我是Java和Spring Framework的新手。我使用Spring STS 3.1.0.RELEASE和tomcat 7.我使用以下指示创建Spring MVC项目。文件> Spring模板项目> Spring MVC项目。 Follwoing是web.xml文件代码:
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
以下是servlet-contxt.xml文件:
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<resources mapping="/resources/**" location="/resources/" />
<!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
<beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<beans:property name="prefix" value="/WEB-INF/views/" />
<beans:property name="suffix" value=".jsp" />
</beans:bean>
<context:component-scan base-package="org.dave.foo" />
</beans:beans>
我想要更改控制器的默认名称和位置。为此,我创建了新的包org.dave.bar并将IndexController移动到此包。我还在servlet-context.xml文件中进行了如下所述的更改:
<context:component-scan base-package="org.dave.bar" />
但是在重新启动Web服务器并在此URL上运行代码(http:// localhost:8080 / bar /)后,我收到404错误。有人可以告诉我我做错了什么以及如何纠正它。
提前致谢
答案 0 :(得分:0)
首先,在web.xml中,您需要定义您希望Spring MVC Dispatcher Servlet处理的URL映射(通过控制器中的请求映射方法)。 根据我在您的问题中的理解,您将需要设置URL映射如下(在web.xml中)
<servlet>
<servlet-name>spring</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
其次, 在org.dave.foo下,您需要放置Spring MVC控制器(使用@Controller和URL映射方法注释的类)。 在您的控制器中,您将需要一个映射到spring dispatcher servlet URL映射的根的方法(在web.xml DispatcherServlet中定义): 因此,对于上面的定义,您需要一个这样的方法:
@RequestMapping(value = "/")
public ModelAndView index(HttpServletRequest request,
HttpServletResponse response) {
...
}
请注意,一般来说,最具体的请求映射“获胜”。这意味着如果除了“/”请求映射之外在控制器中有“/ abc”请求映射,那么请求localhost / myapp / abc将“赢”localhost / myapp /
您可以在此处查看更详细的示例: http://www.commonj.com/blogs/2012/11/30/spring-mvc-default-controller-name/
希望它有所帮助。