好的家伙关于这个话题的最后一个问题(I HOPE)。
我需要做的是汇总来自两个不同表格的字段,将它们加在一起,并检查此总额是否大于客户信用额度。
我已将问题分解为较小的任务,以便我可以尝试提出整体解决方案。 (这些较小的代码对我来说正常工作,但是当在第三段代码中合并时,它们总和不正确)。首先,我计算了第一个求和字段,如下所示:
--summmed open invoices
SELECT company, sum(unit_price * invoice_qty) as open_invoices
FROM
(SELECT arc.company, ard.unit_price, ard.invoice_qty, arc.credit_limit
FROM iqms.arprepost_detail ard, iqms.arprepost arp, iqms.arcusto arc
WHERE ard.arprepost_id = arp.ID
AND arp.arcusto_id = arc.ID)
GROUP BY company
ORDER BY company;
这个数字在总结时正确显示,我已手动检查。接下来我总结了我需要的另一个字段,如下所示:
--summed open orders
SELECT company, (sum (unit_price * total_qty_ord)) as total_open_orders
FROM
(SELECT arc.company, od.unit_price, od.total_qty_ord, arc.credit_limit
FROM iqms.arcusto arc, iqms.orders o, iqms.ord_detail od
WHERE od.orders_id = o.ID
AND o.arcusto_id = arc.ID
AND (od.cumm_shipped < od.total_qty_ord OR od.cumm_shipped IS NULL))
GROUP BY company
ORDER BY company;
这些数字再次在人工检查中正确显示。
我现在需要的是将这两个计算加在一起并检查该数字是否大于该客户的'credit_limit'字段。我已经为此编写了代码,但是这些数字已经超出了它们的应用范围(下面给出了这段代码)。
--summmed open invoices + open orders
SELECT company, credit_limit,
round(sum(i_up * invoice_qty)) AS total_invoices,
round(sum (o_up * total_qty_ord)) AS total_orders,
round(sum(i_up * invoice_qty) + sum (o_up * total_qty_ord)) as overall_total
FROM
(SELECT arc.company, arc.credit_limit, ard.unit_price as i_up, ard.invoice_qty, od.unit_price as o_up, od.total_qty_ord
FROM iqms.arprepost_detail ard, iqms.arprepost arp, iqms.arcusto arc, iqms.orders o, iqms.ord_detail od
WHERE
ard.arprepost_id = arp.ID
AND arp.arcusto_id = arc.ID
AND od.orders_id = o.ID
AND o.arcusto_id = arc.ID
AND (od.cumm_shipped < od.total_qty_ord OR od.cumm_shipped IS NULL)
)
GROUP BY company, credit_limit
HAVING ((sum(i_up * invoice_qty)) + (sum (o_up * total_qty_ord)) > credit_limit)
ORDER BY company;
我不确定我哪里出错了。也许它是一个简单的修复或者我的逻辑可能有问题。非常感谢任何见解。非常感谢您的继续支持。
答案 0 :(得分:1)
在这种情况下,由于两个查询不同,我建议您使用UNION ALL:
SELECT company, SUM(open_invoices) total /*should rename the column in query 1*/
FROM ([QUERY1]
UNION ALL
[QUERY2])
GROUP by company
答案 1 :(得分:1)
我的第一个观察是你应该使用explicit joins instead of implicit joins,暗示连接已经过时了20年
您不能像以前那样组合2个查询,因为它们来自不同的表,使用隐式连接这样做会导致交叉连接。我认为最简单的方法是为每个查询使用2个左连接:
SELECT arc.Company,
arc.Credit_Lime,
COALESCE(Open_Orders, 0) AS Open_Orders,
COALESCE(Open_Invoices, 0) AS Open_Invoices
COALESCE(Open_Orders, 0) + COALESCE(Open_Invoices, 0) AS Total_Amount
FROM iqms.arcusto arc
LEFT JOIN
( SELECT o.arcusto_ID
SUM(od.unit_price * od.total_qty_ord) AS Open_Orders
FROM iqms.orders o
INNER JOIN iqms.ord_detail od
ON od.orders_ID = o.ID
WHERE od.Cumm_Shipped < od.Total_qty_Ord
OR od.Cumm_Shipped IS NULL
GROUP BY o.arcusto_ID
) openOrders
ON openOrders.Arcusto_ID = arc.ID
LEFT JOIN
( SELECT arp.arcusto_id,
SUM(Unit_Price * Invoice_Quantity) AS Open_Invoices
FROM iqms.arprepost_detail ard
INNER JOIN iqms.arprepost arp
ON ard.arprepost_id = arp.ID
GROUP BY arp.arcusto_id
) OpenInvoices
ON OpenInvoices.Arcusto_ID = arc.ID
WHERE COALESCE(Open_Orders, 0) + COALESCE(Open_Invoices, 0) > arc.Credit_Limit;
您还可以按如下方式联合两个查询:
SELECT arc.Company,
arc.Credit_Lime,
SUM(COALESCE(Open_Orders, 0)) AS Open_Orders
FROM iqms.arcusto arc
LEFT JOIN
( SELECT o.arcusto_ID
SUM(od.unit_price * od.total_qty_ord) AS Open_Orders
FROM iqms.orders o
INNER JOIN iqms.ord_detail od
ON od.orders_ID = o.ID
WHERE od.Cumm_Shipped < od.Total_qty_Ord
OR od.Cumm_Shipped IS NULL
GROUP BY o.arcusto_ID
UNION ALL
SELECT arp.arcusto_id,
SUM(Unit_Price * Invoice_Quantity) AS Open_Invoices
FROM iqms.arprepost_detail ard
INNER JOIN iqms.arprepost arp
ON ard.arprepost_id = arp.ID
GROUP BY arp.arcusto_id
) OpenInvoices
ON OpenInvoices.Arcusto_ID = arc.ID
GROUP BY arc.Company, arc.Credit_Limit
HAVING SUM(Open_Orders) > arc.Credit_Limit;
但我认为第一种方法可以更灵活地确定Open_Orders或Open_Invoices是否超出信用额度