Question

我有一个字符串数组，我想用它作为从plist创建的另一个字典数组的过滤器。例如，如果我有一个类似于词典的词典：

Key:      Value:
car1      audi
car2      bmw
car3      bmw
car4      audi
car5      jaguar

我的字符串数组是“audi，jaguar”。我如何编码它以便我可以创建一个返回“car1，car4，car5”的新数组？希望这是有道理的。或者更好的是，我如何走下这本字典并根据一个值过滤它，然后创建一个新的字典数组来使用。

代码：

-(void)plotStationAnnotations {

desiredDepartments = [[NSMutableArray alloc] init];

BOOL tvfrSwitchStatus = [[NSUserDefaults standardUserDefaults] boolForKey:@"tvfrSwitchStatus"];
BOOL hfdSwitchStatus =  [[NSUserDefaults standardUserDefaults] boolForKey:@"hfdSwitchStatus"];

if (tvfrSwitchStatus) {
    NSString *tvfr = @"TVF&R";
    [desiredDepartments addObject:tvfr];
}
if (hfdSwitchStatus) {
    NSString *hfd = @"HFD";
    [desiredDepartments addObject:hfd];
}

NSLog(@"Array 1 = %@", desiredDepartments);

NSString *path = [[NSBundle mainBundle] pathForResource:@"stationAnnotations" ofType:@"plist"];
NSMutableArray *anns = [[NSMutableArray alloc] initWithContentsOfFile:path];

NSMutableArray *newDictionaryArray = [NSMutableArray array];
for (NSDictionary *dictionary in anns) {
    for (NSString *string in desiredDepartments) {
        if ([dictionary allKeysForObject:string]) {
            [newDictionaryArray addObject:dictionary];
            break;
        }
    }
}

NSLog(@"Array = %@", keyMutableArray);

for (int i = 0; i < [keyMutableArray count]; i++) {

    float realLatitude = [[[keyMutableArray objectAtIndex:i] objectForKey:@"latitude"] floatValue];
    float realLongitude = [[[keyMutableArray objectAtIndex:i] objectForKey:@"longitude"] floatValue];

    StationAnnotations *myAnnotation = [[StationAnnotations alloc] init];
    CLLocationCoordinate2D theCoordinate;
    theCoordinate.latitude = realLatitude;
    theCoordinate.longitude = realLongitude;
    myAnnotation.coordinate = theCoordinate;
    myAnnotation.title = [[keyMutableArray objectAtIndex:i] objectForKey:@"station"];
    myAnnotation.subtitle = [[keyMutableArray objectAtIndex:i] objectForKey:@"department"];
    [mapView addAnnotation:myAnnotation];
}
}

Answer 1

可能类似

NSArray *array1;
if([array1 containsObject : someValue])

可以提供帮助。 someValue可以是您要检查它们是否存在于array1中的值。

Answer 2

您可以执行以下操作来按键过滤：

NSArray *keysToLookFor = [NSArray arrayWithObjects:@"car1", @"car4", @"car5", nil];
NSArray *foundObjects = [dictionary objectsForKeys:keysToLookFor notFoundMarker:nil];

或类似的东西按值过滤：

NSString *valueToLookFor = @"Audi";
NSArray *keyArray = [dictionary allKeysForObject:valueToLookFor];

// To filter by multiple values
NSArray *valuesToFilterBy = [NSArray arrayWithObjects:@"Bmw", @"Audi", nil];
NSMutableArray *keyMutableArray = [NSMutableArray array];
for (NSString *string in valuesToFilterBy) {
    [keyMutableArray addObjectsFromArray:[dictionary allKeysForObject:string]];
}

更新了数组中词典的答案：

NSArray *dictionaryArray; // The array of dictionaries that you have
NSMutableArray *newDictionaryArray = [NSMutableArray array];
NSArray *valuesToFilterBy = [NSArray arrayWithObjects:@"Bmw", @"Audi", nil];
for (NSDictionary *dictionary in dictionaryArray) {
    for (NSString *string in valuesToFilterBy) {
        if ([dictionary allKeysForObject:string]) {
            [newDictionaryArray addObject:dictionary];
            break;
        }
    }
}

iOS使用数组过滤数组

2 个答案: