我从服务器加载shapefile,而不是在OpenLayers中绘制它。 shapefile包含超过400,000个具有不同不透明度的多边形。我需要设置不透明度和填充颜色,但openlayers似乎忽略它,而只是绘制橙色方块。我更改属性之前是console.log(),然后它显示我分配的内容。谁能告诉我它为什么这样做?
var green = {
fill: true,
fillColor: "#006633",
fillOpacity: 1
};
var features = wkt.read(element);
if (featureNumber == 0){
document.getElementById('result').innerHTML=element;
}
features = element.toString();
var bounds;
var b = features.indexOf('MULTIPOLYGON', 0);
var c = features.indexOf('MULTIPOLYGON', 40);
if (c == -1) {
c = element.indexOf(':',b+1);
}
leftovers = features.substring(c,100000000000000000);
features = features.substring(b,c);
features = wkt.read(features);
if(features) {
if(features.constructor != Array) {
features = [features];
}
for(var i=0; i<features.length; ++i) {
if (!bounds) {
bounds = features[i].geometry.getBounds();
} else {
bounds.extend(features[i].geometry.getBounds());
}
}
pointLayer.addFeatures(features);
console.log(pointLayer.features[featureNumber].attributes );
pointLayer.features[featureNumber].attributes = green;
console.log(pointLayer.features[featureNumber].attributes );
featureNumber++
map.zoomToExtent(bounds);
var plural = (features.length > 1) ? 's' : '';
console.log('Feature' + plural + ' added');
console.log('feature number: '+featureNumber)
if (leftovers.indexOf('MULTIPOLYGON',0) != -1) {
parseWKT(leftovers,shapefile);
}
} else {
final(leftovers, shapefile);
}
}
答案 0 :(得分:4)
该样式属于.style
属性,而不属于该功能的.attributes
。如果已经在地图上,您还需要致电redraw()
。
pointLayer.features[featureNumber].style = green;
pointLayer.redraw();
如果您想从默认样式开始,只需更改一些内容,您可以执行以下操作:
var green = OpenLayers.Util.applyDefaults(green, OpenLayers.Feature.Vector.style['default']);
green.fill = true;
green.fillColor = "#006633";
green.fillOpacity = 1;
pointLayer.features[featureNumber].style = green;
pointLayer.redraw();