Question

我有一个应用程序和一个.sh文件。我需要一个苹果脚本，双击时，设置该.sh文件的权限并运行它。以下是我的代码：

set app_directory to POSIX path of ((container of (path to me)) as text)

tell application "Terminal" to do shell script "chmod 777 " & app_directory & " start.sh"
tell application "Terminal" to do shell script app_direcory & "start.sh"

但我得到以下错误：

错误“无法创建别名容器”Macintosh HD：用户：santhosh：桌面：EPPFN ver1：条形码Application_mac：test_app.app：\“到类型文本。”来自别名容器的数字-1700“Macintosh HD：用户：santhosh：桌面：EPPFN ver1：条形码Application_mac：test_app.app：”到文本

如何设置当前路径，然后使用相对路径运行脚本。

编辑：我将代码修改为：

set x to POSIX file ((POSIX path of (path to me)) & "/..") as text
set thescript to ("chmod 777 " & x & "start.sh") as text
tell application "Terminal" to do shell script (thescript)

仍然没有运气。

Answer 1

尝试：

tell application "System Events" to set app_directory to POSIX path of (container of (path to me))
set thescript to ("chmod 777 " & quoted form of (app_directory & "/start.sh"))
do shell script thescript

设置当前目录 - 苹果脚本

1 个答案: