如何将字符串转换为XML文件?

时间:2012-12-06 15:58:56

标签: java spring spring-integration

  

可能重复:
  Writing to a XML file in Java

我将XML文本作为字符串。

<someNode>
    <id>A124</id>
    <status>404</status>
    <message>No data</message>
</someNode>

我将上面的XML数据作为String。是否可以将文本转换为XML文件并归档生成的XML文件?

谢谢!

5 个答案:

答案 0 :(得分:1)

DocumentBuilderFactory dbfac = DocumentBuilderFactory.newInstance();
DocumentBuilder docBuilder = dbfac.newDocumentBuilder();
Document doc = docBuilder.parse(new InputSource(new StringReader(theString)));

答案 1 :(得分:0)

您可以使用java.io.FileWriter保存文件。

String fileData = "<sample><xml>data</xml></sample>";
File outputFile = new File("someFile.xml");
BufferedWriter bw = null;
try{
    bw = new BufferedWriter(new FileWriter(outputFile));
    bw.write(fileData);
}
catch(IOException e)
{
    e.printStackTrace();
}
finally
{
    try{bw.close();}catch(Exception e){}
}

如果您需要操纵xml,请执行 Kazekage Gaara 说:

DocumentBuilderFactory dbfac = DocumentBuilderFactory.newInstance();
DocumentBuilder docBuilder = dbfac.newDocumentBuilder();
Document doc = docBuilder.parse(new InputSource(new StringReader(theString)));

为了省钱,你可以像我上面所说的那样做。要将文档转换回字符串:

fileData = doc.toString();

答案 2 :(得分:0)

public class StringToXML {  
public static void main(String[] args) {  
    String xmlString = "<?xml version=\"1.0\" encoding=\"utf-8\"?><soap:Envelope xmlns:soap=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\"></soap:Envelope>";  

     DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();  

    DocumentBuilder builder;  
    try  
    {  
        builder = factory.newDocumentBuilder();  

        // Use String reader  
        Document document = builder.parse( new InputSource(  
                new StringReader( xmlString ) ) );  

        TransformerFactory tranFactory = TransformerFactory.newInstance();  
        Transformer aTransformer = tranFactory.newTransformer();  
        Source src = new DOMSource( document );  
        Result dest = new StreamResult( new File( "xmlFileName.xml" ) );  
        aTransformer.transform( src, dest );  
    } catch (Exception e)  
    {  
        // TODO Auto-generated catch block  
        e.printStackTrace();  
    }  
}  

此信息很有用。

谢谢, 帕

答案 3 :(得分:0)

简单如下:

String text = "<your><xml>data</xml></your>";
Writer writer = new FileWriter("/tmp/filename.xml");
writer.write(text);
writer.flush();
writer.close();

答案 4 :(得分:0)

我建议使用commons-io。它有一个方法可以完成你需要的一切。

代码看起来像

FileUtils.writeStringToFile(new File("filename.xml"), xml);