java.lang.illegalstateexception在activity类的android片段中找不到方法(view)

时间:2012-12-06 08:52:32

标签: android android-gridview

在我的程序中,我正在使用带有一些图像的gridview,我想在用户点击gridview中的图像时显示一个菜单,然后从显示的菜单中选择要执行的操作。

这是我的代码:

package Kazemi.Alireza.scada;
import android.annotation.SuppressLint;
import android.app.Dialog;
import android.app.FragmentManager;
import android.content.Context;
import android.graphics.Typeface;
import android.graphics.drawable.AnimationDrawable;
import android.os.Bundle;
import android.support.v4.app.Fragment;
import android.view.ContextMenu;
import android.view.ContextMenu.ContextMenuInfo;
import android.view.Gravity;
import android.view.LayoutInflater;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.view.ViewGroup;
import android.view.WindowManager;
import android.view.ViewGroup.LayoutParams;
import android.widget.AdapterView;
import android.widget.AdapterView.AdapterContextMenuInfo;
import android.widget.BaseAdapter;
import android.widget.Button;
import android.widget.GridView;
import android.widget.ImageView;
import android.widget.LinearLayout;
import android.widget.PopupWindow;
import android.widget.TextView;
import android.widget.Toast;
import android.widget.AdapterView.OnItemClickListener;


@SuppressLint("NewApi")
public class CitiesTab extends Fragment {

AnimationDrawable[] frameAnimation;
ImageAdapter ia;
GridView gridView;
int in;

public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
    return (LinearLayout)inflater.inflate(R.layout.citytab, container, false);
}

public void onStart()
{
    super.onStart();
    ia = new ImageAdapter(getActivity());
    gridView = (GridView) getActivity().findViewById(R.id.gridview);
    gridView.setAdapter(ia);
    gridView.post(new Starter());
    gridView.setOnItemClickListener(new OnItemClickListener()
    {
        public void onItemClick(AdapterView<?> parent, View v, int position, long id)
        {
            dialog = new Dialog(getActivity(), android.R.style.Theme_InputMethod);
            dialog.setContentView(R.layout.pump_menu);
        }});
    /*Button btn = (Button) getActivity().findViewById(R.id.Button_pumpInfo);
    btn.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            Toast.makeText(getActivity(), "You clicked on Item 1",
                    Toast.LENGTH_LONG).show();
        }
    });*/
}

public void Btn_pumpInfo_Clicked(View v) {
    // TODO Auto-generated method stub
    Toast.makeText(getActivity(), "You clicked on Item 1",
            Toast.LENGTH_LONG).show();
}

}

这是我的pump_menu.xml代码:

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:background="#a5c5f0"
    android:orientation="vertical" >

<Button 
    android:id="@+id/Button_pumpInfo" 
    android:layout_height="40dp" 
    android:text="@string/menu_pumpinfo_item1"
    android:textSize="11sp" 
    android:layout_width="125dp"
    android:background="#a5c5f0"
    android:onClick="Btn_pumpInfo_Clicked"/>

和citytab.xml:

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:orientation="vertical" >

<GridView 
    android:id="@+id/gridview"
    android:layout_width="fill_parent" 
    android:layout_height="fill_parent"
    android:numColumns="auto_fit"
    android:verticalSpacing="10dp"
    android:horizontalSpacing="10dp"
    android:columnWidth="90dp"
    android:stretchMode="columnWidth"
    android:gravity="center" />

<ImageView 
    android:id="@+id/gifViewer"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:scaleType="center"/>

</LinearLayout>

当我使用此代码时,发生错误:

java.lang.RuntimeException: Unable to start activity ComponentInfo{Kazemi.Alireza.scada/Kazemi.Alireza.scada.MainMenu}: java.lang.NullPointerException

当我评论Btn_pumpInfo_Clicked()方法,并在onStart()中取消注释按钮监听器时发生以下错误:

java.lang.IllegalStateException: Could not find a method Btn_pumpInfo_Clicked(View) in the activity class android.view.ContextThemeWrapper for onClick handler on view class android.widget.Button with id 'Button_pumpInfo'
问题在哪里? 谢谢

3 个答案:

答案 0 :(得分:42)

您无法在onClick课程中为android:onClick(来自Button的布局)注册Dialog回调(使用Fragment)因为Android不会找到它,因为它会搜索 Activity以查找匹配该名称(Btn_pumpInfo_Clicked)的方法,它会抛出该异常。而是在Button中查找Dialog并为其指定一个普通的侦听器:

//...
dialog.setContentView(R.layout.pump_menu)
Button b = (Button) dialog.findViewById(R.id.Button_pumpInfo);
b.setOnClickListener(new OnClickListener() {

   @Override
   public void onCLick(View v) {
       // profit
   }
});

或移动方法:

public void Btn_pumpInfo_Clicked(View v) {
    // TODO Auto-generated method stub
    Toast.makeText(getActivity(), "You clicked on Item 1",
            Toast.LENGTH_LONG).show();
}
如果适合你,请在Activity课程中

答案 1 :(得分:3)

如果仅在Android 2.x上发生此错误,请检查Android 4特定类成员的Activity类层次结构:

public class HomeActivity extends Activity {

  private android.app.ActionBar.LayoutParams customTitleParams;

  ....
}

Android 2.x上没有类android.app.ActionBar.LayoutParams,这可能会导致问题。

答案 2 :(得分:0)

当调用onClick视图(按钮)的方法无法访问或在相应活动中不可用时,也会发生这种情况。 检查步骤:

  • 检查android的值中的方法名称:onClick属性与实际编写的方法匹配。
  • 检查方法的访问修饰符是否公开,以便可用 执行。