想象一下这个.txt
文件:
Example.txt
Row Column1 Column2 Column3 <br>
1 aaa bbb ccc<br>
2 ddd eee fff
如何使用命令行在表中获取值?
实施例。 :( Row = 2,Column2)返回值“eee” 防爆。 :( Row = 1,Column3)返回值“ccc”。
我正在尝试findstr
,但我不知道如何实现它。
答案 0 :(得分:0)
假设行信息实际上在文件中,并假设没有值包含空格:
@echo off
call :getValue 2 Column2 "Example.txt"
call :getValue 1 Column3 "Example.txt"
call :getValue 0 Column1 "Example.txt"
call :getValue 1 DoesNotExist "Example.txt"
exit /b
:getValue
setlocal
<%3 set /p "header="
set token=0
for %%C in (%header%) do (
set /a token+=1
if %%C==%2 goto columnFound
)
echo Column %2 not found in %3
exit /b
:columnFound
for /f "tokens=%token%" %%A in ('findstr /blc:"%1 " %3') do (
echo %3 (Row=%1, %2^) = %%A
exit /b
)
echo Row %1 not found in %3
exit /b
结果
"Example.txt" (Row=2, Column2) = eee
"Example.txt" (Row=1, Column3) = ccc
Row 0 not found in "Example.txt"
Column DoesNotExist not found in "Example.txt"