part11
        OR c.colno = i.part12
        OR c.colno = i.part13
        OR c.colno = i.part14
        OR c.colno = i.part15
        OR c.colno = i.part16
        )
),'') = '' THEN 0 ELSE 1 END    AS PK
FROM "informix".systables  AS t  JOIN "informix".syscolumns AS c 
    ON t.tabid = c.tabid
WHERE t.tabtype = 'T'
    AND t.tabid >= 100
    --AND t.tabname = 'resource'
ORDER BY t.tabname, c.colno;