我有一个名为 my_data 的表格,如下所示:
+-------+-------+--------+
| attr1 | attr2 | att3 |
+-------+-------+--------+
| 3 | 1 | 1 |
| 4 | 2 | 1 |
| 5 | 3 | 1 |
| 3 | 6 | 1 |
| 3 | 7 | 1 |
| 3 | 8 | 1 |
| 8 | 8 | 1 |
| 9 | 7 | 1 |
| 3 | 9 | 1 |
+-------+-------+--------+
我需要这样做:
UPDATE my_data
SET
attr3 = 0
WHERE (attr1, attr2) IN (SELECT attr1, attr2 FROM my_data GROUP BY attr1);
在mysql中,update不能与select语句一起使用。还有其他办法吗?
答案 0 :(得分:0)
您可以使用内部查询加入my_data并更新attr3,如下所示:
UPDATE my_data a
JOIN (SELECT attr1, attr2 FROM my_data GROUP BY attr1) b
ON a.attr1 = b.attr1 AND a.attr2 = b.attr1
SET a.attr3 = 0;
答案 1 :(得分:0)
盯着上述数据,我猜您希望将attr3
更新为任何有attr1
个attr2
个attr2
的{{1}}。
如果是这种情况,查询应计算有多少UPDATE
(SELECT attr1,COUNT(attr2) attr2count FROM my_data
GROUP BY attr1 HAVING COUNT(attr2) > 1) A
INNER JOIN my_data B USING (attr1)
SET B.attr3 = 0;
:
SELECT ... GROUP BY ... HAVING
我之所以选择SELECT attr1, attr2 FROM my_data GROUP BY attr1
是因为attr2
attr1
中的GROUP BY
只是attr1=3
重复的数字之一,因此更加稳定。
根据attr2
上的MySQL文档,there is no guarantee which value mysql chooses when using GROUP BY
。
如果您确定要UPDATE
(SELECT attr1,MIN(attr2) attr2 FROM my_data
GROUP BY attr1 HAVING COUNT(attr2) > 1) A
INNER JOIN my_data B USING (attr1,attr2)
SET B.attr3 = 0;
确定具有最小drop database if exists clickit;
create database clickit;
use clickit
create table my_data (attr1 INT,attr2 INT,attr3 INT);
insert into my_data values
(3,1,1),(4,2,1),(5,3,1),
(3,6,1),(3,7,1),(3,8,1),
(8,8,1),(9,7,1),(3,9,1);
的行是将attr3设置为0,那么您的问题的答案将是:
mysql> drop database if exists clickit;
Query OK, 1 row affected (0.12 sec)
mysql> create database clickit;
Query OK, 1 row affected (0.00 sec)
mysql> use clickit
Database changed
mysql> create table my_data (attr1 INT,attr2 INT,attr3 INT);
Query OK, 0 rows affected (0.07 sec)
mysql> insert into my_data values
-> (3,1,1),(4,2,1),(5,3,1),
-> (3,6,1),(3,7,1),(3,8,1),
-> (8,8,1),(9,7,1),(3,9,1);
Query OK, 9 rows affected (0.05 sec)
Records: 9 Duplicates: 0 Warnings: 0
mysql> select * from my_data;
+-------+-------+-------+
| attr1 | attr2 | attr3 |
+-------+-------+-------+
| 3 | 1 | 1 |
| 4 | 2 | 1 |
| 5 | 3 | 1 |
| 3 | 6 | 1 |
| 3 | 7 | 1 |
| 3 | 8 | 1 |
| 8 | 8 | 1 |
| 9 | 7 | 1 |
| 3 | 9 | 1 |
+-------+-------+-------+
9 rows in set (0.00 sec)
mysql>
让我们测试它们:
首先是样本数据:
mysql> UPDATE
-> (SELECT attr1,COUNT(attr2) attr2count FROM my_data
-> GROUP BY attr1 HAVING COUNT(attr2) > 1) A
-> INNER JOIN my_data B USING (attr1)
-> SET B.attr3 = 0;
Query OK, 5 rows affected (0.10 sec)
Rows matched: 5 Changed: 5 Warnings: 0
mysql> select * from my_data;
+-------+-------+-------+
| attr1 | attr2 | attr3 |
+-------+-------+-------+
| 3 | 1 | 0 |
| 4 | 2 | 1 |
| 5 | 3 | 1 |
| 3 | 6 | 0 |
| 3 | 7 | 0 |
| 3 | 8 | 0 |
| 8 | 8 | 1 |
| 9 | 7 | 1 |
| 3 | 9 | 0 |
+-------+-------+-------+
9 rows in set (0.00 sec)
mysql>
以下是加载的示例数据:
mysql> drop database if exists clickit;
Query OK, 1 row affected (0.04 sec)
mysql> create database clickit;
Query OK, 1 row affected (0.00 sec)
mysql> use clickit
Database changed
mysql> create table my_data (attr1 INT,attr2 INT,attr3 INT
Query OK, 0 rows affected (0.07 sec)
mysql> insert into my_data values
-> (3,1,1),(4,2,1),(5,3,1),
-> (3,6,1),(3,7,1),(3,8,1),
-> (8,8,1),(9,7,1),(3,9,1);
Query OK, 9 rows affected (0.05 sec)
Records: 9 Duplicates: 0 Warnings: 0
mysql> select * from my_data;
+-------+-------+-------+
| attr1 | attr2 | attr3 |
+-------+-------+-------+
| 3 | 1 | 1 |
| 4 | 2 | 1 |
| 5 | 3 | 1 |
| 3 | 6 | 1 |
| 3 | 7 | 1 |
| 3 | 8 | 1 |
| 8 | 8 | 1 |
| 9 | 7 | 1 |
| 3 | 9 | 1 |
+-------+-------+-------+
9 rows in set (0.00 sec)
mysql> UPDATE
-> (SELECT attr1,MIN(attr2) attr2 FROM my_data
-> GROUP BY attr1 HAVING COUNT(attr2) > 1) A
-> INNER JOIN my_data B USING (attr1,attr2)
-> SET B.attr3 = 0;
Query OK, 1 row affected (0.06 sec)
Rows matched: 1 Changed: 1 Warnings: 0
mysql> select * from my_data;
+-------+-------+-------+
| attr1 | attr2 | attr3 |
+-------+-------+-------+
| 3 | 1 | 0 |
| 4 | 2 | 1 |
| 5 | 3 | 1 |
| 3 | 6 | 1 |
| 3 | 7 | 1 |
| 3 | 8 | 1 |
| 8 | 8 | 1 |
| 9 | 7 | 1 |
| 3 | 9 | 1 |
+-------+-------+-------+
9 rows in set (0.00 sec)
mysql>
这是我建议的第一个查询:
{{1}}
对于有多行的attr1,第一个将attr3更改为0
让我们重新加载示例并运行第二个查询:
{{1}}
试一试!!!