我正在编写一个用于发送和接收消息的基本Android应用程序。我也在使用Tomcat 7.0.21编写服务器端代码。我目前正在尝试实现"程序化Web应用程序安全性" (http://courses.coreservlets.com/Course-Materials/msajsp.html),其中明确执行客户端身份验证。
我现在已经完成了这个实现,当我使用REST客户端发送请求时,它工作正常。但是,当我从Android设备/模拟器发送请求时,我得到一个java.io.FileNotFoundException。当我检查tomcat访问日志时,似乎tomcat在我的Servlet代码执行之前发送了400 Bad Request,从而产生异常。
我不知道这个问题是客户端还是服务器端。关于如何实现这一点的任何见解或建议都将受到极大的限制。谢谢。
Tomcat localhost_access_log:
192.168.1.2 - - [05/Dec/2012:12:20:39 +0100] "GET /CA/users/get_contacts?user_id=freespirit HTTP/1.1" 400 -
我扩展的Servlet类,我相信它永远不会被执行:
package carter.server.conversations;
import java.io.IOException;
import java.sql.Connection;
import java.sql.SQLException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import sun.misc.BASE64Decoder;
import carter.sqlite.SQLiteUtilities;
import carter.sqlite.conversations.DatabaseHelper;
public class AuthorizationServlet extends HttpsServlet {
protected static final int SERVLET_EXCEPTION_UNAUTHORIZED = 1;
@Override
protected void doGet(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
super.doGet(request, response);
String authorization = request.getHeader("Authorization");
if(authorization == null){
System.out.println("CAAuthorizationServlet: Authorization is null. Sending 401.");
response.sendError(HttpServletResponse.SC_UNAUTHORIZED);
}
else{
String base64encodedDetails = authorization.substring(6).trim(); //remove "BASIC " prefix
BASE64Decoder decoder = new BASE64Decoder();
String unencodedDetails = new String(decoder.decodeBuffer(base64encodedDetails));
String[] userDetails = unencodedDetails.split(":");
//check database for given details
Connection databaseConnection = SQLiteUtilities.getConnection(Constants.databasePath);
try{
String password = DatabaseHelper.getPassword(userDetails[0], databaseConnection);
if(password.equals(userDetails[1]) == false){
//password does not match this user
System.out.println("CAAuthorizationServlet: password does not match this user. Sending 401.");
response.sendError(HttpServletResponse.SC_UNAUTHORIZED);
}
}
catch(SQLException e){
// no such user found in database.
System.out.println("CAAuthorizationServlet: no such user exists in database. Sending 401.");
response.sendError(HttpServletResponse.SC_UNAUTHORIZED);
}
finally{
SQLiteUtilities.closeConnection(databaseConnection);
}
}
}
@Override
protected void doPost(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
super.doPost(request, response);
doGet(request, response);
}
}
package carter.server.conversations;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class HttpsServlet extends HttpServlet {
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
System.out.println("CAHttpsServlet: checking request is secure");
if(request.isSecure() == false){
System.out.println("CAHttpsServlet: Request is NOT secure. Sending 400");
response.sendError(HttpServletResponse.SC_BAD_REQUEST);
}
}
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
doGet(request, response);
}
}
答案 0 :(得分:1)
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
System.out.println("CAHttpsServlet: checking request is secure");
if(request.isSecure() == false){
System.out.println("CAHttpsServlet: Request is NOT secure. Sending 400");
response.sendError(HttpServletResponse.SC_BAD_REQUEST);
}
}
答案 1 :(得分:0)
它似乎与Same Origin Policy相关。
您需要在Tomcat服务器上启用跨域请求。
为此,您需要在Tomcat的ROOT webapp上创建一个crossdomain.xml
文件,其内容如下:
<?xml version="1.0"?>
<!DOCTYPE cross-domain-policy SYSTEM "http://www.adobe.com/xml/dtds/cross-domain-policy.dtd">
<cross-domain-policy>
<site-control permitted-cross-domain-policies="all"/>
<allow-access-from domain="*" />
<allow-http-request-headers-from domain="*" headers="*"/>
</cross-domain-policy>