Question

OpenFileDialog ofImport = new OpenFileDialog();
ofImport.Title = "Select file";
ofImport.InitialDirectory = @"c:\";
ofImport.FileName = txtFileName.Text;
ofImport.Filter = "Excel Sheet(*.xlsx)|*.xlsx|All Files(*.*)|*.*";
ofImport.FilterIndex = 1;
ofImport.RestoreDirectory = true;

if (ofImport.ShowDialog() == DialogResult.OK)
{

     string path = System.IO.Path.GetFullPath(ofImport.FileName);
     string query = "SELECT * FROM Customer.xlsx";
     OleDbConnection conn = new OleDbConnection();
     conn.ConnectionString = @"Provider=Microsoft.ACE.OLEDB.12.0;Data Source="+ofImport.FileName+";Extended Properties=" + "\"Excel 12.0 Xml;HDR=YES;IMEX=1\"";
     OleDbDataAdapter adapter = new OleDbDataAdapter(query, conn);

     //DataSet dataSet = new DataSet();
     adapter.Fill(dsSource);
     dataGridView1.DataSource = dsSource;

}
else
{
     ofImport.Dispose();
}

我想使用DataGridView将Excel数据检索到dataset。 dsSource是使用的数据集。

我收到的错误在adapter.Fill(dsSource);行

Microsoft Access数据库引擎找不到对象'xlsx'。确保对象存在，并拼写其名称和路径名字正确。如果'xlsx'不是本地对象，请检查您的网络连接或联系服务器管理员。

我可以选择文件但不填写数据集。

怎么办？

Answer 1

在以下行中，您要从文件中选择：

string query = "SELECT * FROM " + ofImport.FileName;

然而，您需要从表中进行选择，所以这应该是这样的：

string query = "SELECT * FROM [Sheet1$]"; // Note the '$' sign!!

您需要找出Excel文件的工作表名称，以便您可以从中进行选择（工作表名称显示在工作表的选项卡中 - 只需向其附加$符号）。 文件名仅用于连接字符串，因此数据库引擎知道要打开哪个文件。

想想以下与.NET中通常的SQL数据库访问类比：

file name = database name
sheet name = table name

修改
为了使事情更清楚：在下图中，工作表名称用红色圈出。在您的代码中，在select语句中写入工作表名称，后跟美元符号。

Answer 2

这是我的代码，在没有数据库配置的情况下读取excel到datagridview。

        DataTable dt = new DataTable("dataTable");
        DataSet dsSource = new DataSet("dataSet");
        dt.Reset();

        Excel.Workbook ExWorkbook;
        Excel.Worksheet ExWorksheet;
        Excel.Range ExRange;
        Excel.Application ExObj = new Excel.Application();

        openFileDialog1.Filter = "Excel Files|*.xls;*.xlsx;*.xlsm";
        DialogResult result = openFileDialog1.ShowDialog();

        if (result == DialogResult.OK) // Test result.
        {
            ExWorkbook = ExObj.Workbooks.Open(openFileDialog1.FileName, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value);
            ExWorksheet = (Excel.Worksheet)ExWorkbook.Sheets.get_Item(1);
            ExRange = ExWorksheet.UsedRange;

            for (int Cnum = 1; Cnum <= ExRange.Columns.Count; Cnum++)
            {
                dt.Columns.Add(new DataColumn((ExRange.Cells[1, Cnum] as Excel.Range).Value2.ToString()));
            }
            dt.AcceptChanges();

            string[] columnNames = new String[dt.Columns.Count];
            for (int i = 0; i < dt.Columns.Count; i++)
            {
                columnNames[0] = dt.Columns[i].ColumnName;
            }
            //string[] columnNames = (from dc in dt.Columns.Cast<DataColumn>() select dc.ColumnName).ToArray();

            for (int Rnum = 2; Rnum <= ExRange.Rows.Count; Rnum++)
            {
                DataRow dr = dt.NewRow();
                for (int Cnum = 1; Cnum <= ExRange.Columns.Count; Cnum++)
                {
                    if ((ExRange.Cells[Rnum, Cnum] as Excel.Range).Value2 != null)
                    {
                        dr[Cnum - 1] = (ExRange.Cells[Rnum, Cnum] as Excel.Range).Value2.ToString();
                    }
                }
                dt.Rows.Add(dr);
                dt.AcceptChanges();
            }
            ExWorkbook.Close(true, Missing.Value, Missing.Value);
            ExObj.Quit();

            dataGridView1.DataSource = dt;

Answer 3

    DialogResult dialogResult = MessageBox.Show("Sure", "Some Title", MessageBoxButtons.YesNo);
    if (dialogResult == DialogResult.Yes)
    {
        dt = dsSource.Tables[Index];
        dt.Reset();
        Excel.Workbook workbook;
        Excel.Worksheet NwSheet;
        Excel.Range ShtRange;
        Microsoft.Office.Interop.Excel.Application ExcelObj = new Microsoft.Office.Interop.Excel.Application();
        OpenFileDialog filedlgExcel = new OpenFileDialog();
        filedlgExcel.Title = "Select file";
        filedlgExcel.InitialDirectory = @"c:\";
        //filedlgExcel.FileName = textBox1.Text;
        filedlgExcel.Filter = "Excel Sheet(*.xlsx)|*.xlsx|All Files(*.*)|*.*";
        filedlgExcel.FilterIndex = 1;
        filedlgExcel.RestoreDirectory = true;
        if (filedlgExcel.ShowDialog() == DialogResult.OK)
        {

            workbook = ExcelObj.Workbooks.Open(filedlgExcel.FileName, Missing.Value, Missing.Value,
                 Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value,
                 Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value, Missing.Value);
            NwSheet = (Excel.Worksheet)workbook.Sheets.get_Item(1);
            ShtRange = NwSheet.UsedRange;
            for (int Cnum = 1; Cnum <= ShtRange.Columns.Count; Cnum++)
            {
                dt.Columns.Add(new DataColumn((ShtRange.Cells[1, Cnum] as Excel.Range).Value2.ToString()));
            }
            dt.AcceptChanges();
            string[] columnNames = new String[dt.Columns.Count];
            for (int i = 0; i < dt.Columns.Count; i++)
            {
                columnNames[0] = dt.Columns[i].ColumnName;
            }
            //string[] columnNames = (from dc in dt.Columns.Cast<DataColumn>() select dc.ColumnName).ToArray();


            for (int Rnum = 2; Rnum <= ShtRange.Rows.Count; Rnum++)
            {
                DataRow dr = dt.NewRow();
                for (int Cnum = 1; Cnum <= ShtRange.Columns.Count; Cnum++)
                {
                    if ((ShtRange.Cells[Rnum, Cnum] as Excel.Range).Value2 != null)
                    {
                        dr[Cnum - 1] = (ShtRange.Cells[Rnum, Cnum] as Excel.Range).Value2.ToString();
                    }
                }
                dt.Rows.Add(dr);
                dt.AcceptChanges();
            }
            workbook.Close(true, Missing.Value, Missing.Value);
            ExcelObj.Quit();

            dataGridView1.DataSource = dt;

将Excel文件导入DataGridView

3 个答案: