这个问题可能看似重复,我已经尝试了所有建议的解决方案但是徒劳,我想使用此代码重定向python脚本输出:
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo.FileName = "python.exe";
proc.StartInfo.Arguments = Application.StartupPath.Replace("\\bin\\Debug", "") + "\\scripts\\test.py";
proc.OutputDataReceived += OutputDataReceived;
proc.ErrorDataReceived += ErrorDataReceived;
proc.StartInfo.RedirectStandardOutput = true;
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.CreateNoWindow = true;
proc.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
proc.Start();
//proc.WaitForExit();
StringBuilder q = new StringBuilder();
while (!proc.HasExited)
{
q.Append(proc.StandardOutput.ReadToEnd());
}
string r = q.ToString();
r = proc.StandardOutput.ReadToEnd();
MessageBox.Show(r);
}
private void OutputDataReceived(object sender, DataReceivedEventArgs args)
{
//textOutput.Text += args.Data;
MessageBox.Show(args.Data);
}
python脚本包含print "hello test"
我尝试了非缓冲输出但是徒劳无功。
请帮助。
我正在使用VS 2010 .NET 4.0,Python 2.7,winXP sp3。
答案 0 :(得分:2)
尝试创建StreamReader实例而不是StringBuilder。 这段代码对我很有用:
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo.FileName = "ping.exe";
proc.StartInfo.Arguments = "8.8.8.8";
proc.StartInfo.RedirectStandardOutput = true;
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.CreateNoWindow = true;
proc.StartInfo.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
proc.Start();
StreamReader q = proc.StandardOutput;
while (!proc.HasExited)
Console.WriteLine(q.ReadLine());
Console.ReadKey();