Question

好的，我正在尝试将参数传递给我创建的库的构造函数，以扩展CI_Form_validation类。无论如何，这是我从模型中传递的内容：

$this->load->library('MY_Form_validation', array('config' => '', 'post' => $this->input->post()));

然后是MY_Form_validation库：

private $post;

    public function __construct($params) {
        parent::__construct($params['config']);
        $this->post = $params['post'];
    }

但它说我没有传递任何内容。以下是错误消息：

Message: Missing argument 1 for MY_Form_validation::__construct(), called in H:\WD SmartWare.swstor\HALEY-HP\Source\DStable\stable\core\Loader.php on line 1099 and defined
Message: Undefined variable: params

EDIT 根据要求，全班：

class MY_Form_validation extends CI_Form_validation {
    private $post;

    public function __construct($params) {
        parent::__construct($params['config']);
        $this->post = $params['post'];
    }
}

Answer 1

您需要传递一个空数组而不是空字符串作为构造函数的第一个参数，该参数将发送给父级：

$this->load->library('MY_Form_validation', array('config' => array(), 'post' => $this->input->post()));

CI表单验证库实际上初始化了config参数，这是system/libraries/Form_validation.php的构造函数：

public function __construct($rules = array())

CodeIgniter params没有传递到库？

1 个答案: