Question

我在512 * 512原始图像上进行DCT / IDCT，

但我的程序可能会输出一张只有PSNR 17.54db的图像，

我已多次检查我的配方，有人可以帮我解决这个问题吗？

#include <stdio.h>
#include <math.h>
#define N 512

double COS[8][8], C[8];
unsigned char pic[N][N];
double dct[N][N], idct[N][N];

void init() {
  int i, j;
  for (i = 0; i < 8; i++) {
    for (j = 0; j < 8; j++)
      COS[i][j] = cos((2 * i + 1) * j * acos(-1) / 16.0);
    if (i) C[i] = 1;
    else C[i] = 1 / sqrt(2);
  }
}

void DCT() {
  freopen("dct.raw", "wb", stdout);
  int r, c, i, j, x, y;
  for (r = 0; r < 64; r++)
    for (c = 0; c < 64; c++)
      for (i = 0; i < 8; i++)
        for (j = 0; j < 8; j++) {
          double sum = 0;
          for (x = 0; x < 8; x++)
            for (y = 0; y < 8; y++)
              sum += (pic[r * 8 + x][c * 8 + y] - 128) * COS[x][i] * COS[y][j];
          sum *= C[i] * C[j] * 0.25;
          if (sum < 0) sum = 0;
          if (sum > 255) sum = 255;
          dct[r * 8 + i][c * 8 + j] = sum;
      }
  for (r = 0; r < N; r++)
    for (c = 0; c < N; c++)
      putchar(dct[r][c]);
}

void IDCT() {
  freopen("idct.raw", "wb", stdout);
  int r, c, i, j, x, y;
  for (r = 0; r < 64; r++)
    for (c = 0; c < 64; c++)
      for (i = 0; i < 8; i++)
        for (j = 0; j < 8; j++) {
          double sum = 0;
          for (x = 0; x < 8; x++)
            for (y = 0; y < 8; y++)
              sum += C[x] * C[y] * dct[r * 8 + x][c * 8 + y] * COS[i][x] * COS[j][y];
          sum *= 0.25;
          sum += 128;
          if (sum < 0) sum = 0;
          if (sum > 255) sum = 255;
          idct[r * 8 + i][c * 8 + j] = sum;
      }
  for (r = 0; r < N; r++)
    for (c = 0; c < N; c++)
      putchar(idct[r][c]);
}

int main() {
  freopen("Lena.raw", "rb", stdin);
  int r, c;
  for (r = 0; r < N; r++)
    for (c = 0; c < N; c++)
      scanf("%c", &pic[r][c]);
  init();
  DCT();
  IDCT();
  return 0;
}

Answer 1

问题是DCT代码中的这些行

      if (sum < 0) sum = 0;
      if (sum > 255) sum = 255;

您将DCT值钳位为0 <=值<= 255

他们可能不是。例如，将存在负系数。尝试删除这些行，看看是否有帮助

在我的DCT / IDCT代码中找不到错误

1 个答案: