Question

我有以下内容，我正在动态创建一个链接我遇到了一个分裂的连接。

link = "<li><span id='number'>" + link.split(" ")[0] + ".</span>" // Adding a "peroid" character after the reason number and make it bold 
        + "<a href='#" + reasonTitle + "' " // Open link tag off adding href with relevant reference
        + "onclick=\"_gaq.push([\'_trackEvent\', \'" + experimentConversionReference + "\', \'ReasonClicked\', \'" + reasonTitleSpaces + "\'])\;\">" // Adding event tracking for google
        + link.split(/\d/)[1] // Add back on the back end of the split string
        + "</a>" // Close link tag off
        + "</li>";

更具体地说，line 4上面我想从[1]抓取并打印数组中的所有内容，我该怎样才能这样做？

我不想做的是

link.split(/\d/)[1] + link.split(/\d/)[2]  + link.split(/\d/)[3]  + link.split(/\d/)[]

等等。

Answer 1

使用此：

link.split(/\d/).slice(1).join('')

Answer 2

拆分并加入，不包括第一项：

var joined  = link.split(/\d/);
joined .shift(); // remove first item
joined .join(''); // join the array

然后使用它：

link = "<li><span id='number'>" + link.split(" ")[0] + ".</span>" // Adding a "peroid" character after the reason number and make it bold 
        + "<a href='#" + reasonTitle + "' " // Open link tag off adding href with relevant reference
        + "onclick=\"_gaq.push([\'_trackEvent\', \'" + experimentConversionReference + "\', \'ReasonClicked\', \'" + reasonTitleSpaces + "\'])\;\">" // Adding event tracking for google
        + joined // Add back on the back end of the split string
        + "</a>" // Close link tag off
        + "</li>";

Answer 3

您不需要拆分，只需在空格后获取字符串的一部分：

link.substr(link.indexOf(" ") + 1);

串联数组的串联

3 个答案: