Question

大家好，我当前的Android应用程序上有一个活动，里面有一个webview。我想知道如何从我的Android应用程序上的变量中获取并存储来自该网站上的php的变量（是的，我控制网站，并具有完整的编辑功能）。

Answer 1

我会解释一般需要做的事情。首先，在你的Android应用程序方面，应该有这样的代码。

1）在你的机器人方面

String url = "www.yoururl.com/yourphpfile.php";
List<NameValuePair> parmeters = new ArrayList<NameValuePair>();
            parameters.add(new BasicNameValuePair("category",category));
            parameters.add(new BasicNameValuePair("subcategory",subcategory));// These are the namevalue pairs which you may want to send to your php file. Below is the method post used to send these parameters

  DefaultHttpClient httpClient = new DefaultHttpClient();

  HttpPost httpPost = new HttpPost(url); // You can use get method too here if you use get at the php scripting side to receive any values.

  httpPost.setEntity(new UrlEncodedFormEntity(parameters));

  HttpResponse httpResponse = httpClient.execute(httpPost);

  HttpEntity httpEntity = httpResponse.getEntity();

  is = httpEntity.getContent();

   BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is, "iso-8859-1"), 8); // From here you can extract the data that you get from your php file..

        StringBuilder builder = new StringBuilder();

        String line = null;

        while ((line = reader.readLine()) != null) {
            builder.append(line + "\n");
        }

        is.close();
        json = sb.toString(); // Here you are converting again the string into json object. So that you can get values with the help of keys that you send from the php side.

        String message = json.getString("message");
         int success = json.getInt("success"); // In this way you again convert json object into your original data.

2）在你的php端

$response = array();

// check for post fields
if (isset($_POST['category']) && isset($_POST['subcategory'])) {

    $category = $_POST['category'];
    $subcategory = $_POST['subcategory'];


    // include db connect class
    require_once __DIR__ . '/db_connect.php';

    // connecting to db
    $db = new DB_CONNECT();

    // mysql inserting a new row
    $result = mysql_query("INSERT INTO categorytable(category, subcategory) VALUES('$category', '$subcategory')");

    // check if row inserted or not
    if ($result) {
        // successfully inserted into database
        $response["success"] = 1;
        $response["message"] = "Data inserted into database.";

        // echoing JSON response
        echo json_encode($response);// Here you are echoing json response. So in the inputstream you would get the json data. You need to extract it over there and can display according to your requirement.
}

正如你所说，你对php非常熟练，你可能已经发现php中的上述内容尽可能简单并且不安全。所以，你可以按照一些pdo或其他一些安全的方式在php端编写代码。确保你在asynctask的android端包含代码，以便在你需要的任何地方运行在单独的线程中。希望这会有所帮助。

Answer 2

您的Android应用程序需要向您的PHP应用程序发出请求，在您设置PHP脚本的URL处返回您需要的数据。

您可以直接返回HTML，或者如果您只想返回数据并使用Android应用，JSON是一种出色的数据传输格式。 XML也很受欢迎，但是JSON更加精简并且现在得到了很好的支持。

如何从php发送变量到Android应用程序？

2 个答案: