Question

好的，我有一个看起来像这样的表：

ID   AMOUNT      PAID
1    50.00       Y
2    100.00      N
3    200.00      Y

我希望看到类似的内容：

Total     Due Paid
350.00    1   2

所以我的SQL看起来像（在我脑海里......它不会那样工作，这就是为什么我在这里）

select sum(amount)
,count(paid where paid='y') as due
,count(paid where paid='n') as paid 
from sometable where something=somethingelse

Answer 1

select sum(amount) as total, 
       sum(case paid when 'N' then 1 else 0 end) as due, 
       sum(case paid when 'Y' then 1 else 0 end) as paid
from sometable where something=somethingelse

Answer 2

还有一个选择

SELECT SUM(AMOUNT) AS Total,
       COUNT(CASE WHEN PAID = 'Y' THEN PAID END) AS Paid,
       COUNT(CASE WHEN PAID = 'N' THEN PAID END) AS Due
FROM sometable
WHERE something = somethingelse

演示SQLFiddle

如何在聚合函数SQL Server中使用where子句

2 个答案: