Question

我有这个查询

SELECT
patientid, 
practiceid,
visitcount
  FROM
    (       
        SELECT 
          patientid, 
          practiceid ,
          visitcount,
          RANK() OVER (PARTITION BY patientid ORDER BY visitcount DESC) as Rank
        FROM
            aco.patients_practices
    WHERE practiceid in (select id from aco.practices where parentaco = 30982) and isprimary = 0
    ) AS A
WHERE
    Rank = 1

以下是一些结果

patientid     practiceid       visitcount
157053           30976            6
158463           30974            2
187772           30973            15
187797           30971            1
187797           30975            1

请注意，最后2个patientid是相同的，并且具有相同的visitcount，因此具有相同的等级。如何从输出中完全忽略具有相同等级的这些记录？

谢谢！

Answer 1

您可以通过计算它们并将它们包含在where子句中来消除它们。以下查询使用类似于等级的逻辑来计算它们 - 患者具有相同访问量的次数：

SELECT patientid, practiceid, visitcount
FROM (SELECT patientid, practiceid, visitcount,
             RANK() OVER (PARTITION BY patientid ORDER BY visitcount DESC) as Rank,
             COUNT(*) over (PARTITION by patientid, visitcount) as RankCount
      FROM aco.patients_practices
      WHERE practiceid in (select id from aco.practices where parentaco = 30982) and isprimary = 0
     ) A
WHERE Rank = 1 and RankCount = 1

我注意到，最后两个记录中的practiceid是不同的。但是，你似乎仍然希望消除两者。

RANK（）忽略了同等级别

1 个答案: