TWRequest代码有效但显示速度很慢?

时间:2012-11-30 19:42:21

标签: xcode twitter nsjsonserialization twrequest acaccount

我正在使用TWrequest在桌面视图中显示我的推特列表。以下代码有效。问题是更新表格非常慢。我正在对请求响应进行NSlogging(发生得非常快),我也循环遍历每个列表并将列表'name'添加到一个数组中(这也很快发生在< 1s)。但由于一些莫名其妙的原因,该表大约需要4秒左右才能更新。

为什么表重新加载需要这么长时间?问题是没有解析响应(因为我可以看到nslog这很快发生),它需要很长时间才能显示在表中?非常感谢帮助!

-(IBAction)getLists{

    //  First, we need to obtain the account instance for the user's Twitter account
    ACAccountStore *store = [[ACAccountStore alloc] init];

    ACAccountType *twitterAccountType = [store accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter];

    //  Request permission from the user to access the available Twitter accounts
    [store requestAccessToAccountsWithType:twitterAccountType withCompletionHandler:^(BOOL granted, NSError *error) {

        if (!granted) {
            // The user rejected your request
            NSLog(@"User rejected access to the account.");
        }
        else {

            // Grab the available accounts
            twitterAccounts = [store accountsWithAccountType:twitterAccountType];

            if ([twitterAccounts count] > 0) {

                // Use the first account for simplicity
                ACAccount *account = [twitterAccounts objectAtIndex:0];

                // Now make an authenticated request to our endpoint
                NSMutableDictionary *params = [[NSMutableDictionary alloc] init];
                //[params setObject:@"1" forKey:@"include_entities"];

                //  The endpoint that we wish to call
                NSURL *url = [NSURL URLWithString:@"http://api.twitter.com/1.1/lists/list.json"];

                //  Build the request with our parameter
                TWRequest *request = [[TWRequest alloc] initWithURL:url parameters:params requestMethod:TWRequestMethodGET];

                // Attach the account object to this request
                [request setAccount:account];

                [request performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) {

                    if (!responseData) {
                        // inspect the contents of error
                        NSLog(@"error = %@", error);
                    }
                    else {

                        NSError *jsonError;

                        NSArray *timeline = [NSJSONSerialization JSONObjectWithData:responseData options:NSJSONReadingMutableLeaves error:&jsonError];

                        if (timeline) {

                            // at this point, we have an object that we can parse
                            NSLog(@"timeline = %@", timeline);

                            for (NSDictionary *element in timeline) {

                                NSString *listName = [element valueForKey:@"name"];
                                [listsArray addObject:listName];

                            }

                            [listsTable reloadData];

                        }

                        else {
                            // inspect the contents of jsonError
                            NSLog(@"jsonerror = %@", jsonError);
                        }

                    }
                }];

            } 
        } 
    }];

}

1 个答案:

答案 0 :(得分:5)

对不起,刚发现这篇文章。如果您还没有找到解决方案,希望这会有所帮助。

我相信可以在任何线程上调用performRequestWithHandler,因此应该将UI更改分派到主线程。

dispatch_async(dispatch_get_main_queue(), ^{
//update UI here
});

或者在重新加载表格数据的情况下,您可以使用:

[self.tableView performSelectorOnMainThread:@selector(reloadData) withObject:nil    waitUntilDone:NO];