Question

我对android编程很新，而且我已经坚持使用这段代码了好几天了。我得到的错误是“无效使用SingleClientConnManager：连接仍然分配。” - 我理解为什么会这样，但不知道如何解决它。我正在处理的代码：

protected class loader extends AsyncTask<String, Void, String> {

    protected void onPreExecute()
    {
        nameValuePairs = new ArrayList<NameValuePair>(1);
        nameValuePairs.add(new BasicNameValuePair("username_in",username.getText().toString().trim()));
        nameValuePairs.add(new BasicNameValuePair("password_in",password.getText().toString().trim()));
        tv.setText("Started onPreExecute");

    }

    @Override
    protected String doInBackground(String... params) {

        try {
            httpclient = new DefaultHttpClient();
            httppost = new HttpPost("http://www.myurl.com/phplogin.php");

            httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

            response=httpclient.execute(httppost);

            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            final String response = httpclient.execute(httppost, responseHandler);

            //Toast.makeText(MainActivity.this,response, Toast.LENGTH_LONG).show();
            if(response.equalsIgnoreCase("User Found"))
            {
                httppost.getEntity().consumeContent();
                //startActivity(new Intent("com.example.obligatorisk.BROWSER"));
            }
        }
        catch(IOException e){
            e.printStackTrace();
        }
        return null;
    }

    protected void onPostExecute(String result)
    {
        tv.setText("Reached onPostExecute");
    }
    // TODO Auto-generated method stub      
}

完整错误日志：

10-18 14:30:52.134: W/SingleClientConnManager(3940): Invalid use of SingleClientConnManager: connection still allocated.
10-18 14:30:52.134: W/SingleClientConnManager(3940): Make sure to release the connection before allocating another one.
10-18 14:30:52.414: W/System.err(3940): org.apache.http.client.HttpResponseException: Internal Server Error
10-18 14:30:52.414: W/System.err(3940):     at org.apache.http.impl.client.BasicResponseHandler.handleResponse(BasicResponseHandler.java:71)
10-18 14:30:52.424: W/System.err(3940):     at org.apache.http.impl.client.BasicResponseHandler.handleResponse(BasicResponseHandler.java:59)
10-18 14:30:52.424: W/System.err(3940):     at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:657)
10-18 14:30:52.424: W/System.err(3940):     at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:627)
10-18 14:30:52.424: W/System.err(3940):     at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:616)
10-18 14:30:52.424: W/System.err(3940):     at com.example.obligatorisk.MainActivity$loader.doInBackground(MainActivity.java:113)
10-18 14:30:52.424: W/System.err(3940):     at com.example.obligatorisk.MainActivity$loader.doInBackground(MainActivity.java:1)
10-18 14:30:52.424: W/System.err(3940):     at android.os.AsyncTask$2.call(AsyncTask.java:287)
10-18 14:30:52.434: W/System.err(3940):     at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:305)
10-18 14:30:52.434: W/System.err(3940):     at java.util.concurrent.FutureTask.run(FutureTask.java:137)
10-18 14:30:52.434: W/System.err(3940):     at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230)
10-18 14:30:52.443: W/System.err(3940):     at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)
10-18 14:30:52.443: W/System.err(3940):     at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)
10-18 14:30:52.443: W/System.err(3940):     at java.lang.Thread.run(Thread.java:856)

该项目背后的想法是为应用程序创建登录功能。

我一直试图在网上找到解决方案和帮助，但无论我尝试什么，我都无法弄明白。我真的希望有人能抽出时间来帮助我。如果您需要有关代码，错误等的更多信息，请告诉我，我将添加它。

谢谢，感谢所有早些时候帮助过我的人。

Answer 1

如果响应等于“User Found”，则只执行httppost.getEntity().consumeContent();。无论如何，您必须完全使用内容。将该方法调用移到条件之外。

    ResponseHandler<String> responseHandler = new BasicResponseHandler();
    final String response = httpclient.execute(httppost, responseHandler);

    //Toast.makeText(MainActivity.this,response, Toast.LENGTH_LONG).show();
    if(response.equalsIgnoreCase("User Found"))
    {
        //startActivity(new Intent("com.example.obligatorisk.BROWSER"));
    }
    httppost.getEntity().consumeContent();

使用SingleClientConnManager和AsyncTask时出错

1 个答案: