我正在使用this application,我遇到的唯一问题是,当用户登录时,他们可以查看公开信息,即使他们没有创建。
有没有办法让它与其他用户的帖子一起显示?
应用程序的重点是用户可以登录和创建帖子,默认情况下这些是私有的,这意味着只有他们可以看到它,如果用户公开发布,我希望它是非登录的或登录用户可以查看,但这正是我所拥有的,但所有公开帖子都显示在其他用户的帖子中。
这是应用程序控制器:
class ApplicationController < ActionController::Base
protect_from_forgery
rescue_from ActiveRecord::RecordNotFound, :with => :handle_not_found
def handle_not_found
respond_to do |type|
type.html { redirect_to root_path, :notice => 'Record not found'}
type.all { render :nothing => true, :status => 404 }
end
true
end
end
这是帖子控制器:
class PostsController < ApplicationController
before_filter :authenticate_user!, :except => [:index, :show]
# GET /posts
# GET /posts.json
def index
@posts = current_user ? Post.public_or_owned_by(current_user) : nil
render :template => current_user ? 'posts/index_logged_in' : 'posts/index_not_logged_in'
end
# GET /posts/1
# GET /posts/1.json
def show
@post = current_user ? Post.public_or_owned_by(current_user).find_by_url_id!(params[:id]) : Post.public.find_by_url_id!(params[:id])
respond_to do |format|
format.html # show.html.erb
format.json { render json: @post }
end
end
# GET /posts/new
# GET /posts/new.json
def new
@post = Post.new
respond_to do |format|
format.html # new.html.erb
format.json { render json: @post }
end
end
# GET /posts/1/edit
def edit
@post = current_user.posts.find_by_url_id(params[:id])
end
# POST /posts
# POST /posts.json
def create
@post = current_user.posts.build(params[:post])
respond_to do |format|
if @post.save
format.html { redirect_to @post, notice: 'Post was successfully created.' }
format.json { render json: @post, status: :created, location: @post }
else
format.html { render action: "new" }
format.json { render json: @post.errors, status: :unprocessable_entity }
end
end
end
# PUT /posts/1
# PUT /posts/1.json
def update
@post = current_user.posts.find_by_url_id(params[:id])
respond_to do |format|
if @post.update_attributes(params[:post])
format.html { redirect_to @post, notice: 'Post was successfully updated.' }
format.json { head :no_content }
else
format.html { render action: "edit" }
format.json { render json: @post.errors, status: :unprocessable_entity }
end
end
end
# DELETE /posts/1
# DELETE /posts/1.json
def destroy
@post = current_user.posts.find_by_url_id(params[:id])
@post.destroy
respond_to do |format|
format.html { redirect_to posts_url }
format.json { head :no_content }
end
end
end
这是帖子模型:
class Post < ActiveRecord::Base
belongs_to :user
before_create :generate_url_id
attr_accessible :title, :body, :is_public
scope :public, where(:is_public => true)
def self.public_or_owned_by(user)
t = Post.arel_table
Post.where(t[:user_id].eq(user.id).or(t[:is_public].matches(true)))
end
def generate_url_id
self.url_id = SecureRandom.urlsafe_base64
end
def to_param
self.url_id
end
end
这是用户模型:
class User < ActiveRecord::Base
# Include default devise modules. Others available are:
# :token_authenticatable, :confirmable,
# :lockable, :timeoutable and :omniauthable
devise :database_authenticatable, :registerable,
:recoverable, :rememberable, :trackable, :validatable
# Setup accessible (or protected) attributes for your model
attr_accessible :email, :password, :password_confirmation, :remember_me
# attr_accessible :title, :body
has_many :posts
end
答案 0 :(得分:0)
仍然不确定我理解你想要什么,但我会使用两种不同的路线:
resources :posts # see all public posts from everyone
resources :users do
resources :posts # nested route for a user to only see his own posts
end
所以在您的控制器中,您将拥有:
def index
if params[:user_id]
if current_user && current_user.id == params[:user_id].to_i
# see all posts for a user, even non-public ones
@posts = Post.where( user_id: params[:user_id] )
else
# see public posts from a user
@posts = Post.public.where( user_id: params[:user_id] )
end
else
# see all public posts
@posts = Post.public
end
end
这不是你能做的最好的,但它是功能性的。更好的方法是使用某些授权机制,如CanCan。