我查看了documentation of polyline,没有选项让它破灭。
有人知道如何用android google map sdk v2绘制虚线折线吗?
答案 0 :(得分:16)
现在在Polyline中,您可以将模式设置为Dash,Dot或Gap 只需应用以下
public static final int PATTERN_DASH_LENGTH_PX = 20;
public static final int PATTERN_GAP_LENGTH_PX = 20;
public static final PatternItem DOT = new Dot();
public static final PatternItem DASH = new Dash(PATTERN_DASH_LENGTH_PX);
public static final PatternItem GAP = new Gap(PATTERN_GAP_LENGTH_PX);
public static final List<PatternItem> PATTERN_POLYGON_ALPHA = Arrays.asList(GAP, DASH);
private void drawDashedLeg(GoogleMap googleMap, Route route) {
PolylineOptions polyOptions = new PolylineOptions();
polyOptions.color(ContextCompat.getColor(getContext(), R.color.coolgrey));
polyOptions.addAll(route.getPoints());
polyOptions.pattern(PATTERN_POLYGON_ALPHA);
Polyline polyline = googleMap.addPolyline(polyOptions);
polylines.add(polyline);
}
答案 1 :(得分:13)
Alexey,我刚刚创建了一个对我有用的功能,我认为这对你有用:
public static void createDashedLine(GoogleMap map, LatLng latLngOrig, LatLng latLngDest, int color){
double difLat = latLngDest.latitude - latLngOrig.latitude;
double difLng = latLngDest.longitude - latLngOrig.longitude;
double zoom = map.getCameraPosition().zoom;
double divLat = difLat / (zoom * 2);
double divLng = difLng / (zoom * 2);
LatLng tmpLatOri = latLngOrig;
for(int i = 0; i < (zoom * 2); i++){
LatLng loopLatLng = tmpLatOri;
if(i > 0){
loopLatLng = new LatLng(tmpLatOri.latitude + (divLat * 0.25f), tmpLatOri.longitude + (divLng * 0.25f));
}
Polyline polyline = map.addPolyline(new PolylineOptions()
.add(loopLatLng)
.add(new LatLng(tmpLatOri.latitude + divLat, tmpLatOri.longitude + divLng))
.color(color)
.width(5f));
tmpLatOri = new LatLng(tmpLatOri.latitude + divLat, tmpLatOri.longitude + divLng);
}
}
答案 2 :(得分:12)
目前的版本无法实现。请按照此问题进行更新:https://code.google.com/p/gmaps-api-issues/issues/detail?id=4633
<强>更新强>
最近,Google在Google Maps Android API v2中为折线实现了此功能,并将问题4633标记为已修复。
请参阅Shapes Guide中有关笔画模式的信息。请参阅“折线和多边形”教程中的example。
您还可以在此处阅读相应的博文:
https://maps-apis.googleblog.com/2017/02/styling-and-custom-data-for-polylines.html
答案 3 :(得分:9)
我创建了以下函数来绘制带有LatLng点列表的虚线折线。 无论缩放如何,该算法都会创建0.002 kms(后跟0.002 kms米间隙)的线条。当您不想在缩放更改时重新绘制折线时,这非常有用。
private void drawDashedPolyLine(GoogleMap mMap, ArrayList<LatLng> listOfPoints, int color) {
/* Boolean to control drawing alternate lines */
boolean added = false;
for (int i = 0; i < listOfPoints.size() - 1 ; i++) {
/* Get distance between current and next point */
double distance = getConvertedDistance(listOfPoints.get(i),listOfPoints.get(i + 1));
/* If distance is less than 0.002 kms */
if (distance < 0.002) {
if (!added) {
mMap.addPolyline(new PolylineOptions()
.add(listOfPoints.get(i))
.add(listOfPoints.get(i + 1))
.color(color));
added = true;
} else {/* Skip this piece */
added = false;
}
} else {
/* Get how many divisions to make of this line */
int countOfDivisions = (int) ((distance/0.002));
/* Get difference to add per lat/lng */
double latdiff = (listOfPoints.get(i+1).latitude - listOfPoints
.get(i).latitude) / countOfDivisions;
double lngdiff = (listOfPoints.get(i + 1).longitude - listOfPoints
.get(i).longitude) / countOfDivisions;
/* Last known indicates start point of polyline. Initialized to ith point */
LatLng lastKnowLatLng = new LatLng(listOfPoints.get(i).latitude, listOfPoints.get(i).longitude);
for (int j = 0; j < countOfDivisions; j++) {
/* Next point is point + diff */
LatLng nextLatLng = new LatLng(lastKnowLatLng.latitude + latdiff, lastKnowLatLng.longitude + lngdiff);
if (!added) {
mMap.addPolyline(new PolylineOptions()
.add(lastKnowLatLng)
.add(nextLatLng)
.color(color));
added = true;
} else {
added = false;
}
lastKnowLatLng = nextLatLng;
}
}
}
}
private double getConvertedDistance(LatLng latlng1, LatLng latlng2) {
double distance = DistanceUtil.distance(latlng1.latitude,
latlng1.longitude,
latlng2.latitude,
latlng2.longitude);
BigDecimal bd = new BigDecimal(distance);
BigDecimal res = bd.setScale(3, RoundingMode.DOWN);
return res.doubleValue();
}
Util类计算两个LatLng之间的距离:
public class DistanceUtil {
public static double distance(double lat1, double lon1, double lat2,
double lon2) {
if ((lat1 == lat2) && (lon1 == lon2)) {
return 0;
} else
return distance(lat1, lon1, lat2, lon2, 'K');
}
public static double distance(double lat1, double lon1, double lat2,
double lon2, char unit) {
double theta = lon1 - lon2;
double dist = Math.sin(deg2rad(lat1)) * Math.sin(deg2rad(lat2))
+ Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2))
* Math.cos(deg2rad(theta));
dist = Math.acos(dist);
dist = rad2deg(dist);
dist = dist * 60 * 1.1515;
if (unit == 'K') {
dist = dist * 1.609344;
} else if (unit == 'N') {
dist = dist * 0.8684;
}
return (dist);
}
private static double deg2rad(double deg) {
return (deg * Math.PI / 180.0);
}
private static double rad2deg(double rad) {
return (rad * 180.0 / Math.PI);
}
}
注意:上述算法会生成大量折线,这些折线可能需要一段时间才能渲染。仅当点列表很小时才有用。