我有一张表:
id ip
-- -----------
1 192.168.2.1
需要获得如下结果:
id ip A B C D
-- ----------- --- --- --- ---
1 192.168.2.1 192 168 2 1
可行?
答案 0 :(得分:3)
SELECT `id`, `ip`,
SUBSTRING_INDEX( `ip` , '.', 1 ) AS a,
SUBSTRING_INDEX(SUBSTRING_INDEX( `ip` , '.', 2 ),'.',-1) AS b,
SUBSTRING_INDEX(SUBSTRING_INDEX( `ip` , '.', -2 ),'.',1) AS c,
SUBSTRING_INDEX( `ip` , '.', -1 ) AS d
FROM unicorns
示例强>
SET @ip = '192.168.1.1';
SELECT @ip,
SUBSTRING_INDEX( @ip , '.', 1 ) AS a,
SUBSTRING_INDEX(SUBSTRING_INDEX( @ip , '.', 2 ),'.',-1) AS b,
SUBSTRING_INDEX(SUBSTRING_INDEX( @ip , '.', -2 ),'.',1) AS c,
SUBSTRING_INDEX( @ip , '.', -1 ) AS d
<强>结果强>
| @IP | A | B | C | D | ----------------------------------- | 192.168.1.1 | 192 | 168 | 1 | 1 |