Question

results = open(filename, 'r')


   line = results.readline()
   while line != '':
    # results for a single draw
    star = line[line.rfind('\t') :]
    stars.append(star)
    line =results.readline()
'''

while line != '':


   main = [line[:line.rfind('\t')]]
   mains.append(main)
   line =results.readline()
return (mains)

我正在使用上面的脚本以1,2,3,4,5标签9,10新行6,7,8,9,10标签11,12的格式从文本文件中读取并试图获取回[[1,2,3,4,5]，[6,7,8,9,10]]上面的剧本给了我[['1,2,3,4,5']，['6， 7,8,9,10']] - 括号阻止我使用数据。请原谅我再次愚蠢，但如何从文本文件中获取列表格式？我确实尝试阅读其他帖子，但未能应用这些建议 - 对此太新了非常感谢您的帮助

Answer 1

试试这个：

results = open(filename, 'r')
line = results.readline()
mains = []
while line != '':
  stars = line[:line.rfind('\t')].split(',')
  nums = [int(n) for n in stars]
  mains.append(nums)
  line =results.readline()

Answer 2

尝试：

# say your data is in file named 'testfile'
$ cat testfile 
1,2,3,4,5   9,10
6,7,8,9,10  11,12

# the actual code
datafile = [line.strip().split('\t')[0].split(',') for line in open('testfile')]   
result = []
for l in datafile:
    result.append([int(string) for string in l])
# test the results
print(result)
[[1, 2, 3, 4, 5], [6, 7, 8, 9, 10]]

修改：要获取每行的两个部分，请尝试：

datafile = [line.strip() for line in open('testfile')] datafile = [line.split('\t') for line in datafile if line] datalist = list(zip(*datafile)) result = [] for index in datalist: for i in index: result.append([int(string) for string in i.split(',')]) # you can access the result list by indexing: print(result[:2], result[2:]) # or assign to new lists: firstlist, secondlist = result[:2], result[2:] print(firstlist, secondlist)

从文本文件返回列表列表

2 个答案: