我正在尝试让搜索显示控制器工作,并且遇到了这个错误:
2012-11-30 14:48:19.903 searchstory [5812:c07] - [__ NSCFConstantString objectAtIndex:]:无法识别的选择器发送到实例0x3141c 2012-11-30 14:48:19.904 searchstory [5812:c07] *终止app到期 未捕获的异常'NSInvalidArgumentException',原因: ' - [__ NSCFConstantString objectAtIndex:]:发送到无法识别的选择器 实例0x3141c' * 第一次抛出调用堆栈:(0x1cc0012 0x10fde7e 0x1d4b4bd 0x1cafbbc 0x1caf94e 0x2901d 0xfff4b 0x10001f 0xe880b 0xe6ec2 0xf1d51 0xfa3ad 0x102454 0x329635 0x32c0de 0x27bd85 0x1111705 0x48873 0x10a2ce 0x109960 0x11678c 0x120bf6 0xbbedc9 0x1d1a0c5 0x1c74efa 0xaf3482 0x359509e 0x26e426a 0x2b1f78c 0x2b22588 0x356fd12 0x356fe4a 0x35705c0 0x35703b8 0x356f904 0x295eeab 0x295ee13 0x3542596 0x356ebcc 0x2b1cac6 0x2b1bd56 0x2b4f320 0x31a9afd 0x2b45e66 0x2b470aa 0x2b4501e 0x31a81aa 0x2b5f491 0x2b4f0ca 0x2b2303e 0x27207fb 0x11116b0 0x358aed0 0x275f384 0x27614df 0x206254 0x1c904f 0x1ca3b8 0x1c8f5e 0x1d312d 0x5643b 0x153e05 0x153e05 0x153e05 0x153e05 0x153e05 0x153e05 0x153e05 0x153e05 0x153e05 0x56495 0x55e66 0x5624b 0x47cf8 0x1c1bdf9 0x1c1bad0 0x1c35bf5 0x1c35962 0x1c66bb6 0x1c65f44 0x1c65e1b 0x1c1a7e3 0x1c1a668 0x4565c 0x1c8d 0x1bb5)libc ++ abi.dylib:终止调用throw a 例外
我一直在尝试使代码尝试使用它。我用于搜索和表格的代码是:
- (UITableViewCell *)tableView:(UITableView *)tableView
cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
NSString *contentForThisRow = nil;
if (tableView == [[self searchDisplayController] searchResultsTableView])
contentForThisRow = [[[[self searchResults]objectAtIndex:indexPath.section] objectAtIndex:indexPath.row] objectForKey:@"name"];
else
contentForThisRow = [[[[self contentsList] objectAtIndex:indexPath.section] objectAtIndex:indexPath.row] objectForKey:@"name"];
static NSString *CellIdentifier = @"stoneCell";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if (cell == nil)
{
cell.textLabel.text = [[[self.contentsList objectAtIndex:indexPath.section] objectAtIndex:indexPath.row] objectForKey:@"name"];
[cell setAccessoryType:UITableViewCellAccessoryDisclosureIndicator];
// Do anything that should be the same on EACH cell here. Fonts, colors, etc.
}
// Do anything that COULD be different on each cell here. Text, images, etc.
[[cell textLabel] setText:contentForThisRow];
return cell;
}
- (void)handleSearchForTerm:(NSString *)searchTerm
{
[self setSavedSearchTerm:searchTerm];
if ([self searchResults] == nil)
{
NSMutableArray *array = [[NSMutableArray alloc] init];
[self setSearchResults:array];
}
[[self searchResults] removeAllObjects];
if ([[self savedSearchTerm] length] != 0)
{
for (NSMutableArray *array in contentsList)
{
for (NSDictionary* dictionary in array)
{
NSString *currentstring = [dictionary objectForKey:@"name"];
NSRange r = [currentstring rangeOfString:searchTerm options:NSCaseInsensitiveSearch];
if (r.location != NSNotFound) {
[[self searchResults] addObject:currentstring];
}
}
}
}
}
谁能告诉我哪里出错了?我假设它是objectAtIndex但是哪一个?
修订版 - 我试图改变我的代码一点点,现在我正在进行搜索工作,但原始视图上没有单元格标题,搜索结果在每个标题下重复!我现在的代码是:
- (void)handleSearchForTerm:(NSString *)searchTerm
{
[self setSavedSearchTerm:searchTerm];
if ([self searchResults] == nil)
{
NSMutableArray *array = [[NSMutableArray alloc] init];
[self setSearchResults:array];
}
[[self searchResults] removeAllObjects];
if ([[self savedSearchTerm] length] != 0)
{
for (NSMutableArray *array in contentsList)
{
for (NSDictionary* dictionary in array)
{
NSString *currentstring = [dictionary objectForKey:@"name"];
NSRange r = [currentstring rangeOfString:searchTerm options:NSCaseInsensitiveSearch];
if (r.location != NSNotFound) {
[[self searchResults] addObject:currentstring];
}
}
}
}
}
- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView {
// Return the number of sections.
if (tableView == [[self searchDisplayController] searchResultsTableView])
return [self.stoneSections count];
else
return [self.stoneSections count];
}
- (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section {
return [self.stoneSections objectAtIndex:section];
}
#pragma mark -
#pragma mark UITableViewDataSource Methods
- (NSInteger)tableView:(UITableView *)tableView
numberOfRowsInSection:(NSInteger)section
{
NSInteger rows;
if (tableView == [[self searchDisplayController] searchResultsTableView])
rows = [[self searchResults] count];
else
rows = [[self.contentsList objectAtIndex:section] count];
return rows;
}
- (UITableViewCell *)tableView:(UITableView *)tableView
cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
NSString *contentForThisRow = nil;
if (tableView == [[self searchDisplayController] searchResultsTableView])
contentForThisRow = self.searchResults [indexPath.row];
else
contentForThisRow = [[[[self contentsList] objectAtIndex:indexPath.section] objectAtIndex:indexPath.row] objectForKey:@"name"];
static NSString *CellIdentifier = @"stoneCell";
UITableViewCell *cell = nil;
if(mainTableView == self.mainTableView){
cell = [mainTableView dequeueReusableCellWithIdentifier:CellIdentifier forIndexPath:indexPath];
cell.textLabel.text = self.searchResults [indexPath.row];
} else {
cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];
cell.textLabel.text = [[[self.contentsList objectAtIndex:indexPath.section] objectAtIndex:indexPath.row] objectForKey:@"name"];
}
return cell;
}
答案 0 :(得分:2)
我遇到了同样的例外。我的问题的根本原因是我错误地引用了键/值对。在运行时,抛出异常“ - [__ NSCFConstantString objectAtIndex:]:发送到实例的无法识别的选择器”。这让我感到困惑的时间超过了我承认的时间。但是我找到了问题的解决方案,并希望它可以帮助别人。抛出异常的代码跟随更正后的代码。
错误的代码:
- (void)testMyUnitTest
{
WorldObject *worldObject;
NSMutableDictionary *worldCoordinatesAll = [[NSMutableDictionary alloc] init];
WorldCoordinate *localWCoordinate = [[WorldCoordinate alloc] init];
// Populate with a world coordinate object
[worldCoordinatesAll setObject:[localWCoordinate updateWithLatitude:X2LOC Longitude:Y2LOC Altitude:0] forKey:@"OBJECT 2"];
for (id objectID in worldCoordinatesAll) {
localWCoordinate = (WorldCoordinate *)objectID;
localWCoordinate.latitude = LATITUDE_1; // Exception being thrown on this line
}
}
更正的代码:
- (void)testMyUnitTest
{
WorldObject *worldObject;
NSMutableDictionary *worldCoordinatesAll = [[NSMutableDictionary alloc] init];
WorldCoordinate *localWCoordinate = [[WorldCoordinate alloc] init];
// Populate with a world coordinate object
[worldCoordinatesAll setObject:[localWCoordinate updateWithLatitude:X2LOC Longitude:Y2LOC Altitude:0] forKey:@"OBJECT 2"];
for (id key in worldCoordinatesAll) {
id value = [worldCoordinatesAll objectForKey:key];
localWCoordinate = (WorldCoordinate *)value;
localWCoordinate.latitude = LATITUDE_1;
}
}
我意识到,对于某些人来说,这似乎是一个完全明显的错误。但出于某种原因,我花了一个星期才看到它。所以我希望它可以帮助其他人节省时间。 : - )
答案 1 :(得分:0)
要找出哪个代码行负责异常断点的异常。
有关如何启用异常断点的信息,请参阅此问题"Run > Stop on Objective-C exception" in Xcode 4?。
可能发生的事情是你从一个没有方法objectAtIndex:
的集合中拉出一个对象。以下一行
[[[self searchResults]objectAtIndex:indexPath.section] objectAtIndex:indexPath.row] objectForKey:@"name"];`
可能是问题的根源。在这里,您尝试对objectAtIndex:
的结果使用[[self searchResults]objectAtIndex:indexPath.section]
但是从- (void)handleSearchForTerm:(NSString *)searchTerm
中可以看到的内容,[self searchResults]
只包含一个字符串数组。这意味着您将方法objectAtIndex:
应用于没有该方法的NSString
实例。