垂直对齐div但保持水平位置不变
从数据库中我拉出一种Div的时间轴，带有一定的起点和某个终点。它们中的一些重叠，其中一些可以彼此相邻。
最终我想将它们一起滑动，以便尽可能紧凑，如下所示：
我怀疑如何应对这一挑战：通过服务器端（php）脚本或一些javascript浮动脚本。 或者当然是一种完全不同的方法
有人可以把我推向正确的方向吗？
修改:: 重要的是，正如时间轴一样，div的水平位置保持不变。因此，将所有div向左浮动或内联阻止它们是不可取的：）
我的数据库设置：
id | name | start | end
1 | a | 2 | 7
2 | b | 5 | 10
etc
10 个答案:
答案 0 :(得分：13)
<!DOCTYPE html>
<html>
<!--
Created using jsbin.com
Source can be edited via http://jsbin.com/udofoq/26/edit
-->
<head>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
<meta charset=utf-8 />
<title>JS Bin</title>
<style id="jsbin-css">div.blue {
background-color: #a4dcdf;
}
div.orange {
background-color: #fd9226;
}
div.green {
background-color: #88b37e;
}
div.yellow {
background-color: #d8d03f;
}
div.red {
background-color: #c16558;
}
div.grey {
background-color: #cdcdcd;
}
div.hours1{
top: 0px;
left: 10px;
width: 100px;//(110-10)
}
div.hours2{
top: 30px;
left: 80px;
width: 50px;
}
div.hours3{
top: 60px;
left: 120px;
width: 50px;
}
div.hours4{
top: 90px;
left: 5px;
width: 70px;
}
div.hours5{
top: 120px;
left: 110px;
width: 30px;
}
div.hours6{
top: 150px;
left: 130px;
width: 70px;
}
div.hours {
position: absolute;
height:20px;
color: white;
text-align:center;
border:white;
-webkit-box-shadow: 3px 3px 6px 2px rgba(00, 00, 00, .2);
box-shadow: 3px 3px 6px 2px rgba(00, 00, 00, .2);
font: bold 18px Arial, Helvetica, Geneva, sans-serif;
line-height:20px;
}
button{
position:static;
margin-top:200px;
}
.collapse,
.overlap1,
.overlap2,
.overlap3,
reset{
float:left;
}
</style></head>
<body>
<div class="hours hours1 orange">A</div>
<div class="hours hours2 yellow">B</div>
<div class="hours hours3 blue">C</div>
<div class="hours hours4 green">D</div>
<div class="hours hours5 red">E</div>
<div class="hours hours6 grey">F</div>
<button class="collapse">collapse</button>
<button class="overlap1">sort</button>
<button class="reset">reset</button>
<script>
data1 = [
[1, 10, 110],
[2, 80, 130],
[3, 120, 170],
[4, 5, 70],
[5, 110, 140],
[6, 130, 180]
];
//just added for console output not needed
var divider="";
for (var i = 0; i < 80; i++) {
divider += "_";
}
console.log(divider);
console.log("ORIGINAL ARRAY DATA1:", data1);
//add a column to keep track of the row, to start set it to row 1
data1 = $.each(data1, function(index, value) {
value[3] = 0;
});
console.log(divider);
console.log("ORIGINAL dataA WITH ADDED COLUMN:", data1);
function timelinesort(dataA){
//make a new Array to store the elements in with their new row number
var dataB = dataA.slice(0, 1);
console.log(divider);
console.log("INITIALIZED dataB WITH FIRST ELEMENT FROM dataA:", dataB);
//initialize the counter
var counter = 0;
console.log(divider);
console.log("INITIALIZED ROUNDS COUNTER:", counter);
dataA = $.map(dataA, function(value1, index1) {
//increment counter with 1
counter++;
console.log(divider);
console.log("INCREMENTED ROUNDS COUNTER:", counter);
dataA = $.map(dataA, function(value2, index2) {
//exclude comparing an element with itself
if(value2 != dataB[0]) {
//check to see if elements overlap
if(value2[2] >= dataB[0][1] && value2[1] <= dataB[0][2]) {
console.log(divider);
console.log("Round " + counter + " from dataA: [" + value2 + "] overlaps with " + dataB[0] + " incrementing row counter with 1");
//increment the value in column 3 (row counter) of the array
value2[3]++;
console.log(divider);
console.log("Now the dataA has changed to this:", dataA);
console.log("Meanwhile data1 has changed to this:", data1);
} else {
//if no overlap occurs check if the element is not already in the dataB array and if not check if it doesn't overlap with the existing elements
if($.inArray(value2, dataB) == -1) {
$.each(dataB, function(index3, value3) {
if(value3[2] >= value2[1] && value3[1] <= value2[2]) {
console.log(divider);
console.log("Round " + counter + " from dataA: [" + value2 + "] overlaps with " + value3 + " incrementing row counter with 1");
dataB.pop();
//increment the value in column 3 (row counter) of the array
value2[3]++;
} else {
//if no overlap occurs add the value to dataB
dataB.push(value2);
console.log(divider);
console.log("Added [" + value2 + "] to dataB and now dataB has changed to this: ", dataB);
}
});
} else {
dataB.push(value2);
console.log("Added [" + value2 + "] to dataB and now dataB has changed to this: ", dataB);
}
}
}
return [value2];
});
dataA = jQuery.grep(dataA, function(item) {
return jQuery.inArray(item, dataB) < 0;
});
if(dataA.length >= 1) {
dataB.unshift(dataA[0]);
dataB = dataB.splice(0, 1);
} else {
dataA = [];
}
});
}
//run the function
timelinesort(data1);
console.log(divider);
console.log("Finally the data1 has changed to this:", data1);
$(".collapse").click(function() {
$.each(data1, function(index, value) {
$("div.hours" + (index + 1)).animate({
"top": 0
}, "slow");
});
});
$(".overlap1").click(function() {
$.each(data1, function(index, value) {
console.log("div.hours" + (index + 1) + ":" + (value[3]) * 26);
$("div.hours" + (index + 1)).animate({
"top": (value[3]) * 26
}, "slow");
});
});
$(".reset").click(function() {
$.each(data1, function(index, value) {
$("div.hours" + (index + 1)).removeAttr('style');
});
});
</script>
</body>
</html>
我所做的是将所有行折叠到第一行，然后检查哪些行与该行的原件重叠，如果是，则在重叠的行上增加行号，然后转到下一行并重复该过程直到所有行元素整齐堆叠。
你仍然需要清理javascript / jquery的东西并把它放在一个很好的函数中。但作为概念的证据似乎有效
工作示例：
http://jsbin.com/udofoq/26/watch
或
答案 1 :(得分：5)
查看我的fiddle here。我认为它可以通过无限数量的块来满足您的需求。块数据取自HTML表。
JS：
var data = [],
rows = [],
chart = $('.wrapper-inner');
function DataItem(id, name, start, end){
this.id = id;
this.name = name;
this.start = start;
this.end = end;
}
$('.data tr').each(function() {
var $this = $(this),
item = new DataItem( $this.find('td:eq(0)').text(),
$this.find('td:eq(1)').text(),
$this.find('td:eq(2)').text(),
$this.find('td:eq(3)').text() );
data.push(item);
});
function addRow(){
var row = {
el : $('<div class="row"></div>').appendTo(chart),
positions: []
};
rows.push( row );
}
function checkRow(rowId, item){
var isRowAvailible = true;
for (var i = 0; i < +item.end - +item.start; i++){
if (rows[rowId].positions[+item.start + i]){
isRowAvailible = false;
break;
}
}
return isRowAvailible;
}
function markRowPositions(rowId, item){
for (var i = 0; i < item.end - item.start; i++){
rows[rowId].positions[+item.start + i] = true;
}
}
function addItems(){
for (var i = 0; i < data.length; i++){
(function(i){
setTimeout(function() {addItem(data[i])}, 100 * i);
})(i)
}
}
function addItem(item){
var rowToAdd = false,
itemEl = $('<div class="item"></div>');
for (var i = 0; i < rows.length; i++){
if ( checkRow(i, item) ){
rowToAdd = i;
break;
}
}
if (rowToAdd === false){
addRow();
rowToAdd = rows.length - 1;
}
rows[ rowToAdd ].el.append(itemEl);
console.log(itemEl.css('opacity'))
itemEl.css({
'left': item.start * 30,
'opacity' : 1,
'width': ( ( item.end - item.start ) * 30 ) - 2
});
markRowPositions(rowToAdd, item);
}
addItems();
答案 2 :(得分：2)
这是我能得到的最接近的。它接收一个json_string，解析它并生成结果。它完全是动态的。元素按照它们在json数组中的顺序淡出。
希望这会好起来：
HTML：
<div id="divHolder">
</div>
<input type="button" onclick="loadChart(json_data1);" value="Load Data 1" />
<input type="button" onclick="loadChart(json_data2);" value="Load Data 2" />
<input type="button" onclick="loadChart(json_data3);" value="Load Data 3" />
JS：
var json_data1 = '[{"id":1,"name":"A","start":2,"end":7},{"id":2,"name":"B","start":6,"end":9},{"id":3,"name":"C","start":8,"end":12},{"id":4,"name":"D","start":0,"end":5},{"id":5,"name":"E","start":7,"end":9}]';
var json_data2 = '[{"id":1,"name":"A","start":5,"end":7},{"id":2,"name":"B","start":6,"end":9},{"id":3,"name":"C","start":2,"end":6},{"id":4,"name":"D","start":2,"end":12},{"id":5,"name":"E","start":1,"end":9}, {"id":6,"name":"F","start":7,"end":11}, {"id":7,"name":"G","start":8,"end":12}, {"id":8,"name":"H","start":2,"end":4} ]';
var json_data3 = '[{"id":1,"name":"A","start":8,"end":12},{"id":2,"name":"B","start":4,"end":10},{"id":3,"name":"C","start":2,"end":4},{"id":4,"name":"D","start":0,"end":7},{"id":5,"name":"E","start":7,"end":11}, {"id":6,"name":"F","start":5,"end":7}]';
function loadChart(json_data){
var data = JSON.parse(json_data);
var divHolder = $('#divHolder');
var maxWidth = $(document).width() - 200;
var maxHeight = $(document).height();
$(divHolder).empty();
var maxEnd = 0;
var minStart = 0;
var widthUnit = 0;
$(data).each(function(){
if(this.end > maxEnd)
maxEnd = this.end;
if(this.start < minStart)
minStart = this.start;
});
widthUnit = maxWidth / (maxEnd - minStart) ;
var maxItemUnit = maxEnd;
var rows = new Array();
$(data).each(function(){
var added = false;
var currentObj = this;
var i;
for(i=0;i<rows.length;i++){
var toAdd = true;
//if(widthSum> maxItemUnit
var widthSum = 0;
$(rows[i]).each(function(){
widthSum += this.end - this.start;
if(this.end < currentObj.start || this.start > currentObj.end){
if((widthSum + currentObj.end - currentObj.start) < maxItemUnit)
toAdd = true;
}
else{
toAdd=false;
return false;
}
});
if(toAdd){
rows[i].push(currentObj);
added = true;
break;
}
}
if(!added){
rows[i] = new Array();
rows[i].push(currentObj);
}
});
$(rows).each(function(){
var current = this;
var divMain = $('<div></div>').css('display','block').css('width', maxWidth).css('height', 50)
$(current).each(function(){
var div = $('<div></div>');
div.addClass('item').html('<span class="item-content">'+this.name+'</span>');
var diff = this.end - this.start;
div.attr('id', this.id).css('opacity','0').css('left', widthUnit * this.start).width(widthUnit * diff);
if(diff < (maxItemUnit/3))
div.addClass('small');
else if (diff < (maxItemUnit/2))
div.addClass('medium');
else
div.addClass('large');
divMain.append(div);
});
$(divHolder).append(divMain);
});
var delayVar = 0;
$(data).each(function(){
$('#'+this.id).fadeTo(delayVar, 1);
delayVar += 300;
});
}
CSS：
.item{
display:inline-block;
position:absolute;
color: #ffffff;
border: 1px solid white;
}
.item-content{
margin-left: 50%;
}
.small{
background-color:#E66C3D;
}
.medium{
background-color:#DDD634;
}
.large{
background-color:#3EC043;
}
答案 3 :(得分：2)
你的问题听起来很幼稚，但如果需要以最优化的方式解决，它实际上包含了一些复杂的元素。
快速回答我可能会做什么来生成你的显示 -
- 使用提供的功能将行号添加到您的表
-
使用您的PHP代码生成DIV容器 每一行都有style =“display：block”
行内 -
生成适当大小的DIV（end-start * scale） with style =“display：inline-block; float：left; display：relative”和（EDIT :) 添加透明DIV元素以补偿您需要的空白区域。 （即从0开始，从结束到下一个DIV的开始）
-
在DIV元素
中添加名称字段
use mySchema;
drop procedure if exists tileItems;
DELIMITER $$
CREATE PROCEDURE tileItems ()
BEGIN
DECLARE p_id, p_start, p_end, p_row int;
DECLARE done INT DEFAULT FALSE;
DECLARE cur1 CURSOR FOR SELECT id, start, end FROM tasks order by start, id;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = TRUE;
drop temporary table if exists tiles;
create temporary table tiles (
row int(11) NOT NULL,
id int(11) NOT NULL,
end int(11) NOT NULL
);
-- row field will indicates the row number the task should apear
OPEN cur1;
next_task: LOOP
FETCH cur1 into p_id, p_start, p_end;
IF (done) THEN
LEAVE next_task;
END IF;
select min(row) from (select row, max(end) me from tiles t2 group by row) t1
where me < p_start
into p_row;
-- take care of row numbering
IF (p_row IS NULL) then
select max(row) from tiles
into p_row;
IF (p_row IS NULL) then
SET p_row = 0;
END IF;
SET p_row=p_row+1;
END IF;
insert into tiles (id, row, end)
values (p_id,p_row,p_end);
END LOOP;
-- CLOSE cur1;
-- here is your output, on the PHP/.Net code you should loop on the row
select tasks.*, tiles.row from tasks
inner join tiles
on tasks.id = tiles.id
order by tiles.row, tasks.start;
END $$
DELIMITER ;
这是我用来检查它的表 -
CREATE TABLE `tasks` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(50) COLLATE utf8_unicode_ci NOT NULL,
`start` int(11) NOT NULL,
`end` int(11) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=11 ;
INSERT INTO `tasks` (`id`, `name`, `start`, `end`) VALUES
(1, 'A', 2, 6),
(2, 'B', 5, 7),
(3, 'C', 8, 10),
(4, 'D', 1, 5),
(5, 'E', 6, 7);
关于优化的几句话（我最喜欢的科目之一:) - 在此代码中没有优化，这意味着任务将分配给第一个可用行。 为了尽可能减少行数（但需要一些时间）来创建一个使用Heuristic方法来解决这个问题的函数。
输出：
id name start end row
4 D 1 5 1
5 E 6 7 1
3 C 8 10 1
1 A 2 6 2
2 B 5 7 3
答案 4 :(得分：1)
查看jQuery.Gantt插件
http://taitems.github.com/jQuery.Gantt/
答案 5 :(得分：1)
试试这个：
function collides($block1,$block2) {
return ( ($block1['start'] >= $block2['start']) and ($block1['start'] < $block2['end']) ) or
( ($block1['end'] > $block2['start']) and ($block1['end'] <= $block2['end']) ) or
( ($block1['start'] <= $block2['start']) and ($block1['end'] => $block2['end']) );
}
function FitsInRow ($row,$block) {
$fits=true;
foreach ($row as $block1)
if (collides($block,$block1))
$fits=false;
return $fits;
}
$rows=array();
// $blocks like that:
$blocks[0]['start']=0;
$blocks[0]['end']=10;
$blocks[0]['name']='A';
$blocks[0]['color']='#F00';
$blocks[1]['start']=5;
$blocks[1]['end']=20;
$blocks[1]['name']='B';
$blocks[1]['color']='#0F0';
//etc
foreach ($blocks as $block) {
$i=0;
while (isset($rows[$i]) && !FitsInRow($block,$rows[$i]))
$i++;
$rows[$i][]=$block;
}
echo '<div class="block_outer" style="height: '.(count($rows)*20).'px;">';
foreach ($rows as $nr=>$row)
foreach ($row as $block)
echo '<div class="block" style="left:'.$block['start'].'px; width:'.($block['end']-$block['start']).'px; top:'.($nr*20).'px; background-color:'.$block['color'].';">'.$block['name'].'</div>';
echo '</div>';
使用以下css：
.block {
position:absolute;
height:16px;
/* ... */
}
.block_outer {
position:relative;
width:100%;
overflow:auto;
}
我还没有测试过它。
编辑：我更改了名称，使其符合上述数据库设置。
另一个编辑：现在我添加了外部div，因此内部div的绝对位置不会破坏页面布局。
答案 6 :(得分：0)
您是否尝试使用CSS显示inline？
div.inline {
display: inline-block;
}
你的div有哪个类inline。
答案 7 :(得分：0)
这看起来像是一个很好的案例：
div.hours {
position: absolute;
top: 100px;
left: 155px;
width: 100px;
}
当然，用您的值替换100px，155px，100px。
或者，您可以尝试使用条形图，内部块，以及位置：相对和左/宽度值。
答案 8 :(得分：0)
没有简单的方法可以执行此操作，您需要使用position: absolute并计算在页面中可见事件的位置，例如：一天全天有10px height和{{1我们需要在10px width添加一个事件，然后检查day 1或是否有一个事件，如果它是空的那么line 1 is empty，否则put the event there直到它被分配在一条线上。
答案 9 :(得分：0)
您需要查看topological sorting算法，并自行实现（在php或JavaScript中），或尝试找到合适的现成实现。
CSS属性和表格布局都不会自动完美地解决这个问题。
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