php imagecreatefrom结果是黑色的

时间:2012-12-06 23:42:17

标签: php gd

我一直在努力解决这个问题。我需要上传一张图片,将其裁剪为正方形,调整为300x300,然后调整为150x150,上传到我的'uploads / products / $ id /'文件夹,然后将文件路径推送到mysql数据库。

然而,我一直在输出黑色图像。这个脚本有什么问题?

$ext = explode('.', $_FILES['image1']['name']);
$extension = $ext[1];
$target_path = 'uploads/products/'.$id.'/';
$filename = 'featuredpic.'.$extension;

$featured100_full_path = $target_path.$filename;

if(!is_dir('../../../uploads/products/'.$id)){
    mkdir('../../../uploads/products/'.$id, 0777);
}

if(file_exists('../../../'.$featured100_full_path)) {
    chmod('../../../'.$featured100_full_path, 0755);
    unlink('../../../'.$featured100_full_path);
}

if(!move_uploaded_file($_FILES['image1']['tmp_name'], '../../../'.$featured100_full_path)){
    echo 'Error: Image Not Uploaded!';
}

if($extension=="jpg" || $extension=="jpeg" ){
$uploadedfile = $_FILES['image1']['tmp_name'];
$src = imagecreatefromjpeg($uploadedfile);
    }
else if($extension=="png"){
$uploadedfile = $_FILES['image1']['tmp_name'];
$src = imagecreatefrompng($uploadedfile);
} else {
$src = imagecreatefromgif($uploadedfile);}

list($width, $height) = getimagesize($filename);
$newwidth = 300;
$newheight = 300;
$featured300 = imagecreatetruecolor($newwidth, $newheight);

$newwidth1 = 150;
$newheight1 = 150;
$featuredthumb = imagecreatetruecolor($newwidth1, $newheight1);

imagecopyresampled($featured300,$src,0,0,0,0,$newwidth,$newheight,$width,$height);
imagecopyresampled($featuredthumb,$src,0,0,0,0,$newwidth1,$newheight1,$width,$height);

$filename_featured300 = 'uploads/products/'.$id.'/featured300.'.$extension;
$filename_featuredthumb = 'uploads/products/'.$id.'/featuredthumb.'.$extension;

imagejpeg($featured300, '../../../'.$filename_featured300,100);
imagejpeg($featuredthumb, '../../../'.$filename_featuredthumb,100);

imagedestroy($src);
imagedestroy($tmp);
imagedestroy($tmp1);

1 个答案:

答案 0 :(得分:0)

此功能可能是黑色图像的原因: http://php.net/manual/en/function.imagecreatetruecolor.php

我个人会逐步完成每个修改过程,确保它能够正常运行并做你期望的事情,我不得不承认这些代码很多都有风险:

$ext = explode('.', $_FILES['image1']['name']);
$extension = $ext[1];

你对文件扩展名的信任度太高了,这样更安全: http://php.net/manual/en/function.finfo-file.php

但是,我知道这是一个额外的PECL扩展 - 所以要明白为什么你可能选择了dot上的爆炸。如果没有为文件上传,目录结构等编写包装器,那么很难对代码进行反编译

提示:继续将图像移动到带有数字扩展名的临时目录,以便在转换链的每个阶段进行查看 - 它应该快速识别您的缺陷!希望这会有所帮助,对不起,我无能为力。