Question

我对php很新。

我有一个数组

$ arr = array（0 =＆gt; array（'GID'=＆gt; 1，'groupname'=＆gt;“cat1”，'members'=＆gt; array（0 =＆gt; array（'mid'= ＆GT; 11， 'MNAME'=＆GT; 'WWWW'），1 =＆GT;阵列（ '中'=＆GT; 12， 'MNAME'=＆GT; 'wswww'）））， 1 =＆gt;阵列（ 'GID'=大于2， '组名'=＆gt; “中CAT2”， '成员'=＆GT;阵列（0 =＆GT;阵列（ '中'=＆GT; 13， 'MNAME'=＆GT;'gggwwww '），1 =＆GT;阵列（' 中 '=＆GT; 14，' MNAME '=＆GT;' wvvwww'）））， 2 =＆gt;阵列（ 'GID'=→3 '组名'=＆gt; “中CAT1”， '成员'=＆GT;阵列（0 =＆GT;阵列（ '中'=→15 'MNAME'=＆GT;'wwddsww '）），1 =＆GT;阵列（' 中 '=＆GT; 16，' MNAME '=＆GT;' wwwdddw'）））;

      ie...,I have GID,groupname,mid(member id),mname(member name).I want to insert a new mid and mname into a group if it is already in the array ,if it is not exists then create a new subarray with these elements..I also need to check a member id(mid) is also present.........................I used the code but its not working fine............. if (!empty($evntGroup)) {


            foreach ($evntGroup as $k => $group) {

                if ($group['GID'] == $group_id) {
                    foreach($group as $j=> $mem){

                    if($mem['mid'] == $mem_id){

                        unset($evntGroup[$k]['members'][$j]['mid']);
                        unset($evntGroup[$k]['members'][$j]['mname']);
                    }
                    else{


                    $evntGroup[$k]['members'][] = array(
                        'mid' => $mem_id,
                        'mname' => $mem_name);

                    }}
                } else {


                    $evntGroup[] = array(
                        'GID' => $group_id,
                        'groupname' => $Group['event_group_name'],
                        'members' => array(
                            0 => array(
                                'mid' => $mem_id,
                                'mname' => $mem_name
                            )
                        )
                    );

                }

            }
        } else {

            $evntGroup[$i]['GID'] = $group_id;
            $evntGroup[$i]['groupname'] = $Group['event_group_name'];
            $evntGroup[$i]['members'][] = array(
                'mid' => $mem_id,
                'mname' => $mem_name);
            $i++;

        }

Answer 1

以函数的形式，最简单的解决方案将如下所示：

function isGidInArray($arr, $val) {
    foreach($arr as $cur) {
        if($cur['GID'] == $val)
            return true;
    }
    return false;
}

您已经更新了问题，以指定在找到指定的GID时您想要执行的操作，但这只是对循环的一个简单补充：

function doSomethingIfGidInArray($arr, $val) {
    foreach($arr as $cur) {
        if($cur['GID'] == $val) {
            doSomething();
            break; //Assuming you only expect one instance of the passed value - stop searching after it's found
        }
    }
}

遗憾的是，没有本机PHP数组函数可以检索父数组中每个数组的相同索引。我经常想要这样的东西。

Answer 2

像这样的东西将匹配GOD等于3：

foreach( $arr as $item ) {
  if( $item['GID'] == 3 ) {
     // matches
  }
}

Answer 3

有代码

function updateByGid(&$array,$gid,$groupname,$mid,$mname) {
    //For each element of the array
    foreach ($array as $ii => $elem) {
        //If GID has the same value
        if ($elem['GID'] == $gid) {
            //Insert new member
            $array[$ii]['members'][]=array(
                        'mid'=>$mid,
                        'mname'=>$mname);
            //Found!
            return 0;
        }
    }       
    //If not found, create new
    $array[]=array(
            'GID'=>$gid,
            'groupname'=>$groupname,
            'members'=>array(
                0=>array(
                    'mid'=>$mid,
                    'mname'=>$mname
                )
            )
    );

    return 0;
}

Php Array key =＆gt;价值搜寻

3 个答案: