Question

使用SUM遇到此子查询的问题。该查询将总计来自特定日期范围的若干记录的利润列。我将此总利润按记录附加的帐号进行分组。使用一个帐号，它可以正常工作：

select
    [ACCOUNT ID],
    (
     select SUM(PROFIT)
     from [Transaction Table]
     where [ACCOUNT ID] in ('1001')
     and [ACTIVITY DATE] in ('5/31/2012')
    ) as 'May Profit'

from
    [Transaction Table]

where
    [ACCOUNT ID] in ('1001')

group by
    [ACCOUNT ID]

给出正确的结果：

    | ACCOUNT ID | May Profit |
    ---------------------------
    |    1001    |   $61.97   |

麻烦来自多个帐号：

select
    [ACCOUNT ID],
    (
     select SUM(PROFIT)
     from [Transaction Table]
     where [ACCOUNT ID] in ('1001','2001')
     and [ACTIVITY DATE] in ('5/31/2012')
    ) as 'May Profit'

from
    [Transaction Table]

where
    [ACCOUNT ID] in ('1001','2001')

group by
    [ACCOUNT ID]

结果不正确：

    | ACCOUNT ID | May Profit |
    ---------------------------
    |    1001    |  $127.34   |
    |    2001    |  $127.34   |

每个记录的两个帐户的“5月利润”总计。我需要每个帐号的个人利润总额。

有什么想法？提前谢谢！

Answer 1

您不需要使用子查询

 select
     [ACCOUNT ID],
     SUM(PROFIT)
 from [Transaction Table]
 where [ACCOUNT ID] in ('1001','2001') and [ACTIVITY DATE] in ('5/31/2012')
 group by [ACCOUNT ID]

您的查询只计算了两个帐户的总和，并在每行显示

的更新

实际上，对于多个总和，我会做这样的事情

select [ACCOUNT ID], SUM(case when [ACTIVITY DATE] in ('5/31/2012') then PROFIT else 0 end) as 'May Profit', SUM(case when [ACTIVITY DATE] in ('4/31/2012') then PROFIT else 0 end) as 'April Profit' from [Transaction Table] where [ACCOUNT ID] in ('1001','2001') and group by [ACCOUNT ID]

Answer 2

您不需要使用SubQuery，但是有两种方法可以执行：

第一种方式，使用您的查询（不推荐） - 注意帐户ID = T.Account Id：

select
    [ACCOUNT ID],
    (
     select SUM(PROFIT)
     from [Transaction Table]
     where [ACCOUNT ID] = T.[ACCOUNT ID]
     and [ACTIVITY DATE] in ('5/31/2012')
    ) as 'May Profit'
from
    [Transaction Table] T
where
    [ACCOUNT ID] in ('1001','2001')
group by
    [ACCOUNT ID]

更好的方法：

select
     [ACCOUNT ID],
     SUM(PROFIT)
from [Transaction Table]
where [ACCOUNT ID] in ('1001','2001') and [ACTIVITY DATE] in ('5/31/2012')
group by [ACCOUNT ID]

MS SQL Studio 2008 - 使用SUM选择SubQuery

2 个答案: