Question

您好我有一些JSON格式的数据如下：

`contentJson=`[{"key1":"Value1","key2":"Value2","key3":"Value3","key4":"Value4","key5":"Value5","key6":"Value6","key7":"Value7", "key8":"Value8"},{"key1":"Value1","key2":"Value2","key3":"Value3","key4":"Value4","key5":"Value5","key6":"Value6","key7":"Value7", "key8":"Value8"}]

如何将所有数据保存到Sqlite数据库中的一个字段？

我的代码是

 NSString *statement = [[NSString alloc]initWithFormat:@"INSERT INTO mydatabase(contentJson,ID) VALUES(\"%@\",%d)",contentJson,ID];

但它没有插入任何东西。如果我手动插入通过SQlitemanager然后我得到错误，如错误在“Key1 ......

如果有人能通过向我展示如何做到这一点，我将非常感激。

Answer 1

您的interporlated字符串将如下所示：

INSERT INTO mydatabase(contentJson,ID) VALUES(
"[{"key1":"Value1","key2":"Value2","key3":"Value3","key4":"Value4",
"key5":"Value5","key6":"Value6","key7":"Value7", "key8":"Value8"},
{"key1":"Value1","key2":"Value2","key3":"Value3","key4":"Value4",
"key5":"Value5","key6":"Value6","key7":"Value7", "key8":"Value8"}]",
ID);

你需要exacpe“在字符串中，因为它让你的rdbms感到困惑。

也许试试

NSString *statement = [[NSString alloc]initWithFormat:@"INSERT INTO mydatabase(contentJson,ID) VALUES('%@',%d)",contentJson,ID];

然而，真正的解决方案是在应用程序中使用Prepared Statements而不是SQL String。使用预准备语句时，这不是问题。

如何在iOS中将JSON字符串保存到一个Sqlite字段？

1 个答案: