我如何在MultipartFormDataStreamProvider
中使用Request.Content.ReadAsMultipartAsync
和ApiController
?
我已经搜索了一些教程,但我无法使用它们中的任何一个,即使用.net 4.5。
这就是我目前得到的:
public class TestController : ApiController
{
const string StoragePath = @"T:\WebApiTest";
public async void Post()
{
if (Request.Content.IsMimeMultipartContent())
{
var streamProvider = new MultipartFormDataStreamProvider(Path.Combine(StoragePath, "Upload"));
await Request.Content.ReadAsMultipartAsync(streamProvider);
foreach (MultipartFileData fileData in streamProvider.FileData)
{
if (string.IsNullOrEmpty(fileData.Headers.ContentDisposition.FileName))
{
throw new HttpResponseException(Request.CreateResponse(HttpStatusCode.NotAcceptable, "This request is not properly formatted"));
}
string fileName = fileData.Headers.ContentDisposition.FileName;
if (fileName.StartsWith("\"") && fileName.EndsWith("\""))
{
fileName = fileName.Trim('"');
}
if (fileName.Contains(@"/") || fileName.Contains(@"\"))
{
fileName = Path.GetFileName(fileName);
}
File.Copy(fileData.LocalFileName, Path.Combine(StoragePath, fileName));
}
}
else
{
throw new HttpResponseException(Request.CreateResponse(HttpStatusCode.NotAcceptable, "This request is not properly formatted"));
}
}
}
我得到了例外
MIME多部分流的意外结束。 MIME多部分消息不是 完整。
await task;
运行时。
有没有人知道我做错了什么或者在使用web api的普通asp.net项目中有一个工作示例。
答案 0 :(得分:31)
我解决了错误,我不明白这与多部分流的结束有什么关系,但这是工作代码:
public class TestController : ApiController
{
const string StoragePath = @"T:\WebApiTest";
public async Task<HttpResponseMessage> Post()
{
if (Request.Content.IsMimeMultipartContent())
{
var streamProvider = new MultipartFormDataStreamProvider(Path.Combine(StoragePath, "Upload"));
await Request.Content.ReadAsMultipartAsync(streamProvider);
foreach (MultipartFileData fileData in streamProvider.FileData)
{
if (string.IsNullOrEmpty(fileData.Headers.ContentDisposition.FileName))
{
return Request.CreateResponse(HttpStatusCode.NotAcceptable, "This request is not properly formatted");
}
string fileName = fileData.Headers.ContentDisposition.FileName;
if (fileName.StartsWith("\"") && fileName.EndsWith("\""))
{
fileName = fileName.Trim('"');
}
if (fileName.Contains(@"/") || fileName.Contains(@"\"))
{
fileName = Path.GetFileName(fileName);
}
File.Move(fileData.LocalFileName, Path.Combine(StoragePath, fileName));
}
return Request.CreateResponse(HttpStatusCode.OK);
}
else
{
return Request.CreateResponse(HttpStatusCode.NotAcceptable, "This request is not properly formatted");
}
}
}
答案 1 :(得分:7)
首先,您应该在ajax请求标头中将 enctype 定义为 multipart / form-data。
[Route("{bulkRequestId:int:min(1)}/Permissions")]
[ResponseType(typeof(IEnumerable<Pair>))]
public async Task<IHttpActionResult> PutCertificatesAsync(int bulkRequestId)
{
if (Request.Content.IsMimeMultipartContent("form-data"))
{
string uploadPath = HttpContext.Current.Server.MapPath("~/uploads");
var streamProvider = new MyStreamProvider(uploadPath);
await Request.Content.ReadAsMultipartAsync(streamProvider);
List<Pair> messages = new List<Pair>();
foreach (var file in streamProvider.FileData)
{
FileInfo fi = new FileInfo(file.LocalFileName);
messages.Add(new Pair(fi.FullName, Guid.NewGuid()));
}
//if (_biz.SetCertificates(bulkRequestId, fileNames))
//{
return Ok(messages);
//}
//return NotFound();
}
return BadRequest();
}
}
public class MyStreamProvider : MultipartFormDataStreamProvider
{
public MyStreamProvider(string uploadPath) : base(uploadPath)
{
}
public override string GetLocalFileName(HttpContentHeaders headers)
{
string fileName = Guid.NewGuid().ToString()
+ Path.GetExtension(headers.ContentDisposition.FileName.Replace("\"", string.Empty));
return fileName;
}
}