Question

我的数据库如下所示：

Book,Chapter,Verse,Scripture
"1","1","1","1text1"
"1","1","2","1text2"
"1","1","3","1text3"
"1","1","4","1text4"
"1","2","1","2text1"
"1","2","2","2text2"
"1","2","3","2text3"

我想选择1,1,1到1,2,3的所有行。

但是我当前的查询不会返回第1,1,4行，因为4大于3。

SELECT * FROM my_table WHERE 
Book >= 1 AND Book <= 1 AND 
Chapter >= 1 AND Chapter <= 2 AND
Verse >= 1 AND Verse <= 3

Answer 1

MySQL也支持row constructors。如果您想要（例如）1 1：3到1 2：2，请使用：

SELECT * FROM bible
    WHERE (1,1,3) <= (book, chapter, verse) AND (book, chapter, verse) <= (1,2,2)

58 1：3到62 4：2，

SELECT * FROM bible
    WHERE (58,1,3) <= (book, chapter, verse) AND (book, chapter, verse) <= (62,4,2)

58 1：4将包括在内，59 1：1和60 10:10，但不包括62 5：1。

我找不到太多文档，但是MySQL遵循自SQL-92以来为行比较设置的行为（注意：链接是草稿版本），特别是第8.2节“一般规则”7）：< / p>

设R ^x和R ^y是比较谓词的两个行值构造函数，并且让R ^x _i和R ^y _i是R ^x和R ^y的第i行值构造元素，分别。 “R ^x [comp op] R ^y”为真，假或未知如下：
  [...]
  c）当且仅当R ^x _i = R <时，“R ^x＆lt; R ^y”为真对于所有i ^y _i n和R ^x _n＆lt;对于某些n，R ^y _n。

d）当且仅当R ^x _i时，“R ^x> R ^y”为真所有i <= R ^y _i n和R ^x _n＆gt;对于某些n，R ^y _n。

e）当且仅当R ^x = R ^{y <时，“R ^x＆lt; = R ^y”为真/ sup>或R ^x＆lt; [R ^ý}

f）当且仅当R ^x = R ^{y <时，“R ^x> = R ^y”为真/ sup>或R ^x＆gt; [R ^ý}

第9.2节Joe Celko的SQL For Smarties（链接到第3版，但在早期版本中存在相同的主题）中讨论了行比较。

Answer 2

数据模型中缺少的是Book，Chapter和verse与层次结构相关的事实。

如果对于每个条目，您还存储了将书章和诗节组合在一起的单个数据项，搜索给定范围只需要一个简单的BETWEEN运算符。

让我们说你知道没有一本书包含超过99章，而且没有章节包含999多节经文。你可以计算（Book * 100 + Chapter）* 1000 + Verse 对于存储的每个项目，并将其存储在单独的列中。（是的，我知道这是多余的）。

然后你可以在（1 * 100 + 1）* 1000 + 1和（1 * 100 + 2）* 1000 + 5之间搜索该列找到从1,1,1到1,2,5的所有内容。

Answer 3

您需要使用OR语句。

SELECT * FROM my_table WHERE 
(Book = 1 AND 
Chapter BETWEEN 1 AND 2
Verse BETWEEN 1 AND 2)
OR
(/* THE OTHER STATEMENT */)
OR
(/* THE OTHER STATEMENT */)

修改

如果您使用BETWEEN运算符

，则更加清晰

Answer 4

这就是我在书中选择范围时所提出的。如果我想从1,1,3到1,7,2

SELECT * FROM Bible WHERE Book = 1 AND Chapter = 1 AND Verse >= 3
UNION
SELECT * FROM Bible WHERE Book = 1 AND Chapter >1 AND Chapter <7
UNION
SELECT * FROM Bible WHERE Book = 1 AND Chapter = 7 AND Verse <=2

选择书籍范围：58,1,3到62,4,2

SELECT * FROM Bible WHERE Book = 58 AND Chapter = 1 AND Verse >= 3
UNION
SELECT * FROM Bible WHERE Book = 58 AND Chapter > 1
UNION
SELECT * FROM Bible WHERE Book > 58 AND Book < 62
UNION
SELECT * FROM Bible WHERE Book = 62 AND Chapter < 4
UNION
SELECT * FROM Bible WHERE Book = 62 AND Chapter = 4 AND Verse <=2

Answer 5

我能想到的唯一解决方案是添加一个额外的索引列：

ALTER TABLE my_table ADD VerseIndex CHAR(10) NOT NULL, INDEX(VerseIndex(4));

UPDATE my_table SET VerseIndex = CONCAT(
                                        LPAD(Book, 2, '0'),
                                        '-', LPAD(Chapter, 3, '0'),
                                        '-', LPAD(Verse, 3, '0')
                                        );

现在，您的表中应该有一个额外的列，文本值为“ - ”，mysql可以按字母顺序搜索，为您提供精确的范围：

# find book 2 chapter 4 v 3 through to book 3 chapter 1 v 1 (inclusive)
SELECT * FROM my_table WHERE VerseIndex BETWEEN '02-004-003' AND '03-001-001' ORDER BY VerseIndex;

# find book 5 chapter 4 (whole chapter) through to book 7 end of chapter 9
SELECT * FROM my_table WHERE VerseIndex BETWEEN '05-004-000' AND '07-009-999' ORDER BY VerseIndex;

使用3个不同的索引选择行范围

5 个答案:

修改