我们在IIS7.5后面使用Tomcat 6.29,使用spring,hibernate和struts2框架。我们现在开始注意到服务器会话正在混乱,特别是在Ajax请求中。
有关问题的更多详情
任何指向问题根源的指针都会有所帮助,代码运行正常,用户数量较少,并且没有报告此类实例。
修改
的web.xml
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>bm</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:spring/*Context.xml</param-value>
</context-param>
<filter>
<filter-name>encodingFilter</filter-name>
<filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>UTF-8</param-value>
</init-param>
<init-param>
<param-name>forceEncoding</param-name>
<param-value>true</param-value>
</init-param>
</filter>
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>encodingFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.apache.struts2.tiles.StrutsTilesListener</listener-class>
</listener>
struts.xml中
<result-types>
<result-type name="jasper" class="org.apache.struts2.views.jasperreports.JasperReportsResult"/>
<result-type name="tiles" class="org.apache.struts2.views.tiles.TilesResult" />
</result-types>
<interceptors>
<interceptor name="sessionLoggin" class="com.inrev.bm.interceptor.IRLoggingInterceptor" />
<interceptor name="appAccess" class="appAccessInterceptor" />
<interceptor-stack name="newStack">
<interceptor-ref name="exception"/>
<interceptor-ref name="alias"/>
<interceptor-ref name="servletConfig"/>
<interceptor-ref name="i18n"/>
<interceptor-ref name="prepare"/>
<interceptor-ref name="chain"/>
<interceptor-ref name="debugging"/>
<interceptor-ref name="scopedModelDriven"/>
<interceptor-ref name="modelDriven"/>
<interceptor-ref name="fileUpload"/>
<interceptor-ref name="checkbox"/>
<interceptor-ref name="multiselect"/>
<interceptor-ref name="staticParams"/>
<interceptor-ref name="params">
<param name="excludeParams"> dojo\..*,^struts\..*</param>
</interceptor-ref>
<interceptor-ref name="actionMappingParams"/>
<interceptor-ref name="sessionLoggin"/>
<interceptor-ref name="appAccess"/>
</interceptor-stack>
</interceptors>
<default-interceptor-ref name="newStack"/>
其他信息
1)用户通过提交表单登录,登录时我们执行以下操作,
public class xxxAction extends ActionSupport implements SessionAware
{
public String execute()
{
session.clear();
if (session instanceof org.apache.struts2.dispatcher.SessionMap)
{
try
{
((org.apache.struts2.dispatcher.SessionMap) session).invalidate();
}
catch (IllegalStateException e) {
log.error("Session Invalidate Failed ", e);
}
//Authorization code happens here
session.put("orgs", orgs);
session.put("currentOrg", org);
session.put("permission", adminDAO.getRolePermission(orgs.get(0).getRoleId()));
session.put("simplyApp", simplyApp);
session.put("user", user);
return "login"
}
}
2)正在使用的Os是windows 2008 RC2
EDIT2 收件人代码
INTERCEPTOR 1
public String intercept(ActionInvocation invocation) throws Exception
{
String result = null;
String className = invocation.getAction().getClass().getName();
Map session = invocation.getInvocationContext().getSession();
IRUser user = (IRUser) session.get("user");
IROrgname org = (IROrgname)session.get("currentOrg");
IRAppDetails simplyApp = (IRAppDetails)session.get("simplyApp");
String sessionId = (String)session.get("sessionId");
boolean switchUser =session.get("switchUser")!=null ? (Boolean)session.get("switchUser") : false;
if(className.indexOf("IRLoginAction")!=-1 || className.indexOf("IRContactUsAction")!=-1
|| className.indexOf("IRIPNAction")!=-1 || className.indexOf("IRPaymentAction")!=-1
|| className.indexOf("IRServiceAction")!=-1 || className.indexOf("IRAppBossAction") !=-1)
{
result= invocation.invoke();
session.put("PREV_CLASS_NAME", className);
}
else if(!(className.indexOf("IRLoginAction")!=-1) && (user !=null && org!=null))
{
if(!IRSessionManager.getInstance().compareSession(user.getUserId(), sessionId) && !switchUser)
{
session.clear();
if (session instanceof org.apache.struts2.dispatcher.SessionMap)
{
try
{
((org.apache.struts2.dispatcher.SessionMap) session).invalidate();
}
catch (IllegalStateException e)
{
log.error("Session Invalidate Failed ", e);
}
}
result = "sessionDuplicated";
}
else
{
result= invocation.invoke();
session.put("PREV_CLASS_NAME", className);
}
}
else if(className.indexOf("widgets") !=-1)
{
result= invocation.invoke();
}
else if(className.indexOf("ActionSupport") !=-1)
{
result= invocation.invoke();
}
else if (!(className.indexOf("IRLoginAction")!=-1) && (user ==null || org==null || simplyApp==null))
{
result = "sessionExpired";
}
return result;
}
INTERCEPTOR 2
public String intercept(ActionInvocation invocation) throws Exception
{
String result = null;
HttpServletRequest request = ServletActionContext.getRequest();
String className = invocation.getAction().getClass().getName();
try
{
Map session = invocation.getInvocationContext().getSession();
IRUser user = (IRUser) session.get("user");
IROrgname org = (IROrgname)session.get("currentOrg");
IRAppDetails application = (IRAppDetails)session.get("simplyApp");
if(( user!= null && user.getAppType()!=0) && !(className.indexOf("IRLoginAction")!=-1))
{
if(hasAccess(user.getAppType(), className))
{
result= invocation.invoke();
}
else
{
result = "checkURL";
}
}
else
{
result= invocation.invoke();
}
}
catch (Exception e)
{
e.printStackTrace();
}
return result;
}
答案 0 :(得分:8)
两天前我在遗留项目(而不是我的)上调试了类似的内容。
原来这是自定义拦截器的错。
检查我可以在你的堆栈中看到的自定义拦截器,
<interceptor-ref name="sessionLoggin"/>
<interceptor-ref name="appAccess"/>
并确保其代码为Thread Safe(避免拦截器上的字段而不是同步所有内容,仅使用局部变量)。
例如,考虑代码:
public abstract class ThreadUnsafeInterceptor extends AbstractInterceptor {
private Map<String, Object> session; // <!-- Thread Unsafe
public final String intercept(ActionInvocation invocation) throws Exception {
session = invocation.getInvocationContext().getSession();
/* Do stuff */
System.out.println(session.get("myObject"));
return invocation.invoke();
}
}
这样,当User1进入方法时,它会使用其会话设置共享的session
对象;
如果User2在User1尚未完成时输入方法,则User2将立即用其会话覆盖session
对象,而User1将引用User2会话而不是自己的会话。
为了使其线程安全,它应该如下:
public abstract class ThreadSafeInterceptor extends AbstractInterceptor {
public final String intercept(ActionInvocation invocation) throws Exception {
Map<String, Object> session; // <!-- Thread Safe
session = invocation.getInvocationContext().getSession();
/* Do stuff */
System.out.println(session.get("myObject"));
return invocation.invoke();
}
}
编辑:
你的拦截器存在一些问题:
1)不得以这种方式访问请求(如here所述):
HttpServletRequest request = ServletActionContext.getRequest();
从Struts2拦截器中访问请求的正确方法是:
// Constants are from StrutsStatics interface
HttpServletRequest request = (HttpServletRequest) context.get(HTTP_REQUEST);
2)如果您不想立即返回invocation.invoke();
,请注意将其分配给result
字符串将触发“流”,以及{{1}之后的行将在Action执行后执行as described here:
invoke()