Question

有什么方法可以对此进行排序吗？或者我只是需要拆分并使用循环进行比较？输入

123.4.245.23
104.244.253.29
1.198.3.93
32.183.93.40
104.30.244.2
104.244.4.1

输出

1.198.3.93
32.183.93.40
104.30.244.2
104.244.4.1
104.244.253.29
123.4.245.23

到目前为止，我使用HashMap来存储我的数据。我想按升序对IP地址进行排序。貌似TreeMap是更好的选择吗？

Answer 1

<强> TLDR

您可以直接跳转到有效的比较方法（参见下面的编辑部分）或继续阅读。

为了对IP进行排序，首先需要了解一下它们。有两种类型的IP; 32 Bit和128 Bit。

32位 Source

32 bit IP在0和255之间分为4组数字。这些组通过.
如上所示，单个组是8位数据。这就是组中的数字限制在0和255之间的原因。
要正确格式化32 bit IP，它应为int.int.int.int。即使int是0，它也必须显示在IP地址中。这与可能省略128 bit IP的{{1}}不同。例如0与::5:相同。

128位 Source

0:0:5:0:0:0:0:0被分为8组128 bit IP和0之间的数字（相当于FFFF）。与65535群组不同，这些群组是分开的，请购买32 bit IPs。
如上所示，单个组是16位数据。这就是组中的数字限制在:和0之间的原因。
要正确格式化FFFF，您必须遵循几条规则。可以从组中省略128 bit IP，如果其余组都是0，则也可以省略组。这些组必须用0分隔。如果您要省略组，那么:之后的最后一组必须跟0。:。这些规则为我们留下了格式int:int:int:int:int:int:int:int。省略0和组的示例为58f:::fff:2:。这与58f:0:0:fff:2:0:0:0相同。

<强>分拣

一旦将IP分类到各自的组中，就可以对它们进行排序。要对IP进行排序，您需要使用称为加权的方法。这是因为简单地将不同的组添加或相乘可能不起作用。例如，取这两个IP; 192.5.48.198和198.48.5.192。如果将组的值相加或相加，则得到相同的答案。所以没有办法使用加法和乘法来准确地比较它们。如果你使用加权，你会得到类似的东西。

32位加权

Value of IP = (Group one value * 256^4) + (Group two value * 256^3) +
              (Group three value * 256^2) + (Group four value * 256)

128位加权

Value of IP = (Group one value * 65536^8) + (Group two value * 65536^7) +
              (Group three value * 65536^6) + (Group four value * 65536^5) +
              (Group five value * 65536^4) + (Group six value * 65536^3) +
              (Group seven value * 65536^2) + (Group eight value * 65536)

Java中的代码

只要合理正确地格式化IP，此代码就会将这两种IP分开，然后对它们进行排序。

import java.util.*;
import java.math.*; //For BigInteger
import java.util.regex.*;
import java.lang.*;

public class IPSort
{
    String[] tests = {":8:","::::5:6::8","::::5:6::7","::::5:6::8","123..245.23","1...","..1.","123...23",".1..","123..245.23", "123..245.23", "104.244.253.29", "1.198.3.93", "32.183.93.40", "32.183.93.40", "104.30.244.2", "104.244.4.1","0.0.0.1",":a:","::5:3:4:5:6:78","1::2:3","1::2:3:4","1::5:256.2.3.4","1:1:3000.30.30.30","ae80::217:f2ff:254:7:237:98"};
    ArrayList<String> bit32 = new ArrayList<String>();
    ArrayList<String> bit128 = new ArrayList<String>();
    ArrayList<String> cleanBit32 = new ArrayList<String>();
    ArrayList<String> cleanBit128 = new ArrayList<String>();

    boolean myMatcher32Bit(String s)
    {
        Pattern patter32Bit = Pattern.compile("^(?=(?:[^.]*\\.){3}[^.]*$)(?=(?:[^:]*:){0}[^:]*$)(?=(?:[^a-zA-Z]*[^a-zA-Z])*$)");
        Matcher matcher32Bit = patter32Bit.matcher(s);
        return matcher32Bit.find();
    }

    boolean myMatcher128Bit(String s)
    {
        Pattern patter128Bit = Pattern.compile("^(?=(?:[^.]*\\.){0}[^.]*$)(?=(?:[^:]*:){1,7}[^:]*$)");
        Matcher matcher128Bit = patter128Bit.matcher(s);
        return matcher128Bit.find();
    }

    public void sortIntoRespectiveIPTypes()
    {
        for(String s: tests)
        {
            if(myMatcher32Bit(s))
            {
                bit32.add(s);
            }
            else if(myMatcher128Bit(s))
            {
                bit128.add(s);
            }
        }

        System.out.println("32 bit IPs");
        for(String ip: bit32)
        {
            System.out.println("  "+ip);
        }

        System.out.println("\n128 bit IPs");
        for(String ip: bit128)
        {
            System.out.println("  "+ip);
        }

        int count = 0;
        for(String ip: tests)
        {
            if(myMatcher32Bit(ip)==false && myMatcher128Bit(ip)==false)
            {
                count++;
            }
        }

        if(count != 0)
        {
            System.out.println("\nDidn't match an IP format");
            for(String ip: tests)
            {
                if(myMatcher32Bit(ip)==false && myMatcher128Bit(ip)==false)
                {
                    System.out.println("  "+ip);
                }
            }
        }

    }

    public void sort32BitIPs(ArrayList<String> bit32, ArrayList<String> newBit32)
    {
        ArrayList<BigInteger> bigInt32Bit = new ArrayList<BigInteger>();
        for(String ip:bit32)
        {
            String[] tempArray = ip.split("\\.");
            int i=0;
            for(String s:tempArray)
            {
                if(s.equals(""))
                {
                    tempArray[i]="0";
                }
                i++;
            }
            bigInt32Bit.add(convert32Bit(tempArray));
        }

        Collections.sort(bigInt32Bit);

        ArrayList<String> fixFormat = new ArrayList<String>();
        for(String ip:bit32)
        {
            String[] fixArray = ip.split("\\.");
            int i=0;
            for(String s:fixArray)
            {
                if(s.equals(""))
                {
                    fixArray[i]="0";
                }
                i++;
            }

            StringBuilder strBuilder = new StringBuilder();
            for(int i2 = 0; i2 < 4; i2++) 
            {
                if(i2<3)
                {
                    try
                    {
                        if(!fixArray[i2].equals(""))
                        {
                            strBuilder.append(fixArray[i2]+".");
                        }
                        else
                        {
                            strBuilder.append(".");
                        }
                    }
                    catch(Exception e)
                    {
                        strBuilder.append("0.");
                    }
                }
                else
                {
                    try
                    {
                        strBuilder.append(fixArray[i2]);
                    }
                    catch(Exception e)
                    {
                        strBuilder.append("0");
                    }
                }
            }
            String newString = strBuilder.toString();
            fixFormat.add(newString);
            bit32=fixFormat;
        }

        for(BigInteger finalValue:bigInt32Bit)
        {
            for(String ip:bit32)
            {
                String[] tempArray = ip.split("\\.");
                int i=0;
                for(String s:tempArray)
                {
                    if(s.equals(""))
                    {
                        tempArray[i]="0";
                    }
                    i++;
                }
                if(finalValue.equals(convert32Bit(tempArray)))
                {
                    if(!newBit32.contains(ip))
                    {
                        String str = bit32.toString();
                        String findStr = ip;
                        int lastIndex = 0;
                        int count = 0;

                        while(lastIndex != -1){

                            lastIndex = str.indexOf(findStr,lastIndex);

                            if(lastIndex != -1){
                                count++;
                                lastIndex += findStr.length();
                            }
                        }

                        for(int k = 0; k<count;k++)
                        {
                            newBit32.add(ip);
                        }
                    }
                }
            }
        }
    }

    BigInteger convert32Bit(String[] array)
    {
        int[] tempArray = new int[array.length];
        ArrayList<BigInteger> tempBigIntList = new ArrayList<BigInteger>();
        int i = 0;
        for(String s:array)
        {
            int power = 4-i;
            tempArray[i]= Integer.parseInt(s);
            String string = Integer.toString(tempArray[i]);
            BigInteger myBigInt = new BigInteger(string);
            BigInteger num2 = myBigInt.multiply(new BigInteger("256").pow(power));
            tempBigIntList.add(num2);
            i++;
        }
        BigInteger bigInt32Bit = new BigInteger("0");
        for(BigInteger bI:tempBigIntList)
        {
            bigInt32Bit = bigInt32Bit.add(bI);
        }
        return bigInt32Bit;
    }

    public void sort128BitIPs(ArrayList<String> bit128,ArrayList<String> newBit128)
    {
        ArrayList<BigInteger> bigInt128Bit = new ArrayList<BigInteger>();
        for(String ip:bit128)
        {
            String[] tempArray = ip.split(":");
            int i=0;
            for(String s:tempArray)
            {
                if(s.equals(""))
                {
                    tempArray[i]="0";
                }
                i++;
            }
            bigInt128Bit.add(convert128Bit(tempArray));
        }

        Collections.sort(bigInt128Bit);

        for(BigInteger finalValue:bigInt128Bit)
        {
            for(String ip:bit128)
            {
                String[] tempArray = ip.split(":");
                int i=0;
                for(String s:tempArray)
                {
                    if(s.equals(""))
                    {
                        tempArray[i]="0";
                    }
                    i++;
                }
                if(finalValue.equals(convert128Bit(tempArray)))
                {
                    if(!newBit128.contains(ip))
                    {
                        String str = bit128.toString();
                        String findStr = ip;
                        int lastIndex = 0;
                        int count = 0;

                        while(lastIndex != -1){

                            lastIndex = str.indexOf(findStr,lastIndex);

                            if(lastIndex != -1){
                                count++;
                                lastIndex += findStr.length();
                            }
                        }

                        for(int k = 0; k<count;k++)
                        {
                            newBit128.add(ip);
                        }
                    }
                }
            }
        }
    }

    BigInteger convert128Bit(String[] array)
    {
        int[] tempArray = new int[array.length];
        ArrayList<BigInteger> tempBigIntList = new ArrayList<BigInteger>();
        int i = 0;
        for(String s:array)
        {
            int power = 8-i;
            tempArray[i]= Integer.parseInt(s,16);
            String string = Integer.toString(tempArray[i]);
            BigInteger myBigInt = new BigInteger(string);
            BigInteger num2 = myBigInt.multiply(new BigInteger("65536").pow(power));
            tempBigIntList.add(num2);
            i++;
        }
        BigInteger bigInt128Bit = new BigInteger("0");
        for(BigInteger bI:tempBigIntList)
        {
            bigInt128Bit = bigInt128Bit.add(bI);
        }
        return bigInt128Bit;
    }

    public void printInOrder(ArrayList<String> bit32,ArrayList<String> bit128)
    {
        System.out.println("\nSorted IPs");

        System.out.println("Sorted 32 bit IPs - Ascending");
        for(String ip: bit32)
        {
            System.out.println("  "+ip);
        }

        Collections.reverse(bit32);
        System.out.println("\nSorted 32 bit IPs - Descending");
        for(String ip: bit32)
        {
            System.out.println("  "+ip);
        }

        System.out.println("\nSorted 128 bit IPs - Ascending");
        for(String ip: bit128)
        {
            System.out.println("  "+ip);
        }

        Collections.reverse(bit128);
        System.out.println("\nSorted 128 bit IPs - Descending");
        for(String ip: bit128)
        {
            System.out.println("  "+ip);
        }
    }

    public void run(ArrayList<String> bit32,ArrayList<String> bit128,ArrayList<String> newBit32,ArrayList<String> newBit128)
    {
        sortIntoRespectiveIPTypes();
        sort32BitIPs(bit32,newBit32);
        sort128BitIPs(bit128,newBit128);
        printInOrder(newBit32,newBit128);
    }

    public static void main(String[] args)
    {
        IPSort ipS = new IPSort();
        ipS.run(ipS.bit32,ipS.bit128,ipS.cleanBit32,ipS.cleanBit128);
    }
}

作为注释，可以使用this class对IP进行排序，但我的代码不使用它

此代码还将列表按升序排序，然后按降序排序。运行代码时，它将在命令控制台中打印出来

<强>输出

的修改

更有效和准确的方法是使用上面提到的InetAddress class。致200_success代码。

import java.net.InetAddress;
import java.net.Inet4Address;
import java.net.Inet6Address;
import java.net.UnknownHostException;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.Optional;
import java.util.stream.Stream;

public class IPSort {
    private static String[] TESTS = {"0:0:0:0:0:0:fff:ffff","::FFFF:222.1.41.90",":8:","::::5:6::8","::::5:6::7","::::5:6::8","123..245.23","1...","..1.","123...23",".1..","123..245.23", "123..245.23", "104.244.253.29", "1.198.3.93", "32.183.93.40", "32.183.93.40", "104.30.244.2", "104.244.4.1","0.0.0.1",":a:","::5:3:4:5:6:78","1::2:3","1::2:3:4","1::5:256.2.3.4","1:1:3000.30.30.30","ae80::217:f2ff:254:7:237:98","::2:3:4:5:6:7","2:3:4:5:6:7","::5:3:4:5:6:7:8","::5:3:4:5:6:7:8:9:0","1::8","1::2:3","1::2:3:4","1::5:256.2.3.4","1:1:3000.30.30.30","ae80::217:f2ff:254.7.237.98","1:2:3:4::5:1.2.3.4","2001:0000:1234:0000:0000:C1C0:ABCD:0876","12345::6:7:8","1::1.2.900.4","fe80::","::ffff:0:0"};

    public static class InetAddressComparator implements Comparator<InetAddress> {
        @Override
        public int compare(InetAddress a, InetAddress b) {
            byte[] aOctets = a.getAddress(),
                   bOctets = b.getAddress();
            int len = Math.max(aOctets.length, bOctets.length);
            for (int i = 0; i < len; i++) {
                byte aOctet = (i >= len - aOctets.length) ?
                    aOctets[i - (len - aOctets.length)] : 0;
                byte bOctet = (i >= len - bOctets.length) ?
                    bOctets[i - (len - bOctets.length)] : 0;
                if (aOctet != bOctet) return (0xff & aOctet) - (0xff & bOctet);
            }
            return 0;
        }
    }

    public static Optional<InetAddress> toInetAddress(String s) {
        try {
            return Optional.of(InetAddress.getByName(s));
        } catch (UnknownHostException badAddress) {
            return Optional.empty();
        }
    }

    public static void main(String[] args) throws Exception {
        System.out.println("Valid 32-bit addresses");
        Arrays.stream(TESTS)
              .map(IPSort::toInetAddress)
              .filter(Optional::isPresent)
              .map(Optional::get)
              .filter((addr) -> addr instanceof Inet4Address)
              .map(InetAddress::getHostAddress)
              .forEach(System.out::println);

        System.out.println("\nValid 128-bit addresses");
        Arrays.stream(TESTS)
              .map(IPSort::toInetAddress)
              .filter(Optional::isPresent)
              .map(Optional::get)
              .filter((addr) -> addr instanceof Inet6Address)
              .map(InetAddress::getHostAddress)
              .forEach(System.out::println);

        System.out.println("\nInvalid addresses");
        Arrays.stream(TESTS)
              .filter((s) -> !toInetAddress(s).isPresent())
              .forEach(System.out::println);

        System.out.println("\nSorted addresses");
        Arrays.stream(TESTS)
              .map(IPSort::toInetAddress)
              .filter(Optional::isPresent)
              .map(Optional::get)
              .sorted(new InetAddressComparator())
              .map(InetAddress::getHostAddress)
              .forEach(System.out::println);
    }
}

Answer 2

我建议你实现自己的比较器。请参阅此帖子：Sorting IP addresses in Java

仅为您复制粘贴：

/**
 * LGPL
 */
public class InetAddressComparator implements Comparator {
    @Override
    public int compare(InetAddress adr1, InetAddress adr2) {
        byte[] ba1 = adr1.getAddress();
        byte[] ba2 = adr2.getAddress();

        // general ordering: ipv4 before ipv6
        if(ba1.length < ba2.length) return -1;
        if(ba1.length > ba2.length) return 1;

        // we have 2 ips of the same type, so we have to compare each byte
        for(int i = 0; i < ba1.length; i++) {
            int b1 = unsignedByteToInt(ba1[i]);
            int b2 = unsignedByteToInt(ba2[i]);
            if(b1 == b2)
                continue;
            if(b1 < b2)
                return -1;
            else
                return 1;
        }
        return 0;
    }

    private int unsignedByteToInt(byte b) {
        return (int) b & 0xFF;
    }
}

Answer 3

对于ip4地址，您只是向您展示需要拆分。那么我会把它转换成一个长值，并按此排序。

long value = f3 + f2*256 + f1 * 256^2 + f0 * 256^3

其中f0 - f3是选定的值。

Answer 4

将IP中的每个片段填充到3长度，然后填充sort，例如下面：

    List<String> ipList = new ArrayList<String>();
    ipList.add("123.4.245.23");
    ipList.add("104.244.253.29");
    ipList.add("1.198.3.93");
    ipList.add("32.183.93.40");
    ipList.add("104.30.244.2");
    ipList.add("104.244.4.1");
    Collections.sort(ipList, new Comparator<String>() {
        @Override
        public int compare(String o1, String o2) {
            String[] ips1 = o1.split("\\.");
            String updatedIp1 = String.format("%3s.%3s.%3s.%3s",
                                                  ips1[0],ips1[1],ips1[2],ips1[3]);
            String[] ips2 = o2.split("\\.");
            String updatedIp2 = String.format("%3s.%3s.%3s.%3s",
                                                  ips2[0],ips2[1],ips2[2],ips2[3]);
            return updatedIp1.compareTo(updatedIp2);
        }
    });
    //print the sorted IP
    for(String ip: ipList){
        System.out.println(ip);
    }

打印：

1.198.3.93
  32.183.93.40
  104.30.244.2
  104.244.4.1
  104.244.253.29
  123.4.245.23

Answer 5

public class IpSort {  
    public static void main(String[] args) {  
        // TODO Auto-generated method stub  
        String[] arr = {"192.168.1.1",  
            "191.122.123.112",  
            "192.161.1.1",  
            "191.122.123.1",  
            "123.24.5.78",  
            "121.24.5.78",  
            "123.24.4.78",  
            "123.2.5.78",  
            "192.1.1.1",  
            "125.45.67.89",  
            "1.1.1.1",  
            "3.4.5.6",  
            "2.2.2.2",  
            "6.6.6.7",  
            "155.155.23.0"};  
        String tmp;  
        for(int i=0;i<arr.length;i++)  
        {  
                  for(int j=1;j<arr.length-i;j++)  
                  {  
                      String[] instr1 = arr[j-1].split("\\.");  
                      String[] instr2 = arr[j].split("\\.");  
                           if(Integer.parseInt(instr1[0]) > Integer.parseInt(instr2[0]))  
                           {  
                               tmp=arr[j-1];  
                               arr[j-1]=arr[j];  
                               arr[j]=tmp;  
                           }else if(Integer.parseInt(instr1[0]) == Integer.parseInt(instr2[0])  
                         && Integer.parseInt(instr1[1]) > Integer.parseInt(instr2[1]) )  
                           {  
                                tmp=arr[j-1];  
                                arr[j-1]=arr[j];  
                                arr[j]=tmp;  
                           } else if(Integer.parseInt(instr1[0]) == Integer.parseInt(instr2[0])  
                         && Integer.parseInt(instr1[1]) == Integer.parseInt(instr2[1])  
                         && Integer.parseInt(instr1[2]) > Integer.parseInt(instr2[2]) )  
                           {  
                                tmp=arr[j-1];  
                                arr[j-1]=arr[j];  
                                arr[j]=tmp;  
                           } else if(Integer.parseInt(instr1[0]) == Integer.parseInt(instr2[0])  
                         && Integer.parseInt(instr1[1]) == Integer.parseInt(instr2[1])  
                         && Integer.parseInt(instr1[2]) == Integer.parseInt(instr2[2])  
                         && Integer.parseInt(instr1[3]) > Integer.parseInt(instr2[3]) )  
                           {  
                               tmp=arr[j-1];  
                               arr[j-1]=arr[j];  
                               arr[j]=tmp;  
                           }  
                  }  

        }  
        System.out.println("final sorted list of ips :\n");  
        for(int k=0;k<arr.length;k++){  
            System.out.println(arr[k]);  
        }  
    }  
}

Answer 6

在Java8中

import java.math.BigInteger;
import java.net.InetAddress;
import java.net.UnknownHostException;
import java.util.AbstractMap;
import java.util.Arrays;
import java.util.Comparator;
import java.util.Map;

class Test {
    private static final Comparator<InetAddress> COMPARATOR = Comparator
            .comparing(InetAddress::getAddress,
                    Comparator.comparingInt((byte[] b) -> b.length)
                    .thenComparing(b -> new BigInteger(1, b)));

    public static void main(String[] args) {
        final String[] addresses = {
                "123.4.245.23",
                "104.244.253.29",
                "1.198.3.93",
                "32.183.93.40",
                "104.30.244.2",
                "104.244.4.1"
        };

        for (final String address : sort(addresses)) {
            System.out.println(address);
        }
    }

    public static String[] sort(final String[] addresses) {
        return Arrays.stream(addresses)
                .map(s -> new AbstractMap.SimpleImmutableEntry<>(toInetAddress(s), s))
                .sorted(Comparator.comparing(Map.Entry::getKey, Comparator.nullsLast(COMPARATOR)))
                .map(Map.Entry::getValue)
                .toArray(String[]::new);
    }

    private static InetAddress toInetAddress(final String address) {
        try {
            return InetAddress.getByName(address);
        } catch (final UnknownHostException | SecurityException e) {
            e.printStackTrace();
            return null;
        }
    }
}

输出：

1.198.3.93
32.183.93.40
104.30.244.2
104.244.4.1
104.244.253.29
123.4.245.23

Answer 7

这个简单的逻辑怎么样：

Ip地址： [10.1.1.2,10.22.33.11,10.12.23.12]

1）填写IP以完成12位数格式，前缀为0：喜欢 [010.001.001.002,010.022.033.011,010.012.023,012]

2）删除＆＃34;。＆＃34; s使其成为完整的数字串： [010001001002,010022033011,010012023012]

3）应用排序 [010001001002,010012023012,010022033011]

4）每3位数后保留点数： [010.001.001.002,010.012.023.012,010.022.033.011]

5）删除前缀0＆＃39; s [10.1.1.2,10.12.23.12,10.22.33.11]

6）排序！

Answer 8

public class SortIP
{

    public static String getFormattedIP(String ip)
    {
        String arg[] = new String[4];
        arg = (ip).split("\\.");

        int i=0;
        while(i<=3)
        {
            if(arg[i].length()==1)
            {
                arg[i]="00"+arg[i];
            }
            else if(arg[i].length()==2)
            {
                arg[i]="0"+arg[i];
            }

            i++;
        }

        return arg[0]+arg[1]+arg[2]+arg[3];
    }

    public static ArrayList<Integer> sortedList(Object[] obj,String order)
    {
        if(order.equalsIgnoreCase("Ascending"))
        {
            Arrays.sort(obj, new Comparator() {
                public int compare(Object o1, Object o2) {
                    return ((Map.Entry<Integer, Long>) o1).getValue()
                               .compareTo(((Map.Entry<Integer, Long>) o2).getValue());
                }
            });
        }
        else
        {
            Arrays.sort(obj, new Comparator() {
                public int compare(Object o1, Object o2) {
                    return ((Map.Entry<Integer, Long>) o2).getValue()
                               .compareTo(((Map.Entry<Integer, Long>) o1).getValue());
                }
            });
        }

        int counter=0;
        ArrayList<Integer> key = new ArrayList<Integer>();
        //int key[] = new int[ipRange.size()];

        for (Object e : obj) {
            key.add(((Map.Entry<Integer, Long>) e).getKey());
            //key[counter++]=((Map.Entry<Integer, Long>) e).getKey();

            System.out.println(((Map.Entry<Integer, Long>) e).getKey() + " : " + ((Map.Entry<Integer, Long>) e).getValue());
        }

        return key;
    }

    public static void main(String[] args) 
    {
        Map<Integer,String> ipRange= new TreeMap<Integer,String>();
        Map<Integer,Long> formatedIpRange= new TreeMap<Integer,Long>();

        ipRange.put(1, "10.1.4.100");
        ipRange.put(2, "1.10.400.10");
        ipRange.put(3, "196.0.14.15");
        ipRange.put(4, "196.70.5.1");
        ipRange.put(5, "196.70.7.3");
        ipRange.put(6, "153.70.7.0");

        for(int j=1;j<=ipRange.size();j++)
        {
            formatedIpRange.put(j, Long.parseLong(getFormattedIP(ipRange.get(j))));
        }

        Object[] a = formatedIpRange.entrySet().toArray();

        ArrayList<Integer> key = sortedList(a,"descending");

        System.out.println("ordered list ");

        for (Integer integer : key) 
        {
            System.out.println(ipRange.get(integer));
        }
    }
}

Answer 9

尝试这个

medi = Top15['% Renewable'].median()
Top15['new col'] = Top15['% Renewable'].transform(lambda value: 1 if value>=medi else 0)

如何按升序排序IP地址

9 个答案: