Question

这是我在python 3.2.3上的代码IDLE：我基本上让用户输入一堆数字然后转换为列表。之后，我想检查是否有任何小于10或超过100的数字。

n = input("(Enter a empty string to quit) Enter a number: ")
while n != "":
    numbers.append(int(n))
    n = input("(Enter a empty string to quit) Enter a number; ")

print ("The list is", numbers)

if numbers < 10:
    print ("your list has numbers less than 10.")
if numbers > 100:
    print ("your list has numbers more than 100")

列表显示正常但是当我尝试检查是否有任何值小于10或超过100时，它有一个错误。我该如何解决这个问题？

Answer 1

使用any：

if any(number < 10 for number in numbers):
    print ("your list has numbers less than 10.")
if any(number > 100 for number in numbers):
    print ("your list has numbers more than 100")

此外，python中也有all函数。

顺便说一下，你可以加入两行：

if all(10 < number < 100 for number in numbers):
    #correct code goes here

Answer 2

如果要检查列表中的元素，请执行

a = ["Hello world","Basic comments","Basic outputs"]
g = []
for i in a:
    g.extend(i)
print("Nice?")
#This is actually the way of transferring characters in a list to the other!

检查列表中的数字？

2 个答案: