Question

select name, birthday 
from user 
where uid in (SELECT uid2 FROM friend WHERE uid1 = me()) 
    and birthday != null;

结果

{
  "error": {
    "message": "(#602) NULL is not a member of the user table.", 
    "type": "OAuthException", 
    "code": 602
  }
}

我可以以某种方式过滤掉空值吗？

Answer 1

这应该取出它在一年中获得普通字母时所用的所有空值

SELECT name, birthday, email, uid FROM user WHERE uid in (SELECT uid2 FROM friend WHERE uid1 = me()) AND (strpos(lower(birthday),"a") >=0 OR strpos(lower(birthday),"e") >=0 OR strpos(lower(birthday),"u") >=0) ORDER BY birthday_date

Answer 2

无需使用str *函数...只需使用'where field '排除空值，或'where not field '排除非空值。对于这个特例：

选择姓名，生日来自用户生日那天和uid in（SELECT uid2 FROM friend WHERE uid1 = me（））

如何用fql过滤null？

2 个答案: