如何在面板中发送标签作为DynamicContextKey?

时间:2012-12-09 22:58:21

标签: asp.net ajax jquery asp.net-ajax

    <tr class="content" id="row1" onmouseover="$find('pce_1').showPopup();" onmouseout="$find('pce_1').hidePopup();">
<td class="style28">
    &nbsp;</td>
        <td class="style30">
            <asp:Panel ID="panel_player_1" runat="server">
            </asp:Panel>
        </td>
        <td class="style21" align="right">
            <asp:Panel ID="panel_table_1" runat="server" Width="50px">
            <ajaxToolkit:PopupControlExtender ID="PopupControlExtender1" runat="server" PopupControlID="Panel222" TargetControlID="panel_table_1"
               DynamicContextKey='<%# Eval("panel_table_1") %>' BehaviorID="pce_1"
               DynamicControlID="Panel222"
               DynamicServiceMethod="GetDynamicContent" Position="Bottom" OffsetX="-485" />
            </asp:Panel>
        </td>

</tr>

我有十个像这样的块......我在panel_table_1和panel_player_1中通过代码隐藏放置了一个标签...我想在panel_table_1中发送text o label作为DynamicContextKey.how我应该这样做吗?

0 个答案:

没有答案