我创建了一个搜索框,它将从MySQL数据库中提取某些参数。如果没有参数出现,我需要将哪些代码嵌入到以下代码中,从而导致回显文本通知用户没有匹配的参数可能很好。
<?php
mysql_connect ("localhost", "root", "") or die (mysql_error());
mysql_select_db ("store_location");
$term = $_POST['term'];
$sql = mysql_query("SELECT * FROM store_location where store_name like '%$term%' or address like '%$term%' or city like '%$term%' or state like '%$term%' or zip like '%$term%' or phone like '%$term%' or fax like '%$term%' or email like '%$term%' or url like '%$term%' ");
echo '<h1>Search Results:</h1>';
while ($row = mysql_fetch_array($sql)){
echo 'Store Name: '.$row['store_name'];
echo '<br/> Address: '.$row['address'];
echo '<br/> City: '.$row['city'];
echo '<br/> State: '.$row['state'];
echo '<br/> Zip: '.$row['zip'];
echo '<br/> Phone: '.$row['phone'];
echo '<br/> Fax: '.$row['fax'];
echo '<br/> Email: <a href="mailto:'.$row['email'].'">'.$row['email'].'</a>';
echo '<br/> URL: <a href="'.$row['url'].'">'.$row['url'].'</a>';
echo '<br/><br/>';
}
?>
答案 0 :(得分:1)
答案 1 :(得分:1)
要获取表格中的记录数,您可以尝试以下代码:
<?php
$query = mysql_query("select count(*) as total from table_name");
$result = mysql_fetch_array($query);
echo $result['total'];
if( $result['total']==0)
{
echo "no records is found";
}else{
echo"numbers of records is=".$result['total'];
}
?>
答案 2 :(得分:0)
试试这个。 mysql_num_rows
if(mysql_num_rows($sql)){
while ($row = mysql_fetch_array($sql)){
echo 'Store Name: '.$row['store_name'];
echo '<br/> Address: '.$row['address'];
echo '<br/> City: '.$row['city'];
echo '<br/> State: '.$row['state'];
echo '<br/> Zip: '.$row['zip'];
echo '<br/> Phone: '.$row['phone'];
echo '<br/> Fax: '.$row['fax'];
echo '<br/> Email: <a href="mailto:'.$row['email'].'">'.$row['email'].'</a>';
echo '<br/> URL: <a href="'.$row['url'].'">'.$row['url'].'</a>';
echo '<br/><br/>';
}
}else{
echo 'No results found';
}
答案 3 :(得分:0)
<?
$term = mysql_real_escape_string($_POST['term']); // sanitize input!
if ($sql = mysql_query('...')) { // mysql_* functions are deprecated, consider mysqli instead
$count = mysql_num_rows($sql);
echo "<h1>$count Result" . ($count == 1 ? '' : 's') . ' Found' . ($count ? ':' : '') . '</h1>';
while ($row = mysql_fetch_array($sql)) {
echo '...';
}
}