我正在创建一个谷歌地图,以便在印度展示品牌的商店位置......
我已经存储了完整的地址,包含纬度和数据。我的SQL服务器数据库中的经度...
在这里,我可以从数据库中获取地址并显示在我的网页中,但我坚持使用,在谷歌地图上映射地址......
这里我保留了一个文本框,以便用户输入他的州/城市/任何位置名称,然后点击搜索按钮,然后我必须用标记在地图上标记相应的商店位置..
这是我的googgle map代码......
<script type="text/javascript">
var infowindow = null;
function initialize() {
//var centerMap = new google.maps.LatLng(13.040547,80.230805);
var centerMap = new google.maps.LatLng(12.264864, 77.937012);
var myOptions = {
zoom: 7,
center: centerMap,
mapTypeId: google.maps.MapTypeId.ROADMAP
}
var map = new google.maps.Map(document.getElementById("map"), myOptions);
setMarkers(map, sites);
infowindow = new google.maps.InfoWindow({ });
}
//var sites = '<%=TextBox1.Text%>'
//alert(sites);
//[
//// ['Ambattur', 13.119438,80.148182, 4, 'Ambattur, Chennai, Tamil Nadu, India, 600031'],['Avadi', 13.124453,80.101662, 1, 'Avadi, Tamil Nadu, India, 600017'], ['Jayanagar', 12.928945,77.590599, 1, 'Jayanagar, Bangalore, Karnataka, India, 560041'],['Indira Nagar', 12.973697,77.641325, 1, 'Indira Nagar, Bangalore, Karnataka, India, 560038'],['TamilNadu', 11.415418,78.662109, 1, 'TamilNadu, India, 600017']
//];
function setMarkers(map, markers) {
for (var i = 0; i < markers.length; i++) {
var sites = markers[i];
var siteLatLng = new google.maps.LatLng(sites[1], sites[2]);
var marker = new google.maps.Marker({
position: siteLatLng,
map: map,
icon: new google.maps.MarkerImage(
'Images/R.png ',
null, null, new google.maps.Point(0, 42)),
title: sites[0],
zIndex: sites[3],
html: sites[4]
});
google.maps.event.addListener(marker, "click", function () {
infowindow.setContent(this.html);
infowindow.open(map, this);
});
}
}
</script>
这里,我有网站变量,所以我可以在地图上映射我的位置,
但是我需要从数据库中映射它们......
任何帮助将不胜感激......
感谢 shameer ali shaik
答案 0 :(得分:0)
乍一看,您的代码似乎没问题。但是我的代码对我来说非常好,可能会对你有所帮助。
myLatlng = new google.maps.LatLng(32.54681317351514,15.1171875);
map = new google.maps.Map(document.getElementById(&#34; gmap&#34;),{mapTypeId:google.maps.MapTypeId.ROADMAP,zoom:2,center:myLatlng});
/* loop which plot the markers on the map*/
// record[i] holds lat&lang in this format'32.54681317351514, 15.1171875'
var points=record[i].geo_location.split(',');
marker = new google.maps.Marker({
position: new google.maps.LatLng(points[0],points[1]),
draggable: false,
map: map
});
答案 1 :(得分:0)
Guruparan Giritharan ..
正如我在问题中所说,我希望在印度各地找到商店。&amp;疼痛的细节将存储在数据库中.. 现在,我能够获得商店的详细信息和用你的代码在地图上标出他们的位置.. 早些时候它对pincode工作正常,从某种意义上说,如果你在搜索框中提供密码,它将检索相应的 商店详情..
现在,根据我的代码,在我对你的博客帖子的回复中,我只能在文本框中输入字符串值。这里我需要为数值(pincode)实现它,
这是我的更新面板和计时器点击事件的代码..
protected void UpdatePanel1_Load(object sender, EventArgs e)
{
//Linq is used to load the table to the code
DataClassesDataContext data = new DataClassesDataContext();
//Select all from the table
//List<addressmap> lst = (from u in data.addressmaps select u).ToList();
List<addressmap> lst = (from u in data.addressmaps where u.StoreLocation == TxtSearch.Text || u.StoreCity == TxtSearch.Text || u.StoreState == TxtSearch.Text || u.StoreCountry == TxtSearch.Text select u).ToList();
//add the table contents to the javascript array so that new locations will be loaded
foreach (addressmap item in lst)
{
ScriptManager.RegisterArrayDeclaration(UpdatePanel1, "infoarray", "'" + item.StoreAddress.ToString() + "'");
ScriptManager.RegisterArrayDeclaration(UpdatePanel1, "lonarray", item.StoreLongitude.ToString());
ScriptManager.RegisterArrayDeclaration(UpdatePanel1, "latarray", item.StoreLatitude.ToString());
ScriptManager.RegisterArrayDeclaration(UpdatePanel1, "bounce", item.StoreBounce.ToString());
}
}
protected void Timer1_Tick(object sender, EventArgs e)
{
//update the update panel every 10 seconds
UpdatePanel1.Update();
}
这里在select语句中,我还需要pincode ..
任何帮助都会感激不尽..