无法在shell脚本中显示选项参数

Question

这是我的shell脚本 -

while getopts ":m" opt; do
  case "$opt" in
    m)
      echo "-m was triggered! $OPTARG was entered" >&2
      ;;
    j)
       echo "-j was triggered! $4 was entered" >&2
       ;;
    k)
       echo "-k was triggered! $6 was entered" >&2
       ;;
   \?)
      echo "Invalid option: -$OPTARG" >&2
      ;;
  esac
done
shift $(($OPTIND - 1))

当我运行shell脚本时 -

./test.sh -m hello

我以这种方式获得输出 -

-m was triggered!  was entered

我哪里错了？请耐心等待我，因为我对shell脚本完全不熟悉。

Answer 1

它应该是m：而不是：m

while getopts "m:" opt; do