Question

我尝试了两种方法，但它们都没有工作.. 第一种方式::

string filepath = Server.MapPath[this is not a link]("XMLFile2.xml");
XmlDocument xdoc = new XmlDocument();
                xdoc.Load(filepath);

                XmlNode root = xdoc.DocumentElement;
                XmlNode idNode = root.SelectSingleNode("/students/student/id");
if (idNode.Value == 9.ToString())
                    {
                        var nodeOfStudent = xdoc.SelectNodes("/students/student[@id='9']");
                        nodeOfStudent[1].InnerXml = TextBox_firstname.Text;
                        nodeOfStudent[2].InnerXml = TextBox_lastname.Text;
                        nodeOfStudent[3].InnerXml = TextBox_dob.Text;
                        nodeOfStudent[4].InnerXml = TextBox_class.Text;
                        nodeOfStudent[5].InnerXml = TextBox_section.Text;
                        nodeOfStudent[6].InnerXml = TextBox_telephone.Text;

                    }

第二种方式::

string filepath = Server.MapPath("XMLFile2.xml");
                XmlDocument xdoc = new XmlDocument();
                xdoc.Load(filepath);

                XmlNode root = xdoc.DocumentElement;
                XmlNode idNode = root.SelectSingleNode("/students/student/id");

xdoc.SelectSingleNode("/students/student[@id='10']/firstname").InnerXml = TextBox_firstname.Text;
                        xdoc.DocumentElement.AppendChild(firstname);
                        xdoc.SelectSingleNode("/students/student[@id='10']/lastname").InnerXml = TextBox_firstname.Text;
                        xdoc.SelectSingleNode("/students/student[@id='10']/dob").InnerXml = TextBox_firstname.Text;
                        xdoc.SelectSingleNode("/students/student[@id='10']/class").InnerXml = TextBox_firstname.Text;
                        xdoc.SelectSingleNode("/students/student[@id='10']/section").InnerXml = TextBox_firstname.Text;
                        xdoc.SelectSingleNode("/students/student[@id='10']/telephone").InnerXml = TextBox_firstname.Text;

                        xdoc.Save(filepath);

有什么不对，我看不到...... 我的xml文件看起来像这样::

<students>
  <student>
    <id>1</id>
    <first_name>ahmad</first_name>
    <last_name>hani</last_name>
    <DOB>12/5/1998</DOB>
    <class>sixth</class>
    <section>A</section>
    <telephone>06555632</telephone>
  </student>  
</students>

我使用查询字符串从位于另一个页面的gridView加载“QueryString”....

提前感谢。

Answer 1

您可以使用Linq to xml轻松完成此操作：

int id = 9;
XDocument xdoc = XDocument.Load(filepath);
var student = xdoc.Descendants("student")
                  .Where(s => (int)s.Element("id") == id)
                  .SingleOrDefault();

if (student != null)
{
    student.Element("first_name").Value = TextBox_firstname.Text;
    student.Element("last_name").Value = TextBox_lastname.Text;
    student.Element("DOB").Value = TextBox_dob.Text;
    student.Element("class").Value = TextBox_class.Text;
    // etc
}

xdoc.Save(filepath);

基于xmlElement编辑xml节点

1 个答案: