我正在使用此PHP代码获取访问者的IP地址:
<?php echo $_SERVER['REMOTE_ADDR']; ?>
但是,当他们使用代理时,我无法从访客获取真实的IP地址。在这种情况下,有没有办法获取访问者的IP地址?
答案 0 :(得分:152)
试试这个PHP代码。
<?PHP
function getUserIP()
{
// Get real visitor IP behind CloudFlare network
if (isset($_SERVER["HTTP_CF_CONNECTING_IP"])) {
$_SERVER['REMOTE_ADDR'] = $_SERVER["HTTP_CF_CONNECTING_IP"];
$_SERVER['HTTP_CLIENT_IP'] = $_SERVER["HTTP_CF_CONNECTING_IP"];
}
$client = @$_SERVER['HTTP_CLIENT_IP'];
$forward = @$_SERVER['HTTP_X_FORWARDED_FOR'];
$remote = $_SERVER['REMOTE_ADDR'];
if(filter_var($client, FILTER_VALIDATE_IP))
{
$ip = $client;
}
elseif(filter_var($forward, FILTER_VALIDATE_IP))
{
$ip = $forward;
}
else
{
$ip = $remote;
}
return $ip;
}
$user_ip = getUserIP();
echo $user_ip; // Output IP address [Ex: 177.87.193.134]
?>
答案 1 :(得分:37)
这是我见过的最常见的技术:
function getUserIP() {
if( array_key_exists('HTTP_X_FORWARDED_FOR', $_SERVER) && !empty($_SERVER['HTTP_X_FORWARDED_FOR']) ) {
if (strpos($_SERVER['HTTP_X_FORWARDED_FOR'], ',')>0) {
$addr = explode(",",$_SERVER['HTTP_X_FORWARDED_FOR']);
return trim($addr[0]);
} else {
return $_SERVER['HTTP_X_FORWARDED_FOR'];
}
}
else {
return $_SERVER['REMOTE_ADDR'];
}
}
请注意,它并不能保证您始终可以获得正确的用户IP,因为有很多方法可以隐藏它。
答案 2 :(得分:18)
这是我的方法:
function getRealUserIp(){
switch(true){
case (!empty($_SERVER['HTTP_X_REAL_IP'])) : return $_SERVER['HTTP_X_REAL_IP'];
case (!empty($_SERVER['HTTP_CLIENT_IP'])) : return $_SERVER['HTTP_CLIENT_IP'];
case (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) : return $_SERVER['HTTP_X_FORWARDED_FOR'];
default : return $_SERVER['REMOTE_ADDR'];
}
}
使用方法:
$ip = getRealUserIp();
答案 3 :(得分:7)
代理可能会发送HTTP_X_FORWARDED_FOR
标头,但即使这是可选的。
另请注意,访问者可以共享IP地址;大学网络,大型公司和第三世界/低预算的ISP倾向于与许多用户共享IP。
答案 4 :(得分:5)
应用此代码获取ipaddress:
if (getenv('HTTP_X_FORWARDED_FOR')) { $pipaddress = getenv('HTTP_X_FORWARDED_FOR');
$ipaddress = getenv('REMOTE_ADDR');
echo "Your Proxy IP address is : ".$pipaddress. "(via $ipaddress)" ; }
else { $ipaddress = getenv('REMOTE_ADDR'); echo "Your IP address is : $ipaddress"; }
------------------------------------------------------------------------
答案 5 :(得分:4)
这是我的功能。
好处:
/**
* Get real user ip
*
* Usage sample:
* GetRealUserIp();
* GetRealUserIp('ERROR',FILTER_FLAG_NO_RES_RANGE);
*
* @param string $default default return value if no valid ip found
* @param int $filter_options filter options. default is FILTER_FLAG_NO_PRIV_RANGE | FILTER_FLAG_NO_RES_RANGE
*
* @return string real user ip
*/
function GetRealUserIp($default = NULL, $filter_options = 12582912) {
$HTTP_X_FORWARDED_FOR = isset($_SERVER)? $_SERVER["HTTP_X_FORWARDED_FOR"]:getenv('HTTP_X_FORWARDED_FOR');
$HTTP_CLIENT_IP = isset($_SERVER)?$_SERVER["HTTP_CLIENT_IP"]:getenv('HTTP_CLIENT_IP');
$HTTP_CF_CONNECTING_IP = isset($_SERVER)?$_SERVER["HTTP_CF_CONNECTING_IP"]:getenv('HTTP_CF_CONNECTING_IP');
$REMOTE_ADDR = isset($_SERVER)?$_SERVER["REMOTE_ADDR"]:getenv('REMOTE_ADDR');
$all_ips = explode(",", "$HTTP_X_FORWARDED_FOR,$HTTP_CLIENT_IP,$HTTP_CF_CONNECTING_IP,$REMOTE_ADDR");
foreach ($all_ips as $ip) {
if ($ip = filter_var($ip, FILTER_VALIDATE_IP, $filter_options))
break;
}
return $ip?$ip:$default;
}
答案 6 :(得分:1)
如果代理是您信任的,您可以尝试:(假设代理IP为151.101.2.10
)
<?php
$trustProxyIPs = ['151.101.2.10'];
$clientIP = isset($_SERVER['REMOTE_ADDR']) ? $_SERVER['REMOTE_ADDR'] : NULL;
if (in_array($clientIP, $trustProxyIPs)) {
$headers = ['HTTP_CLIENT_IP', 'HTTP_X_FORWARDED_FOR'];
foreach ($headers as $key => $header) {
if (isset($_SERVER[$header]) && filter_var($_SERVER[$header], FILTER_VALIDATE_IP)) {
$clientIP = $_SERVER[$header];
break;
}
}
}
echo $clientIP;
这将阻止直接请求的客户端伪造前向标头,并通过受信任的代理获得真正的IP。
答案 7 :(得分:0)
是的,$_SERVER["HTTP_X_FORWARDED_FOR"]
是我在我的nginx服务器上的代理下看到我的IP的方式。
但您最好的选择是在代理下请求的页面上运行phpinfo()
,这样您就可以查看所有可用变量,看看哪个变量带有真正的IP。
答案 8 :(得分:-2)
适用于Windows和Linux!如果它是本地主机或在线,则无关紧要。
function getIP() {
$ip = $_SERVER['SERVER_ADDR'];
if (PHP_OS == 'WINNT'){
$ip = getHostByName(getHostName());
}
if (PHP_OS == 'Linux'){
$command="/sbin/ifconfig";
exec($command, $output);
// var_dump($output);
$pattern = '/inet addr:?([^ ]+)/';
$ip = array();
foreach ($output as $key => $subject) {
$result = preg_match_all($pattern, $subject, $subpattern);
if ($result == 1) {
if ($subpattern[1][0] != "127.0.0.1")
$ip = $subpattern[1][0];
}
//var_dump($subpattern);
}
}
return $ip;
}