Question

我希望有人能帮助我做到这一点。我正在运行这个sql命令将一些数据放入我的Excel工作表中，这让我疯狂。

我有3张桌子需要合并

sup =每小时供应数据
audit =记录事情到达时（sup＆amp;米）
米=米上的每日数据

在事情开始失控之前，我实际上已经到了这里。我可以得到sup和aud合并，我可以得到米和aud合并。虽然我无法选择有关供应的顶部仪表。

SELECT      sup.*, aud.*, meters.*
FROM        SuppliesData AS sup
INNER JOIN  Audit As aud
ON          sup.AuditID = aud.AuditID 
    WHERE   sup.DeviceID = '14365' 
INNER JOIN  (
    SELECT TOP 1
    From    MeterAudit AS meters
    INNER JOIN aud
    ON aud.AuditID=meters.AuditID 
    WHERE meters.DeviceID='14365' AND sup.AuditDate > meters.AuditDate// << I am so confused now...
    ORDER by    aud.AuditDate ASC
    )
ORDER by    aud.AuditDate ASC

我为尝试弄清楚我的烂摊子而道歉。

基本上， sup和meter都没有AuditDate字段。我需要将AuditDate字段应用于耗材，然后为每个耗材抓取最近的仪表。它是嵌套（你可能已经看到了）当前正在让我...所有我看到的错误我得到的是'围绕FROM的不正确的语法'

非常感谢任何帮助，

对于参考，以下代码完全正常

SELECT  sup.*, aud.*
// -  simply changing SuppliesData to MeterAudit changes everything perfectly.
FROM    SuppliesData AS sup 
INNER JOIN  Audit As aud
ON  sup.AuditID = aud.AuditID 
WHERE DeviceID = '14365' 
ORDER by    aud.AuditDate ASC

JC

Answer 1

请改为尝试：

SELECT      sup.*, aud.*, meters.*
FROM        SuppliesData AS sup
INNER JOIN  Audit As aud ON  sup.AuditID  = aud.AuditID 
                         AND sup.DeviceID = aud.DeviceID 
INNER JOIN  
(
    SELECT AuditID, MAX(AuditDate) MaxDate
    From    MeterAudit
    GROUP BY AuditID
) Maxa ON aud.AuditID = maxa.AuditID AND sup.AuditDate = maxa.AuditDate
WHERE   sup.DeviceID = '14365'

SQL嵌套内部在大约日期加入

1 个答案: