Question

我扩展了我的课程（从这个问题：How to get a whole row from database using SOCI?），有两个私人成员，还添加了getter和setter。但是在编译我的程序时，我又遇到了错误。

myClass.h

#include <soci.h>
#include <postgresql/soci-postgresql.h>
#include <string>

class MyClass
{
public:
    MyClass();
    MyClass(int i, std::string);

    void setI(int i);
    int getI() const;
    void setS(std::string s);
    std::string getS() const;

private:
    int i_;
    std::string s_;
};

namespace soci
{
    template <>
    struct type_conversion<MyClass>
    {
        typedef MyClass base_type;

        static void from_base(int i, std::string s, soci::indicator ind, MyClass & mi)
        {
            if (ind ==  soci::i_null)
            {
                throw soci_error("Null value not allowed for this type");
            }

            mi.setI(i);
        mi.setS(s);
        }

        static void to_base(const MyClass & mi, int & i,  std::string &s, soci::indicator & ind)
        {
            i = mi.getI();
        s = mi.getS();
            ind = soci::i_ok;
        }
    };
}

myClass.cpp

#include "myClass.h"

MyClass::MyClass()
{

}

MyClass::MyClass(int i, std:string s)
{
    this->i_ = i;
    this->s_ = s;
}

int MyClass::getI() const
{
    return this->i_;
}

void MyClass::setI(int i)
{
    this->i_ = i;
}

std::string MyClass::getS() const
{
    return this->s_;
}

void MyClass::setS(std::string s)
{
    this->s_ = s;
}

myClassTest.cpp

#include <iostream>
#include "myClass.h"

int main(int argc, char **argv)
{

    soci::session sql;
    sql.open(soci::postgresql, "dbname=mydb user=postgres password=postgrespass");
    MyClass i;
    sql << "SELECT id, name FROM person;", soci::into(i);
    std::cout << i.getI() << " " << i.getS();
    sql.close();

    return 0;
}

我这样编译：

g ++ myClassTest.cpp myClass.h myClass.cpp -o App -lsoci_core -lsoci_postgresql -ldl -lpq -I / usr / local / include / soci -I / usr / include / postgresql

我得到的错误是：

In file included from /usr/local/include/soci/into-type.h:13:0,
                 from /usr/local/include/soci/blob-exchange.h:12,
                 from /usr/local/include/soci/soci.h:18,
                 from myClass.h:1,
                 from myClassTest.cpp:2:
/usr/local/include/soci/exchange-traits.h: In instantiation of ‘soci::details::exchange_traits<MyClass>’:
/usr/local/include/soci/into.h:29:60:   instantiated from ‘soci::details::into_type_ptr soci::into(T&) [with T = MyClass, soci::details::into_type_ptr = soci::details::type_ptr<soci::details::into_type_base>]’
myClassTest.cpp:27:65:   instantiated from here
/usr/local/include/soci/exchange-traits.h:35:5: error: incomplete type ‘soci::details::exchange_traits<MyClass>’ used in nested name specifier
In file included from /usr/local/include/soci/into.h:13:0,
                 from /usr/local/include/soci/soci.h:22,
                 from myClass.h:1,
                 from myClassTest.cpp:2:
/usr/local/include/soci/type-conversion.h: In member function ‘void soci::details::conversion_into_type<T>::convert_from_base() [with T = MyClass]’:
myClassTest.cpp:34:1:   instantiated from here
/usr/local/include/soci/type-conversion.h:59:9: error: no matching function for call to ‘soci::type_conversion<MyClass>::from_base(soci::type_conversion<MyClass>::base_type&, soci::indicator&, MyClass&)’
/usr/local/include/soci/type-conversion.h:59:9: note: candidate is:
myClass.h:28:21: note: static void soci::type_conversion<MyClass>::from_base(int, std::string, soci::indicator, MyClass&)
myClass.h:28:21: note:   candidate expects 4 arguments, 3 provided
myClass.cpp:8:28: error: found ‘:’ in nested-name-specifier, expected ‘::’

Answer 1

你有没有尝试过SOCI 3.2？我用这个版本做了类似的工作，效果很好：

vector<Entry> Entry::findByName(string name) {

    Entry entry;

    vector<Entry> entries;

    //Starting a connection to database
    session sql(firebird, "service=/srv/firebird/registry.gdb user=SYSDBA password=password");

    //Querying data using a prepared statement and place data into a Entry object
    statement st = (sql.prepare <<
                "select NAME, ADDRESS, PHONE from ENTRY WHERE NAME like '%' || :NAME || '%'",
                into(entry), use(name));
    st.execute();

    //Checking if we can fetch a row from resultset
    while (st.fetch())
    {
        //Pushing the object with mapped data into the entries vector
        entries.push_back(entry);
    }

    return entries;
}

您可以将其更改为：

Entry Entry::findByName(string name) {

    Entry entry;

    //Starting a connection to database
    session sql(firebird, "service=/srv/firebird/registry.gdb user=SYSDBA password=password");

    //Querying data using a prepared statement and place data into a Entry object
    statement st = (sql.prepare <<
                "select NAME, ADDRESS, PHONE from ENTRY WHERE NAME like '%' || :NAME || '%'",
                into(entry), use(name));
    st.execute();

    //Checking if we can fetch a row from resultset
    if (st.fetch())
    {
        return entry;
    }

    return NULL;
}

注意：它们都是我的模型类的静态类，它实现了ActiveRecord的自定义版本。

如何使用SOCI从用户定义的对象类型中获取整行？

1 个答案: