Question

我遇到了这个SQL语句的问题：

$sql="SELECT b.FrameNumber, b.BikeCode, IF(b.ProductID = 0, p.FrameNumber) 
   AS FrameNumber 
 FROM BikeStock b LEFT JOIN Purchase p ON b.FrameNumber = p.FrameNumber 
 WHERE b.bikecode = '$bikecode'";

我希望SQL语句以这种方式工作：

Select FrameNumber & BikeCode from BikeStock 
THEN IF ProductID(BikeStock) is equal to 0 
     then it will grab the framenumber from the purchase table where bikecode is equal to $bikecode

任何想法？

提前致谢。

Answer 1

您必须在if()

中添加其他部分

SELECT b.FrameNumber, b.BikeCode,
       IF(b.ProductID = 0, p.FrameNumber, NULL) AS FrameNumber
FROM BikeStock b
LEFT JOIN Purchase p ON b.FrameNumber = p.FrameNumber
WHERE b.bikecode = '$bikecode'

Answer 2

MySQL IF语句具有以下语法：IF(condition, expression if true, expression if false)。

据我所知，你实际上是在寻找一个WHERE子句（请记住，你可以在WHERE中有多个条件 - 使用布尔运算符来组合它们）：

SELECT b.FrameNumber, b.BikeCode, p.FrameNumber
FROM BikeStock b
LEFT JOIN Purchase p ON b.FrameNumber = p.FrameNumber
WHERE b.bikecode = :bikecode AND b.ProductID = 0

Answer 3

您忘记了该IF语句的else部分：

$sql = "SELECT b.FrameNumber, b.BikeCode, IF(b.ProductID = 0, p.FrameNumber, NULL /* ELSE HERE */) AS FrameNumber 
        FROM BikeStock b 
        LEFT JOIN Purchase p 
            ON b.FrameNumber = p.FrameNumber 
        WHERE b.bikecode = '$bikecode'";

Answer 4

试试这个

    $sql="SELECT b.FrameNumber, b.BikeCode, p.FrameNumber (
          CASE WHEN b.ProductID = 0 THEN p.FrameNumber ELSE NULL END AS Framenumber)  
          FROM BikeStock b 
          LEFT JOIN Purchase p ON b.FrameNumber = p.FrameNumber 
          WHERE b.bikecode = '$bikecode'";

MySQL-IF语句错误

4 个答案: