Question

与split()中的awk相反的是什么？想象一下，我有数组包含字符/整数。

我尝试了什么：

color = "#FFFF00";
printf("color original: %s\n", color);
split(color, chars, "");
joined = "";
for (i=1; i <= length(chars); i++) {
    joined = joined + chars[i];
}
printf("color joined: %s\n", joined);

然而输出是：

color original: #FFFF00
color joined: 0

这当然是不正确的。

更新酷，最后得到以下代码（灵感来自答案中的连接函数）：

color = "#FFFF00";
printf("color original: %s\n", color);
split(color, chars, "");
joined = "";
for (i=1; i <= length(chars); i++) {
    joined = joined "" chars[i];
}
printf("color joined: %s\n", joined);

诀窍在于加入时不会使用+符号

Answer 1

这是一个不依赖于gawk或知道数组长度的解决方案，如果您愿意，可以在每个数组元素之间放置一个分隔符（在本例中为空格）字符串：

color = "#FFFF00"
printf "color original: %s\n", color
split(color, chars, "")
joined = sep = ""
for (i=1; i in chars; i++) {
    joined = joined sep chars[i]
    sep = " "     # populate sep here with whatever string you want between elements
}
printf "color joined: %s\n", joined

我还清理了错误使用printf和虚假的冒号。

Answer 2

使用GNU awk 4.1

#!/usr/bin/awk -f
@include "join"
BEGIN {
  split("#FFFF00", chars, "")
  print join(chars, 1, length(chars), SUBSEP)
}

awk save modifications in place

Answer 3

你想要的（在你的循环中）是string concatenation。

Answer 4

这是POSIX Awk的一种方式：

br = "red,orange,yellow,green,blue"
ch = split(br, de, ",")
print "original: " br
printf "joined: "
for (ec in de) printf ec == ch ? de[ec] "\n" : de[ec] "-"

输出：

original: red,orange,yellow,green,blue
joined: red-orange-yellow-green-blue

Answer 5

知道split()的反面是join()，仅谷歌搜索就会向我提供此页面，其中似乎包含解决方案：http://www.gnu.org/software/gawk/manual/html_node/Join-Function.html。它将数组的所有元素连接在一起，并返回相应的字符串。

['f','o','o'] => "foo"

玩得开心

分开对面的awk

5 个答案: