Question

我正在尝试使用XslCompiledTransform，并将输出用作XPathDocument。

任何想法？

Answer 1

先生。琼斯的回答对我很有帮助，但我发现最后一行没有用。我最终这样做了：

XslCompiledTransform xsl = new XslCompiledTransform();
xsl.Load(filePath);
StringWriter stringWriter = new StringWriter();
XmlWriter xmlWriter = XmlTextWriter.Create(stringWriter);
xsl.Transform(xPathDoc, xmlWriter);
String newXml = stringWriter.ToString();
StringReader stringReader = new StringReader(newXml);
xPathDoc = new XPathDocument(stringReader);

（这里，xPathDoc是一个已经从XmlReader初始化的XPathDocument。）

Answer 2

根据XmlTextWriter将转化发送至StringWriter。然后通过从XPathDocument恢复XML字符串来实例化StringWriter。

var sw = new StringWriter();
var xtw = new XmlTextWriter(sw);

myTransform.Transform(myXml, xtw);

var xpd = new XPathDocument(sw.ToString());

它不是最有效的内存机制，但足以满足大多数需求。类似的方法是使用MemoryStream而不是StringWriter，但相比之下它有点混乱。

Answer 3

稍微好一点的David M. Anderson的答案如下：它没有遭受潜在的资源泄漏;否则它是一样的。

private static XPathDocument TransformToXPathDocument(string styleSheetPath,
                                                      IXPathNavigable xPathDoc)
{
    var xsl = new XslCompiledTransform();
    xsl.Load(styleSheetPath);
    using(var stringWriter = new StringWriter())
    {
        using(XmlWriter xmlWriter = XmlWriter.Create(stringWriter))
        {
            xsl.Transform(xPathDoc, xmlWriter);
        }
        using(var reader = new StringReader(stringWriter.ToString()))
        {
            return new XPathDocument(reader);
        }
    }
}

XslCompiledTransform输出为XPathDocument

3 个答案: